100 Questions 100 Min. Capacitance NEET-2017/IIT MAINS 2017

A NAME IN CONCEPTS OF PHYSICS

9027187359, 7351266266 XI &XII (CBSE & ICSE BOARD)

IIT-JEE/AIIMS/AIPMT/CPMT/UPTU

Based on Capacitance 1.

7.

Two insulated charged spheres of radii 20 cm and 25 cm respectively and having an equal charge Q are connected by a copper wire, then they are separate [ANS C] (a) Both the spheres will have the same charge Q (b) Charge on the 20 cm sphere will be greater than that

(c) 8.

on the 25 cm sphere

condenser will be

(d) Charge on each of the sphere will be 2Q

(c)

3.

(a)

Separation between the plates of a parallel plate capacitor is d and the area of each plate is A . When a slab of material of dielectric constant k and thickness t(t  d) is introduced between the plates, its capacitance becomes [ANSC]

0 A 1  d  t1   k 

0 A 1  d  t1   k 

(d) W / 4

dielectric constant k2 . The potential difference across the

on the 20 cm sphere

(a)

4W

Between the plates of a parallel plate condenser, a plate of thickness t1 and dielectric constant k1 is placed. In the rest of the space, there is another plate of thickness t 2 and

(c) Charge on the 25 cm sphere will be greater than that

2.

A capacitor of capacity C has charge Q and stored energy is W . If the charge is increased to 2Q , the stored energy will be [ANSC] (a) 2W (b) W / 2

(b)

(d)

0 A

9.

1  d  t1   k 

0 A 1  d  t1   k  10.

potentials of the bigger drop and the smaller drop is [ANS B] (a) 8 : 1

(b) 4 : 1

(c) 2 : 1

(d) 1 : 8

Q A 0

(a)

q2 2 0 AK q 2 0 A

1000 small water drops each of radius r and charge q

(a) CV 2 / 4 (c)

5.

coalesce together to form one spherical drop. The potential of the big drop is larger than that of the smaller drop by a factor of [ANS B] (a) 1000 (b) 100 (c) 10 (d) 1 The capacitance of a spherical condenser is 1F . If the spacing between the two spheres is 1 mm , then the radius of the outer sphere is (a) 30cm (c) 5cm

6.

[ANS D]

(c)

240 F

100 QUESTIONS 100 MIN. SERIES FOR MED. / ENGG.

Opp. Sagar Complex Meerut

q2 2 0 A2 K

(d) CV 2

(b) V / N (d) V  N 2 / 3

VN

A 6 F capacitor is charged from 10 volts to 20 volts . Increase in energy will be (a) 18  10 J

(d) None of the above

P.L. SHARMA ROAD, center

3CV 2 / 4

4

the medium between them is 6. The capacity of the condenser will be [ANS A] (a) 240 pF (b) 240F

(d)

N identical spherical drops charged to the same potential V are combined to form a big drop. The potential of the new drop will be [ANS D]

(c)

(b) 6m (d) 3m

The respective radii of the two spheres of a spherical condenser are 12 cm and 9 cm . The dielectric constant of

q2  0 AK

(b) CV 2 / 2

(a) V 12.

(b)

A capacitor of capacity C is connected with a battery of potential V in parallel. The distance between its plates is reduced to half at once, assuming that the charge remains the same. Then to charge the capacitance upto the potential V again, the energy given by the battery will be [ANS D]

4.

11.

[ANS A]

 Qt t  (b) 0  1  2  A  k1 k2 

 k1 k2   Q    (d) 0 (k1t1  k2t 2 ) t  A  1 t2  Force of attraction between the plates of a parallel plate capacitor is [ANS A] (c)

(c)

Eight small drops, each of radius r and having same charge q are combined to form a big drop. The ratio between the

Q  t1 t 2     A 0  k1 k2 

(c) 13.

4.5  10

4

J

[ANS B] 4

(b) 9  10 J (d) 9  10 6 J

Twenty seven drops of water of the same size are equally and similarly charged. They are then united to form a bigger drop. By what factor will the electrical potential changes (a) 9 times

(b) 27 times

(c) 6 times

(d) 3 times

ANS A

(CAPACITANCE)

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9027187359, 7351266266 XI &XII (CBSE & ICSE BOARD) 14.


The outer sphere of a spherical air capacitor is earthed. For increasing its capacitance [ANS B]

22.

