Pelat HalfSlab T - 40 Berikut data perencanaan pelat halfslab T-40 : - Tebal Pelat Precast - Tebal Pelat $nsitu - %utu Bet!n
= = =
Ditanyakan : 1) !ntr!l Pen"amatan umur 2) !ntr!l Penumpukan umu #) !ntr!l Pemasan"an &'re
20 cm 20 cm #0 %pa
- %utu Baa Tulan"an Def!rm
= =
#00 "6cm2 #*0 %pa
4) !ntr!l Pen"ec!ran $nsitu +) !ntr!l ,endutan etelah
- Diameter Tulan"an Pelat - elimut Bet!n - 3arak Tulan"an Pelat - Titik n"kat
= = = = =
#*00 "6cm2 1* mm cm 100 mm 4 titik
.) /itun" Diameter Tulan"a () ambar Detai !mp!nen Tulan"annya
Berikut adalah Desi"n Penulan"annya : 02+ b
0+ b
02+ b
m
02+ a
( 1 5 2
0+ a
= a
02+ a
b
=
#5*
m
# hari r # hari ti!n) umur ( hari umur ( hari Pen"ec!ran umur ( hari n"kat y" diperlukan Pelat Beserta
Kontrol Plat Precast Data Material :
Mutu Beton Precast : fc7 fci7 fci7 fci7 Mutu Tulangan fy Diameter Tulangan D
= = = =
#0 2.54 1*5+ 1#5
%pa %pa %pa %pa
&2 hari) &14 hari) &( hari) &# hari)
=
#*0
%pa
=
1*
mm *.0
Data Perencanaan :
Tebal Precast Tebal $n itu
= =
20 cm 20 cm
Perhitungan Beban
Beban Mati : - Berat Precast
=
052
8
2400
=
40
k"6m2
- Berat $nsitu
=
052
8
2400
=
40
k"6m2
=
*.0
k"6m2
Beban Hidup : - Pekera
=
200
k"
%aka : 9u saat pen"an"katan 9u saat pemasan"an Pu saat pemasan"an 9u saat pen"ec!ran
= = = =
152 D &Precast aa) 152 D &Precast aa) 15. , 152 D
$nsitu &arna diberi
= = = =
+(. +(. #20 10+.
k"6m2 k" k"6m2
T!pin") Perhitungan Momen Tahanan
Pelat Type P4b
02+ b
0+ b
02+ b %aka %!men Tahanan :
m
02+ a
( 1 5 2
0+ a
=
rah ;
b
(arah pendek)
2
<8
=
1
=
#5* m
rah
b
(arah pendek)
2
= =
b
x
2 1#000 cm#
=
b
x
.
a
02+ a
=
1 .
=
x
(2##5###### cm#
b 2
x
1*+
h
cm
2
105+
h
cm
2
A. Kontrol Saat Pengangatan! "mur # Hari Data %aterial : fci7
=
%aka : fr
=
1#5 %pa
05(
= =
05( 8 25.00#4+.* %pa
=
2.500#4+.* k"6cm2
Pen"an"katan den"an :
4
√
8
#5(14#+124
Titik an"kat
Beban adalah Berat endiri Bal!k Precast :
+(.
<,62
k"6m2 <,62
02+ ,
0+ ,
%aka : %8
= 05010( 05010( 11#51*
%8
= = = = = =
05010( 05010(
02+ ,
- %8
den"an fakt!r keut sebesar 8 8
> +(.
a2 45(1
b #5*
k"m - %y
%aka : %87 %y7
8 8
> +(.
a 251(
b2 1+521
= = =
1.*5((0(1 -
=
#0+51#10*+4
=
20#542
k"m
Tegangan $ang ter%a&i :
-
σ8
= =
%8 <8 15#0+*+1.2
k"6cm2
?
fr
fr
'K
-
σ8
= =
%8 <8 452140224
k"6cm2
? 'K
15+ %87 k"m %y7 k"m
B. Kontrol Saat Penum(uan! "mur # Hari Data %aterial : fci7
=
Berat pelat per meter panan" : 9u
%!men Tahanan : -
<
1#5 %pa
=
152
= =
152 8 124*5*2 k"6m
= =
1 . 1 .
