this is a work articulates how the types of circuit design and electro-pneumatic within the types of designs are meeting by the cascade method and the method step by stepFull description
this is a work articulates how the types of circuit design and electro-pneumatic within the types of designs are meeting by the cascade method and the method step by stepDescripción completa
Home design magazine.
Descripción completa
ste
search engine optimizationFull description
Create CV01N
ABAP badi creation stepsFull description
Descripción: Echocardiography
Description complète
Reiki Energy healing
CMG step by step guideFull description
This document helps in creating IDOC's.Description complète
Description complète
Panduan Software MIKEFull description
Step-by-step photographic guide with inspirational projects to make succesfull woodworking.Descripción completa
CMG step by step guideDeskripsi lengkap
This document helps in creating IDOC's.
Step by step learningDescription complète
BRAINSTORMING Subject
DATE: 30/11/2016
: Comparison of step shaft deflection by analytical and KISSsoft.
PRESENCE : 1 Manish Parmar 3 Hemil Shah 5 Harsh Shah 7 Krunal Joshi
2 4 6 8
Mayur Desai Dharmik Lakhtariya Brijesh Vastarpara Rut Shah
Find Shaft Deflection with analytical method There are several methods for finding deflection of stepped shaft. For analytical calculation, we are taking Successive Integration method on below example (In Figure 1).
We assume that there are no axial forces so that the equilibrium equation in the x direction is identically satisfied. In Figure 2, a free-body diagram of the shaft is given. By applying equilibrium condition we got below equation.
PREPARED BY: R & D TEAM
BRAINSTORMING
DATE: 30/11/2016
By putting all value, R1 = 2444.44 N R2 = -444.44 N In Figure 3(a), the free-body diagram for the section 0 < x < a is given. The moments must be developed for each cross section. Figure 3(b) and Figure 3(c) show the free-body diagram for the sections given by a < x < b and b < x < L, respectively.
PREPARED BY: R & D TEAM
BRAINSTORMING
DATE: 30/11/2016
The equations for equilibrium can be written for each free-body diagram to determine shear force V (x) and moment M(x) on each section. For brevity, only the results for M(x) are given here as
Where each Mi(x) equation is valid only for the range given in the accompanying free-body diagrams. Young’s modulus, E, is taken as 207000MPa. The moments can be integrated to yield slope and deflection equations. The integration results are summarized here. For 0 < x < a,
For a < x < b
For b < x < L
Substituting x = 0 clearly yields EI1*v1(0) = C2. But, v1(0) = 0, so C2 = 0. The other five conditions can be obtained by applying boundary condition on above equation. This is written in matrix form as
PREPARED BY: R & D TEAM
BRAINSTORMING
DATE: 30/11/2016
Where α2 = I2/I1 and α3 = I3/I1. By solving this matrix, it gives five constant as C1 = -11634308.6608796 C2 = 0 C3 = -7700776.70431813 C4 = -5471341563.78601 C5 = -20854430.1380887 C6 = -275423104.52675 By putting all value in deflection equation, it gives segment wise deflection. Deflection graph is plot as
PREPARED BY: R & D TEAM
BRAINSTORMING
DATE: 30/11/2016
Deflection 0.1
0.09
0.08
0.07
) m 0.06 m ( n o0.05 i t c e l f 0.04 e D 0.03
0.02
0.01
0 0
50
100
150
200
250
300
350
400
450
Distance (mm)
From above graph, Y = 0.0918 mm at X = 100 mm
Find Shaft Deflection with help of KISSsoft. Make same shaft on KISSsoft and apply same boundary condition and forces to shaft And take 18CrNiMo7-6 material for calculation because for 18CrNiMo7-6, value of young’s modulus, E is 206000MPa.
PREPARED BY: R & D TEAM
500
BRAINSTORMING
DATE: 30/11/2016
By Solving this problem with KISSsoft , deflection graph as
From above graph, Y = 0.0947 mm at X = 100 mm
PREPARED BY: R & D TEAM
BRAINSTORMING
DATE: 30/11/2016
Conclusion From above exercise, we conclude that deflection by analytical method and deflection by KISSsoft is almost same…….. So, that we can take KISSsoft result as final result for shaft deflection in industrial practice.