(a) Vacuum is created between two spheres (b) Dielectric material is filled between the two spheres

(a) 4  103 m

(c) The space between two spheres is increased (d) The earthing of the outer sphere is removed 15.

(c) 16.

17.

23.

Force acting upon a charged particle kept between the plates of a charged condenser is F . If one plate of the condenser is removed, then the force acting on the same particle will become [ANS B] (a) 0

F

(c) 24.

(a) 9  106 volts

(b) 4.5  106 volts

(c) 1.8  107 volts

(d) 13.5  106 volts

25.

The distance between the circular plates of a parallel plate condenser 40mm in diameter, in order to have same capacity as a sphere of radius 1 metre is [ANS B] 26.

(b) 0.1 mm (d) 10 mm

18.

The capacitance of a metallic sphere will be 1F , if its radius is nearly [ANS A] (a) 9 km (b) 10 m (c) 1.11 m (d) 1.11 cm

19.

Between the plates of a parallel plate condenser there is 1mm thick paper of dielectric constant 4. It is charged at 100 volt . The electric field in volt / metre between the plates of the capacitor is (a) 100 (c) 25000

20.

[ANS B]

21.

V0 E0 , 3 3

(a) 7.2  103 V

(b) 7.2  102 V

(c) 1.44  10 2 V

(d) 1.44  103 V

Two spherical conductors each of capacity C are charged to potentials V and V . These are then connected by means of a fine wire. The loss of energy will be [ANS C] 1 (a) Zero (b) CV 2 2 (c) CV 2 (d) 2CV 2 The area of the plates of a parallel plate condenser is A and the distance between the plates is 10mm . There are two dielectric sheets in it, one of dielectric constant 10 and thickness 6mm and the other of dielectric constant 5 and thickness 4 mm . The capacity of the condenser is [ANS C] 12 2 (a) (b) 0 A 0 A 3 35 5000 0 A 7

(d) 1500  0 A

A 2F capacitor is charged to 100 volt and then its plates are connected by a conducting wire. The heat produced is

(c) 28.

(a)


29.

0.01 J

(b) 0.1 J (d) 0.001 J

A parallel plate condenser with oil between the plates (dielectric constant of oil K  2 ) has a capacitance C . If the oil is removed, then capacitance of the capacitor becomes

(c)

A parallel plate capacitor has a capacity C . The separation between the plates is doubled and a dielectric medium is introduced between the plates. If the capacity now becomes 2C , the dielectric constant of the medium is [ANS C] (a) 2 (b) 1 (c) 4 (d) 8


(d) Q0 ,

[ANS C]

(d) 30 F


V0 , 3 E0 3

(a) 1 J

between the parallel plates is 6mm . A copper plate of 3mm thickness is introduced symmetrically between the plates. The capacitance now becomes [ANS D] (a) 5 F (b) 7.5 F 22.5 F

27.

Q0 ,

(b) Q0 , 3V0 , 3E0

A charge of 109 C is placed on each of the 64 identical drops of radius 2cm . They are then combined to form a bigger drop. Find its potential [ANS A]

(c)

(b) 100000 (d) 4000000

The capacitance of an air capacitor is 15 F the separation

(c)

(c) 1cm (d) 1  103 cm A capacitor when filled with a dielectric K  3 has charge Q0 , voltage V0 and field E0 . If the dielectric is replaced

(a) 3Q0 , 3V0 , 3E0

(b) F / 2 (d) 2 F

(b) 1  10 3 m

with another one having K  9 the new values of charge, voltage and field will be respectively (ANS D)

Two metallic charged spheres whose radii are 20 cm and 10 cm respectively, have each 150 micro  coulomb positive charge. The common potential after they are connected by a conducting wire is [ANS A]

(a) 0.01mm (c) 1.0 mm

The diameter of each plate of an air capacitor is 4 cm . To make the capacity of this plate capacitor equal to that of 20cm diameter sphere, the distance between the plates will be [ANS B]

2C C

2

(b) 2C C (d) 2

[ANS D]

The capacity of a parallel plate condenser is 10 F without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in F is [ANS D]

(a) 10 (c) 15

(b) 20 (d) 13.33 (CAPACITANCE)




31.

32.

33.


Two identical charged spherical drops each of capacitance C merge to form a single drop. The resultant capacitance is (a) Equal to 2C (b) Greater than 2C (c) Less than 2C but greater than C (d) Less than C [ANS C] If the capacity of a spherical conductor is 1 picofarad, then its diameter, would be [ANS B] (a) 1.8  10 3 m

(b) 18  10 3 m

(c) 1.8  10 5 m

(d) 18  10 7 m

(c) 40.

