Design a Fracture Treatment

DESIGN A FRACTURE TREATMENT 1. Fracture Coefficient

Use:



       But

       ( ) )                      

Then:

      ( () )() ()

  () √   2. Fracture Area

Use:

)()   ()   ()     But    ()       √   ()   ()() () 

From the efficiency table, when x = 2.66, efficiency = 31%. Then:

  () () 

     

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3. Weight Of Propping Agent - Weight of propping agent per unit area of fracture

()     ( (   )( )( ) )       

-

Total weight of propping agent required

   ( )     ()       4. Total Injected Volume - Volume of fluids injected

( )      -

Volume of propping agent

    ( )       ( )   ()

( )      So Total Injected Volume V(total injected) =

( )  ( )

= 40000 + 8051.35 = 48051.35 gals 5. Flow Rate

)   (









6. Surface Injection Pressure Use

      

But,

                 ()

And,

  [ [()] ()] Thermal expansion coefficient is taken to be

  [()]     More,

     x = 4.42 (where = ?)

  () ()       Therefore,

   ()( ()() )       Hence, The injection pressure

       

  





7. Hydraulic Horse Power Use

      ()    ()() ()()     

8. The Productivity Ratio - The equivalent radius for the facture area

              -

From figure, the permeability of 10-20 mesh sand is 6000 Md, Then, ()

    (    () ) 

-

Facture Penetration rate

           Using the productivity ratio graph with the value of C=11.1 and productivity ratio is

5.

  ,   

from the





FIGURE TO REFER











Design a Fracture Treatment

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