Desarrollo de ejercicio 8.1 treybalDescripción completa
Descripción: treybal distillation
Descripción: Problemas 11.2 Libro Transferencia de Masa- Treybal
Soluciones Treybal
Resultados del problema 5.3 treybal
Descripción: Solution to Treybal 9.10
Descripción completa
Treybal 5.2 y 5.4
Solucionario del capítulo 3 del libro operaciones de transferencia de masa de Robert E TreybalDescripción completa
Descripción completa
rDescripción completa
Descripción: Treybal 5.2 y 5.4
treybal
0 3 3 2.9 At 1 std atm ,100 C ,density of air=0.9482kg/m ,the viscosity= 2.18x10 kg/m.s , thermal conductivity = 0.0317 W/m.K , specific heat at constant pressure = 1.047 kJ/kg.K, 0 5 At 25 C the viscosity = 1.79x10 kg/m.s 0 a. Calculate the kinematic viscosity at 100 C 0 b. Calculate thermal diffusivity at 100 C 0 c. Calculate Prandtl number at 100 C d. Assuming that for air at 1 std ™ ,Pr=Sc, and Sc=const with changing temperature, 0 calculate D for air at 25 C . Compare with the value of D for the system O N at 1 2 2 0 std atm,25 C . Ans: a. Finding kinematic viscosity λ λ = μ/ρ 5 =(2.18x10 )/(0.9482 5 2 =2.299x10 m /s b.finding thermal diffusivity α = k/C pρ = (0.0317)/(1.047x0.9482) 2 =.03193Wm /kJ c. To find Prandtl number, Pr= C p μ /k 5 =(1.047x2.18x10 )/(.0317) =.015161 d. To find diffusivity D o Pr=Sc,=0.15161 , T=25 C P =1 atm Sc= Schimdt number Sc= μ/ρD D= μ/ρSc 5 = (2.18x10 )/(0.9482x0.15161) 4 2 =1.564x10m /s