Sixty-four drops are jointed together to form a bigger drop. If each small drop has a capacitance C, a potential V, and a charge q, then the capacitance of the bigger drop will be (a) C (b) 4C (c) 16C (d) 64C [ANS B] A variable condenser is permanently connected to a 100 V battery. If the capacity is changed from 2 F to 10  F , then change in energy is equal to (a) 2  10 2 J (c)

34.

39.

3.5  10 2 J

(c) 41.

(b) 2.5  10 2 J 2

J

In a capacitor of capacitance 20 F , the distance between

(a) 2 F (c) 35.

26.6 F

(b) 15.5 F

(c) 42.

(d) 32 F

The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is 2 F . The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is

43.

[ANS A]

36.

(a) 11.2F

(b) 15.6 F

(c) 19.2F

(d) 22.4 F

Two insulated metallic spheres of

and

5 F

capacitances are charged to 300 V and 500V respectively. The energy loss, when they are connected by a wire is [ANS C]

37.

(a) 0.012 J

(b) 0.0218 J

(c) 0.0375 J

(d) 3.75 J

conducting wire, the charge on the smaller sphere is

45. [ANS B]

38.

44.

(b) 10 C

(c) 15 C

(d) 20C

A body of capacity 4  F is charged to 80 V and another body of capacity 6  F is charged to 30V. When they are connected the energy lost by 4  F capacitor is

[ANS A]

100 QUESTIONS 100 MIN. SERIES FOR MED. / ENGG. P.L. SHARMA ROAD, center Opp. Sagar Complex Meerut

R1 R2 R2  R1

2 0 A

2

q2 2 0 A

(b)

q 2 0 A 2

(d) None of the above

3 0 AV02 d

 0 AV02 3d

(b)

 0 AV02

(d)

 0 AV02

2d d

If the distance between parallel plates of a capacitor is halved and dielectric constant is doubled then the capacitance [ANS C] (a) Decreases two times

(b) Increases two times

(c) Increases four times

(d) Remain the same

If there are n capacitors in parallel connected to V volt source, then the energy stored is equal to [ANS B]

(c)

Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 C each. After the two spheres are joined by a

(a) 5 C

q2

(a) CV

3 F

(d)

A parallel plate capacitor has plate area A and separation d. It is charged to a potential difference V0. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is [ANS D] (a)

the plates is 2mm. If a dielectric slab of width 1mm and dielectric constant 2 is inserted between the plates, then the new capacitance is [ANS C]

R1 R 2 R1  R 2

The mean electric energy density between the plates of a charged capacitor is (here q = charge on the capacitor and A = area of the capacitor plate) [ANS A] (a)

[ANS D]

(d) 4  10

(a) 7.8 mJ (b) 4.6 mJ (c) 3.2 mJ (d) 2.5 mJ A solid conducting sphere of radius R1 is surrounded by another concentric hollow conducting sphere of radius R2. The capacitance of this assembly is proportional to [ANS D] R2  R1 R 2  R1 (a) (b) R1 R2 R1 R 2

CV 2

(b)

1 nCV 2 2

(d)

1 CV 2 2n

If n drops, each of capacitance C, coalesce to form a single big drop, then the ratio of the energy stored in the big drop to that in each small drop will be [ANSC] (a) n : 1

(b) n1/3 : 1

(c) n5/3 : 1

(d) n2 : 1

A conducting sphere of radius 10cm is charged 10 C . Another uncharged sphere of radius 20 cm is allowed to touch it for some time. After that if the sphere are separated, then surface density of charges, on the spheres will be in the ratio of [ANS C] (a) 1 : 4

(b) 1 : 3

(c) 2 : 1

(d) 1 : 1

(CAPACITANCE)




The work done in placing a charge of 8  10 a condenser of capacity 100 micro-farad is (a) 32  10 32 Joule (c)

47.

48.

49.

3.1  10 26 Joule

IIT-JEE/AIIMS/AIPMT/CPMT/UPTU coulomb on

3.

[ANS A]

(b) 90 kW

(c) 180 kW

(d) 360 kW

(c)

1 F 8

(b) 8 F

(c)

1 F 2

(d)

3F

2F

60 F

(d) 10 F

Q 20F

4.