8
a
8
t
8
2400
251(
8
052
8
2400
8
a
8
t2
8
21(500
8
400
9u
8
,2
052+
8
124*5*2
8
#502+
052+
8
8
9u
8
,2
8
124*5*2
8
#502+
= 144..5....( cm# Penumpukan den"an 2 tumpuan :
0+b
-
%,
= = =
-
%T
=
1 8 10 1 8 10 .#15220 k"m 1
=
1
den"an fakt!r keut sebesar %,7 -
%T7
=
+*45102. k"m
Tegangan $ang ter%a&i :
-
σ8
= =
%8 <8 .5+4+++1+21
k"6cm2
?
fr
'K
-
σ8
= =
%8 <8 .51.00+
k"6cm2
? 'K
fr
Pu
8
,
#20
8
15*+
15+ =
*4.5*2#12 k"m
=
*151+#* k"m
). Kontrol Saat Pemasangan! "mur * Hari Data %aterial : fci7
=
%aka : fr
=
1*5+ %pa
05(
= =
05( 8 #50*111.#0# %pa
=
#05*111.#0# k"6cm2
Berat Pelat per %eter Panan" : 9u
%!men Tahanan : -
8
<
= = =
= = =
√ 4541+04##
152 a 152 251( 124*5*2 k"m
1 . 1 .
8 8
t 052
8 8
2400 2400
8
a
8
t2
8
21(500
8
400
8
9u
8
,2
052+
8
8
124*5*2
8
1+521
052+
8
144..5....( cm#
b
-
%,
= =
1 10 1 10
= -
%T
= = =
den"an fakt!r keut sebesar %,7 -
%T7
221#512#2 k"m 1 8 1 8 2#(.54104 k"m
9u
8
,2
124*5*2
8
1+521
?
fr
15+ =
##1*5.*24 k"m
=
#+.45.1+. k"m
Tegangan $ang ter%a&i :
-
σ8
= =
%8 <8 225*4(1#04
k"6cm2
'K
-
σ8
= =
%8 <8 245.402
k"6cm2
? 'K
fr
Pu
8
,
#20
8
#5*
D. Kontrol Saat Pengecoran! "mur * Hari Data %aterial : fci7
=
%aka : fr
=
1*5+ %pa
05(
8
= =
05( 8 #50*111.#0# %pa
=
#05*111.#0# k"6cm2
Berat Pelat per %eter Panan" : 9u = = = %!men Tahanan : <
= = =
√ 4541+04##
152 a 152 251( 24**54 k"m
1 . 1 .
8 8
t 054
8 8
2400 2400
8
a
8
t2
8
21(500
8
1.00
8
9u
8
,2
052+
8
Pu
8
24**54
8
1+521
052+
8
#20
+(..5....( cm#
b -
%,
= =
1 10 1 10
= -
%T
= = =
den"an fakt!r keut sebesar %,7 -
%T7
411452+..4 1 8 1 8 4(+2520 k"m
9u
8
,2
24**54
8
1+521
?
fr
15+ =
.1(15#4*. k"m
=
(12*52#12 k"m
Tegangan $ang ter%a&i :
-
σ8
= =
%8 <8 105..4#+(.
k"6cm2
'K
-
σ8
= =
%8 <8 125#201
k"6cm2
? 'K
fr
8
,
8
#5*
+. )e ,en&utan "mur * Hari & 0
= = =
& mak'
=
Dimana : W
L4 E
I
1 250 1 250 1.56
= = "aka : & mak'
= =
5 384
x
390
w E
L4 I
beban mati x 0.096 x 20.832 k!cm
a 217
231.3441 m4 √ 4700 4700 44.158804332
= = = = =
L
cm
5 384
= = =
x
207546.38 k!cm2 1 x 12 1 x 12
a
x
t3
2.17
x
0.064
0.01157333 m4
20.832 23134410000 207546.38 1157333.3333
0.026125 cm
# $%
24096.8 & 0
. Menghitung Tulangan Angat (e)*it+nan (embebanan : ,eban "ati - ,e)at en/i)i ()eca't - t+/ +anan ankat
= 10 be)at )eca't = ta =
,eban i/+ - ,eban i/+ 1 )an (eke)a
=
"aka : - ,eban an *a)+' /iankat = ,eban "ati x b ,eban i/+ - ,eban an /ite)ima 'etia titik ankat = "aka : - eanan ta)ik iin baa σ b = =
<'
/iakai t+anan
1249.92 k!m 124.992 k!m 1374.912 k!m
/i+nakan ;-39
&
fy 15+
390 15+
=
260
"a
=
2600
=
( σ b
=
1365.539 2600
=
0.525207 cm2
k!cm2
1.6 cm
2.010619
100 k
5462.157 k 1365.539 k
=
390 "a
D-16
