Treatment of Coriolis force, which a Foucault pendulum is designed to measure. A heavy analysis is carried out right to the end, and Taylor expansion is the very last step.Descripción completa
Lab Report on the Inertia Wheel, for an AP Calculus-Based Mechanics Course
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Bug magazine No 275
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Mamma Mia
it tracks all the bugs and generates a report of all the bugs
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The Jazz Improvisation concept of side slipping allows for the inclusion of more chromaticism into ones solos through a melodic application of a commonly applied technique when a rhythm sect…Full description
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bradley j. nartowt Saturday, July 06, 2013, 12:20:04
PHYS 6246 – classical mechanics Dr. Whiting Whiting
a wagon-wheel with spokes is mounted on a vertical-axis, so it is free to rotate in the horizontal plane. A bug crawls out on one of the spokes of the wheel.
[I.1]
The wheel is rotating with an angular speed of 3.0 rad -velocity is 0.5 cm s . The bug’s crawl -velocity s . There is a coefficient of static friction friction 0.30 between bug and spoke. How far can the bug crawl along the spoke before it starts to slip? In cylindrical coordinates, we have a force-balance in the r-direction.
m r g ( r) r g r 2
F
ˆ
ˆ
[I.2]
The coriolis force is due to the bug velocity and the wheel rotation —we rotation —we neglect neglect earth’s earth’s coriolis force because because it is about
3 2 parts in 86400 compared to the angular velocity if the wheel. The coriolis force is in the cylindrical-direction, ˆ
Fcor
2 v r 2 v r 2v ˆ
ˆ
[I.3]
The is there because we don’t know if the wheel is rotating clockwise or counterclockwise. The resultant force is given by the Pythagorean Pythagorean resultant. The bug does does not slip up until the radius,
g
2
2
4 2
4 v r r
2 g 2 4 2 v 2 4
(0.3 981 scm2 ) 2 4(3.0 r sad ) 2 (0.5 csm ) 2 (3.0 rad )4 s