The capacities of two conductors are C1 and C2 and their respective potentials are V1 and V2 . If they are connected by a thin wire, then the loss of energy will be given by [ANS C]

A spherical drop of capacitance 1 F is broken into eight drops of equal radius. Then, the capacitance of each small drop is ...... [ANS C] (a)

12F P

(b) 3 F

(d) 4  10 10 Joule

(a) 45 kW

In the circuit diagram shown in the adjoining figure, the resultant capacitance between P and Q is [ANS B] (a) 47 F

(b) 16  10 32 Joule

A 40 F capacitor in a defibrillator is charged to 3000 V. The energy stored in the capacitor is sent through the patient during a pulse of duration 2ms. The power delivered to the patient is [ANS B]

1 F 4

5.

(a) 12  10–6 J

(b) 9  10–4 J

(c) 4  10 J

(d) 4  10–9 J

(a)

C1C2 (V1  V2 ) 2(C1  C2 )

(b)

C1C2 (V1  V2 ) 2(C1  C2 )

(c)

C1C2 (V1  V2 )2 2(C1  C2 )

(d)

(C1  C2 )(V1  V2 ) C1C2

A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is A metre 2 and the separation is

If the potential of a capacitor having capacity of 6 F is increased from 10 V to 20 V, then increase in its energy will be [ANS A]

t metre .

The

dielectric

constants

are

k1

respectively. Its capacitance in farad will be (a)

0 A

A parallel plate capacitor having a plate separation of 2 mm is charged by connecting it to a 300 V supply. The energy density is [ANS B]

(b)

 0 A k1  k2

(a) 0.01 J/m3

(b) 0.1 J/m3

(c)

(c) 1.0 J/m3

(d) 10 J/m3

–6

50.

18

(d)

t t

and

k2

[ANS B]

(k1  k2 ) .

2

k2

k1

2 0 A (k1  k2 ) t

 0 A k1  k2 t

.

2

Problems Based on Grouping of Capacitors 6. 1.

A parallel plate capacitor is made by stacking n equally spaced plates connected alternately. If the capacitance between any two plates is C then the resultant capacitance is

(a) C (b) 3C

[ANS C]

2.

(a) C

(b) nC

(c) (n  1)C

(d) (n  1)C

(c) (d)

Five capacitors of 10 F capacity each are connected to a d.c. potential of 100 volts as shown in the adjoining figure. The equivalent capacitance between the points A and B will be equal to [ANS D] 10F

(a) 40 F (b) 20 F (c)

10F

A

30 F

Three equal capacitors, each with capacitance C are connected as shown in figure. Then the equivalent capacitance between A and B is [ANS B]

10F 10F

B

10F

(d) 10 F

7.

C 3

A

C

C

C

B

3C 2

2F capacitance has potential difference across its two terminals 200 volts . It is disconnected with battery and then

another uncharged capacitance is connected in parallel to it, then P.D. becomes 20 volts . Then the capacity of another capacitance will be (a) 2F

(b) 4 F

(c) 18 F

(d) 10 F

[ANS C]

100 Volt


(CAPACITANCE)




9.

10.


In the following circuit, the resultant capacitance between A and B is 1F. Then value of C is [ANS D] (a)

32 F 11

(b)

11 F 32

(c)

23 F 32

(d)

32 F 23

C

(a) 107 joule and 300 paise (b) 5  106 joule and 300 paise (c)

1F

A

(d) 107 joule and 150 paise 8F

14. 6F

2F

2F

4F

12F

5 6

Two dielectric slabs of constant K1 and K 2 have been filled

(b)

in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor [ANS D]

7 6

(c)

8 3

(a)

2 0 A (K1  K2 ) 2

(b)

2 0 A  K1  K 2    2  K1  K 2 

(c)

2 0 A  K1  K 2    2  K1  K 2 

(d)

2 0 A  K1  K 2    d  K1  K 2 

k1

15.

d k2

1F

y

1F

x

2F

What is the effective capacitance between points X and Y (a) 24 F

C3 = 6F X

(c) 12F

A capacitor 4 F charged to 50 V is connected to another

[ANS A]

(a) 1.5 and 1.33 (b) 1.33 and 1.5 (c) 3.0 and 2.67 (d) 2.67 and 3.0 Two identical parallel plate capacitors are connected in series to a battery of 100 V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively [ANS B] (a) 50 V, 50 V (b) 80 V, 20 V (c) 20 V, 80 V (d) 75 V, 25 V

16.

