ReVISIOn
Example
3.0
Crane
Crane 12 to
12 to
5.0
Coil
30 ton
3.0 5.0
1m
l.9
1/11
Solution
ea Load Load
Live Live Load Load
Late Latera ra Shoc Shoc
dl
ton /6
.2
.2
/6
=1.2
R;
ton .6 ton
Pd
21.2 ton
.6 ton
ton
3 . 4 2 ton
?1l1
Re\ISlOn
Hz
member in
26mt '3
ColI 4ton~ BM
NFD
3.2 mt
1. to
ou plan
1/11
9 t
y =
Mx=26mt
Assume = = 1 . t/crrr' Choose B.F.I.B
cnr'
==
M,
Check:
t~
My=
Lbin Lbout
==
A m = = L b x / r x = 1600117.1 Aout=Lby/ry=800/7.41 A.max == 7500 (107.9)2 9/198
s,
Fbx
m'
12880 = =
Lumax
Luact mp
F2
-M
==
~Fy)
(2
'II »)
10.9 mp Ms
Mb .4
Fltb
Applying interactio
equation
.07
0.71
1.2
/n
1M,
=20mt 16
Lbin
8.0
Lbout
1600 17.1 800 7.41
bx
Aout
107.9
My
180
Amax=
.643 t/cnr' 75001 (107.9)2 .151 t/cm 30/198
1 -
Fca/Fc==.235>.15 Crux
Fc ex
Al
.151 7500
7500
"!vx
93.5
.858
1.031 my
frame prevented with
Fca=.15I ey 7500 j)\ ..
Az
1.3
Fbx
M,
Fby
Sx
2000 12880
Sy
320
721
cm
bcy
0.7 0.44
7500 1107.9
cm cnr'
Fb
cm
Luact
1\f2.4
M, -M
4x IS ec Msmall
Mt,ig
Sx
-0.15
0.7
387
0.55 -0.85
Sx
1.35
((~Fy)
(2
£'
90.8
800
.643
1.75 Fltb
bc
800 Af 1.4
75
1.4
cm
Applying interactio .235
3.15
1.03 x.
11.4
equation 0.445/1.4
1.16
h/11
ReVlSlOn
En gabl
olumn.
9.2
Own
1.
kg/m'.
11
20 kg/m'.
lll.
In
1.
(C,
q)
it
Sj
Hz Bl"'Qdng
0.8 for
2- Th strainin
actions:
Wx
'Wine!
1x
il~1
10m
Loa.e!
c:=[::>
0.336 tim' 3.
S, 6x
x6
of
M,
1.31 to x= I.
29 crrr
40
Check:
Lbin
7111
Lbout 9.2 Lby
Aout
Lbx
fy r,
Am.ax
12.69 920 19.97
Fe 10- (93)2 Fca= 1.31/39.1
AI =1.0
Fca/Fe=.043<.15
FbI:
M,
S,
.8 tJcm
cm
355/324
Luact
Lumax
Sectio is on compac
slender
F,
Dw
M,
Sx
-.033
0.98) 10.62
1--,)
1.09
20
12/--,)2.4
1.057
32.38
(190
( (- -,)Fy
(2
115.3
Se
Fltb
800 Af Cj, (L
ApplYing interactio .043
11.4
d)
800
equation 0.82
12
0.98
24)
Re\lSlOn)
of Suctio ni.
In
Wwind= (C,
IV.
q)
fo
Wx
SI
10
Wwind Wx
0.25
9.22 /8
y.+X
b. N=
We
(SI
Wg
LP.E 240 Check:
Lbin
Loom
Aout "-max Fe Fe
9.2 by
180 180
fy
1.31/39.1
(93)2 0.83 t/cm'' .033 t/cnr' 1.0
bx
Hz
0.82
cm
S]
Bra~
IS
th Insi
flange
ern "wall height
vl2A
\i
-.033
M,
2=
A - M , / x=
\fI=F /F
=-.92>-1
;/
y)
(2
'P
1.13
Fbcx
1.4
cm
Applving interactio .043
1.4
equation 0.62
10/11
Re\!SlOn
Welded splice
-W
Qact Mmax
6Fbcx
x6 1388 cm Lweld
Lweld
Mmax
Qact I,
1627 cm 0.8 36 12 3110.4 ern" 3110.4 116270 (Iwl Ix) Mmax Mw 1122 cm x-
Lweld
Mflange
~c
~~~5==1"_4I
hI Lweld act
1122 36 mm
(§
31 16 to 16
13.2
11111
ReYlSlon
B-
We
splice 10cm
JMweb
10.8
0.8
Mweb
Qact 1hzweld Properties of
I, Iy
crrr'
0x 12 16.8 10 0.6
0.6 0.6
I v w el d
eld:
28 wtot
10 em
28 10
Ip:: 3551.4
12 cnr' 10 10
2+ .6
0.6) 0.6 10 0.6
28 (28
0.3) 128.8
0.6 0.6 )2
on cr tica
3551.48 ern" 0.6
)2
.1
Mweb
Mweb
Chec
28
2.5 em
Qa
b)
ints 90.3 cm 290.3
Qactl
.5
11111
RC\lSlOn
IIp R,
Qact
0+145x(14)/3848.11=0.52t/cm XI II
Awvl
,j (0.18
=."j
0 + M,
1.51
13848.11
0.5i)
0.72 t/cm
4+ =0.30t/cm2
8.1/3848.11
=."j In
safe
,j
0.63 in
.7 t/cm
safe
weld
1~11~
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;.,.;t· (sIde.
\.-\_)~y\ ~,("~-MQ.(j
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C4Je
'4=-
(0<)
1.
Design
typica
3.
econdary beam if th li
ta
IS
/m
beam
ti
I:
In
1. la (scale
te ws
6x2=12m load.
3.
De ig suitable ecti ns fo th differen vertical bracin members.
---""
-.
...•... ..........._