P.L. SHARMA ROAD, center Opp. Sagar Complex Meerut

C2 = 6F D

C5 = 20F

Y

The charge on a capacitor of capacitance 10 F connected as shown in the figure is

[ANS A] 2

(a) 20C 10F

3

(b) 15 C (c) 10 C (d) Zero 17.

2V

Three plates A, B, C each of area 50 cm 2 have separation 3mm between A and B and 3mm between B and C The energy stored when the plates are fully charged is [ANS B] 9

(a) 1.6  10 J

another uncharged condenser of capacity C2 in parallel. The energy dissipated in the process is [ANS A] C2 C1 U0 U0 (a) (b) C1  C2 C1  C2


C

B

C4 = 6F

The electrostatic energy stored in it is U0 . It is connected to

and the cost of charging them, if electrical energy costs [ANS C] 108 paise per kWh , will be

A

(d) 6 F

A condenser of capacity C1 is charged to a potential V0 .

 C  C2  C1C2 U0 U0 (c)  1 (d)  C  C 2 ( C 2  1  C2 )  1 100 capacitors each having a capacity of 10 F are connected in parallel and are charged by a potential difference of 100 kV . The energy stored in the capacitors

[ANS D]

C1 = 6F

(b) 18 F

connection in multiples of (10 J ) is

13.

1F

(d) 2

2

12.

Four capacitors are connected as shown in the figure. Their capacities are indicated in the figure. The effective capacitance between points x and y is (in F ) [ANS C] (a)

B

capacitor of 2F charged to 100 V with plates of like charges connected together. The total energy before and after

11.

5  106 joule and 150 paise

(b) 2.1  109 J (c)

9

5  10 J

(d) 7  109 J 18.

A B C

12V

A capacitor of 20 F is charged to 500 volts and connected in parallel with another capacitor of 10 F and charged to [ANS C] 200 volts . The common potential is (a) 200 volts

(b) 300 volts

400 volts

(d) 500 volts

(c)

(CAPACITANCE)





A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants k1 ,k 2 and k 3 as shown. If a

23.

with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4, as shown in the figure. The capacity of the capacitor changes to [ANS A] (a) 25  F

single dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given by [ANS B] A/2

A/2

K1

K2

(b) 20  F d/2

(c)

d

24.

A A = Area of plates

1 1 1 1    k k1 k 2 2k 3

(c) k  20.

k1 k 2  2k 3 k1  k 2

K=4

40  F

(d) 5  F

K3

(a)

Consider a parallel plate capacitor of 10 F (micro-farad)

(b)

1 1 1   k k1  k 2 2k 3

[ANS B]

(d) k  k1  k 2  2k3

3F

A

B

Q

(a) Q, 2Q

C1

(b) Q / 3, 2Q / 3

Two capacitors A and B are connected in series with a battery as shown in the figure. When the switch S is closed and the two capacitors get charged fully, then 2F

Two capacitors C1 and C2 = 2C1 are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and C1 holds charge Q. The switch is closed. At steady state, the charge on each capacitor will be

(c)

S

3Q / 2, 3Q

R

(d) 2Q / 3, 4Q / 3

[ANS B]

25.

C2 = 2C1

Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2 . The

S

10 V

negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy

(a) The potential difference across the plates of A is 4V and across the plates of B is 6V (b) The potential difference across the plates of A is 6V and across the plates of B is 4V (c) The ratio of electrical energies stored in A and B is 2 : 3 (d) The ratio of charges on A and B is 3 : 2 21.

Two capacitors of 10  F and 20  F are connected in series with a 30V battery. The charge on the capacitors will be, respectively [ANS D] (a) 100  C , 200  C (b) 200  C , 100  C (c) 100  C , 100  C

22.

of the combined system is

26.

A/2

K1 K3

27.

d

K2

1 C(V12  V22 ) 4

(b)

1 C(V12  V22 ) 4

(c)

1 CV1  V2 2 4

(d)

1 CV1  V2 2 4

A capacitor of capacity C1 is charged upto V volt and then final potential difference across each will be

In the figure a capacitor is filled with dielectrics. The resultant capacitance is [ANS D]

d/2

(a)

connected to an uncharged capacitor of capacity C2 . Then

(d) 200  C , 200  C

A/2

[ANS C]

(a)

C2 V C1  C 2

 C  (b)  1  2  V C1  

(c)

C1 V C1  C 2

 C  (d)  1  2  V C1  

In the figure a potential of + 1200 V is given to point A and point B is earthed, what is the potential at the point P

2 0 A  1 1 1     d  k1 k 2 k 3 

(b)

(c)

2 0 A k1  k 2  k 3  d

(d) None of these

0 A  1

 d  k1



1 1   k2 k3 


(b) 200 V (c) 400 V (d) 600 V

[ANS C]

4F

(a) 100 V (a)

[ANS C]

3F A

B P 2F

(CAPACITANCE)


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XI &XII (CBSE & ICSE BOARD) 28.


The charge on 4 F capacitor in the given circuit is .... in C [ANS B] 1F

(a) 12

4F 5F

(b) 24

3F

(c) 36

1.

of identical capacitors marked 8F, 250V , we require a minimum number of capacitors (a) 40 (b) 32

(d) 32 10 V

29.

30.

Three plates of common surface area A are connected as shown. The effective capacitance will be [ANS D] 0 A (a) d 3 0 A d (b) d A B 3 0 A (c) d 2 d 2 0 A (d) d

To form a composite 16F, 1000V capacitor from a supply

(c) 8 (b)

(d) 2

Suppose C = 8 F , C' = 16F and V = 250 V, V' = 1000V C, V 1

C, V

C, V

2

n

1 2 m

V'

Three capacitors of capacitance 1 F, 2 F and 3 F are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 F capacitor is [ANS D]

Suppose m rows of given capacitors are connected in parallel and each row contains n capacitors then potential V' difference across each capacitor V  and equivalent n

(a) 2 V

(b) 4 V

capacitance of network C' 

(c) 1 V

(d) 6 V

mC on putting the values we n

get n = 4 and m = 8  Total capacitors = n  m = 4  8 = 32 Short Trick : For such type of problems number of 2

capacitors = 2.

2

C'  V '  16  1000        32 C V 8  250 

An infinite number of identical capacitors each of capacitance 1F are connected as in adjoining figure. Then the equivalent capacitance between A and B is (a) 1F (b) 2F (c)

8 capacitors 16 capacitors

1 F 2



(d)  (b)

A

B

This combination forms a G.P. S  1  Sum of infinite G.P. S 

1 1 1   ...... 2 4 8

a 1r

Here a = first term = 1 and r = common ratio   S

1 1


1 2

1 2

 2  Ceq  2F

(CAPACITANCE)


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XI &XII (CBSE & ICSE BOARD) 3.

IIT-JEE/AIIMS/AIPMT/CPMT/UPTU (a) 3 : 1

Two condensers of capacities 2C and C are joined in parallel and charged upto potential V. The battery is removed and the condenser of capacity C is filled completely with a medium of dielectric constant K. The p.d. across the capacitors will now be (a)

3V K2

(c)

V K2

(b)

3V K

(d)

V K

(b) 5 : 1

(c)

B

100V

20 A

(c)

U2

6.

10

(b) VAB  75 V, VBC  25 V

Ceq

 Q  CV 

5  100  250C 2

(a) Zero (c) (c)

 6 2  Charge in 6 F branch  VC    100  150 C 6 2 6F

7. 2F

VAB

5.

100 V

……(ii)

(b)

25CV 2 6

(d)

9CV 2 2

Total charge  (2C) (2V)  (C) (V)  3CV 3CV V 3C

1 3 (3C) (V )2  CV 2 2 2

Condenser A has a capacity of 15 F when it is filled with

charged separately by a battery of 100 V . After charging, both are connected in parallel without the battery and the dielectric medium being removed. The common potential now is

C

Figure given below shows two identical parallel plate capacitors connected to a battery with switch S closed. The switch is now opened and the free space between the plate of capacitors is filled with a dielectric of dielectric constant 3. What will be the ratio of total electrostatic energy stored in both capacitors before and after the introduction of the dielectric



10 CV 2 6

a medium of dielectric constant 15. Another condenser B has a capacity of 1F with air between the plates. Both are

150   25 V and VBC  100  VAB  75 V 6


3CV 2 2

 Energy 

1F A



5

 Common potential 

B

2

A parallel plate capacitor of capacitance C is connected to a battery and is charged to a potential difference V. Another capacitor of capacitance 2C is connected to another battery and is charged to potential difference 2V. The charging batteries are now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

VAB  25 V, VBC  75 V (d) VAB  VBC  50 V (3  3)  (1  1) 5  6 2   1     1  F (3  3)  (1  1) 2 6 2

1 1 V (3C)V 2  (3C)   2 2 3

So, U1  3

C

(a) VAB  VBC  100 V (c)

U2 

1F 1F

……(i)

In the second case when key K is opened and dielectric medium is filled between the plates, capacitance of both the capacitors becomes 3C, while potential difference V across A is V and potential difference across B is 3 hence energy of the system now is

3CV 3V  (K  2)C K  2

In the figure below, what is the potential difference between the point A and B and between B and C respectively in steady state 3F 1F 3F

1 1 CV 2  CV 2  CV 2 2 2

U1 

As charge is conserved

4.

B

Initially potential difference across both the capacitor is same hence energy of the system is

Now condenser of capacity C is filled with dielectric K, therefore C2 = KC  q1  q2  (C2'  2C)V '  V ' 

A

(d) 5 : 3

q1  2CV , q2  CV

(a)

V

(c) 3 : 5

(b)

(a) 400V

(b) 800 V

(c) 1200 V

(d) 1600 V

Charge on capacitor A is given by Q1  15  10 6  100  15  10 4 C Charge on capacitor B is given by Q 2  1  10 6  100  10 4 C

(CAPACITANCE)



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Capacity of capacitor A after removing dielectric

15  10 6   1F 15 Now when both capacitors are connected in parallel their equivalent capacitance will be Ceq  1  1  2F So common potential 

(15  10 4 )  (1  10 4 ) 2  10 6

+

Q

–

+

2pF

Q

–

2pF

Q = 60 pC Q = 60 pC + – + –



V1 = 30 V V2 = 30 V

 800V .

+ – 50 V

 when S3 is closed V1  30V and V2  20V 8.

In an isolated parallel plate capacitor of capacitance C, the four surface have charges Q1 , Q 2 , Q 3 and Q4 as shown. The potential difference between the plates is

Q1  Q2  Q3  Q4 2C

(a)

Q1

Q 2  Q3 2C Q 2  Q3 (c) 2C Q1  Q4 (d) 2C (c)

Q3 Q2

(b)

10.

(c)

Q4

(d) d

0 A x

dC d  0 A dt dt



;

1   x

 0 A  dx   0 A  dx       x 2  dt  d 2  dt 

dC  0 A dC 1  2 v i.e.  2 dt dt d d



Plane conducting surfaces facing each other must have equal and opposite charge densities. Here as the plate areas

11.

The charge on a capacitor means the charge on the inner surface of the positive plate (here it is Q2 ) Potential difference between the plates 

charge capacitanc e

For the circuit shown, which of the following statements is true V1=30V S1 + –

V2=20V S3 + –

C1=2pF

C2=3pF

 12.

2msT C

(b)

2mCT s

mCT s

(d)

1 CV 2  m.s.T 2

2msT C

A network of four capacitors of capacity equal to C1  C, C2  2C, C3  3C and C4  4C are conducted in a battery as shown in the figure. The ratio of the charges on C 2 and C 4 is

(c) With S1 and S2 closed V1  V2  0

(a)

(d) With S1 and S3 closed, V1  30 V, V2  20 V

Q1  30  2  6 pC

and

Q2  20  3  60 pC or Q1  Q2  Q (say)

(b) (c)

The situation is situation is similar as the two capacitors in series are first charged with a battery of emf 50 V and then disconnected



(b)

msT C

 V

(b) With S3 closed V1  V2  25V


(c)

S2

(a) With S1 closed, V1  15 V, V2  20 V

Charges on capacitors are

A fully charged capacitor has a capacitance ‘C’. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity ‘s’ and mass ‘m’. If the temperature of the block is raised by ‘ T ’, the potential difference ‘V’ across the capacitance is 

(a)

Q 2Q 2 Q  (Q 2 ) Q 2  Q3  2   2  . C 2C 2C 2C

(d)

d2

C

(b)

are equal, Q2  Q3 .

9.

The plates of a parallel plate condenser are pulled apart with a velocity v . If at any instant their mutual distance of separation is d , then the magnitude of the time of rate of change of capacity depends on d as follows 1 1 (a) (b) d d2

(d)

22 3 3 22 7 4 4 7

C2 = 2C

C1 = C

C4 = 4C

C3 = 3C

V

(CAPACITANCE)


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XI &XII (CBSE & ICSE BOARD) (b)


The given circuit can be redrawn as follows V Q A C1

C2

V

(a)

C3

(b)

Line (A) C4 = 4C X

Line (B)

QB

V

(c)

(d)

X

V

V

Ceq 

C1 C2 C3 6C  C1 C2  C2 C3  C3 C1 11

QA C 6C / 11 3  A   QB CB 4C 22 13.

A 4 F capacitor, a resistance of 2.5 M is in series with 12 V battery. Find the time after which the potential difference across the capacitor is 3 times the potential difference across the resistor. [Given ln(2)= 0.693 (a) 13.86 s

X

X

Figure (a) shows two capacitors connected in series and joined to a battery. The graph in figure (b) shows the variation in potential as one moves from left to right on the branch containing the capacitors, if [MP PMT 1999] Y

(b) 6.93 s

(c) 7 s (a)

3.

(d) 14 s

V VR  0 = V0 4

t  e RC

X

t

C1

 1  = e 10 4

(a)

C2

(b)

(a) C1  C2

t e 10

t  4  log e 4   t  10 log 4 = 13.86 s 10 (RC = 2.5  106  4  10-6 = 10)

(b) C1  C2 (c)

C1  C2

(d) The information is not sufficient to decide the relation between C1 and C2 4.

1.

What physical quantities may X and Y represent ? ( Y represents the first mentioned quantity) Y

During charging a capacitor variation of potential V of the capacitor with time t is shown as [MP PET 2003]

(a)

(b)

V

V

[NCERT 1978; MP PMT 2003] O

t

(c) V

X

(d)

O

t

O

t

V

(a) Pressure v/s temperature of a given gas (constant volume) (b) Kinetic energy v/s velocity of a particle

O

(c) Capacitance v/s charge to give a constant potential (d) Potential v/s capacitance to give a constant charge 2.

Between the plates of a parallel plate capacitor a dielectric plate is introduced just to fill the space between the plates. The capacitor is charged and later disconnected from the battery. The dielectric plate is slowly drawn out of the capacitor parallel to the plates. The plot of the potential difference across the plates and the length of the dielectric plate drawn out is [MP PET 1997]


5.

t

Change Q on a capacitor varies with voltage V as shown in the figure, where Q is taken along the X-axis and V along the Y-axis. The area of triangle OAB represents [Kerala (Engg.) 2001] Y

(a) Capacitance (b) Capacitive reactance

A

V

(c) Magnetic field between the plates (d) Energy stored in the capacitor

O

Q

B

X

(CAPACITANCE)


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Equipotential surfaces are shown in figure. Then the electric field strength will be 10V

Y

(c)

(cm)

x

30° 10

20

O

X

30

E x

X

O

(cm)

10.

(a) 100 Vm–1 along X-axis (b) 100 Vm–1 along Y-axis (c) 200 Vm–1 at an angle 120o with X-axis (d) 50 Vm–1 at an angle 120o with X-axis Three identical capacitors are given a charge Q each and they are then allowed to discharge through resistance R1, R2 and R3. Their charges, as a function of time shown in the graph below. The smallest of the three resistance is

Y S R

log i R1

P

X

t

t

(b) R2

(c) R1

(d) Cannot be predicted

11.

A condenser of 2F capacitance is charged steadily from 0 to 5 Coulomb. Which of the following graphs correctly represents the variation of potential difference across its plates with respect to the charge on the condenser (a)

Q

R3 R2

(a) R3

X

In an RC circuit while charging, the graph of in i versus time is as shown by the dotted line in the diagram figure, where i is the current. When the value of the resistance is doubled, which of the solid curve best represents the variation of in i versus time [IIT-JEE (Screening) 2004]

Q

8.

Y

30V

20V

E

O

7.

(d)

Y

(a) P

(b) Q

(c) R

(d) S

Two concentric conducting thin spherical shells A, and B having radii rA and rB ( (rB  rA ) are charged to QA and

QB (| QB || QA |) . The electrical field along a line, (passing through the centre) is

[AIIMS 2005]

(b) 6

V ( 10 V)

(a) E

V ( 106 V)

2.5

(b) E

5 0 5

(c)

Q (d)

5

Q

6

V ( 10 V) 5

(c)

rA

rB

x

0

rA rB

(d)

E

E

V ( 106 V) 2.5 0

9.

5

5

Q

rA rB

x

0

rA

rB

x

Q

Two identical point charges are placed at a separation of d. P is a point on the line joining the charges, at a distance x from any one charge. The field at P is E, E is plotted against x for values of x from close to zero to slightly less than d. Which of the following represents the resulting curve

(a)

(b)

Y E O

Y E

x

X

O

x

X


(CAPACITANCE)


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100 Questions 100 Min. Capacitance NEET-2017/IIT MAINS 2017

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