Unix DTOe Code

1. Write a Bourn shell script dTOe which takes as an input any number between 0 and 999 and prints the English value for this number. The program should display an error message when a NOT digit value entered. ANSWER CODE:

#!/bin/bash # FILE NAME: dTOe.sh clear # Three different arrays are defined here with the values stored in them. UNITARRAY=(ONE TWO THREE FOUR FIVE SIX SEVEN EIGHT NINE TEN) ELEARRAY=(ELEVEN TWELEVE THIREEN FOURTEEN FIFTEEN SIXTEEN SEVENTEEN EIGHTEEN NINETEEN) TYSARRAY=(TEN TWENTY THIRTY FOURTY FIFTY SIXTY SEVENTY EIGHTY NINTY)

#Varibles declared as null. num="" count="" words=""

#Prompting user to give input echo "Enter the number you want to Print in words" read num # user has to give input

#checks if the input number is greater than 0 and less than or equal to 999 if [[ "$num" -ge 0 ]] && [[ "$num" -le 999 ]] then #checks if the number is 0, then Print in words. if [[ "$num" -eq 0 ]] then echo "ZERO" fi

# checks if the number is greater than 100. if [[ "$num" -ge 100 ]] then count=`expr $num / 100` num2=`expr $num % 100` words="${UNITARRAY[$count - 1]} "HUNDRED"" if [[ "$num2" -gt 0 ]] then words="$words AND" fi num=$num2 fi # checks for the condition if number is greater than 10 & less than 20. if [[ "$num" -gt 10 ]] && [[ "$num" -lt 20 ]] then count2=`expr $num % 10` index2=`expr $count2 - 1` words="$words ${ELEARRAY[$index2]}"

# checks for the condition if the number is greater than 19 elif [[ "$num" -gt 19 ]] then count3=`expr $num / 10` num3=`expr $num % 10` index3=`expr $count3 - 1` words="$words ${TYSARRAY[$index3]}" num=$num3 fi

# checks for the condition if the number is equal or greater than 0 if [[ "$num" -gt 0 ]] then words="$words ${UNITARRAY[$num - 1]}" fi echo "$words" else echo "Please enter numbers from 0 to 999 only. Try again." Fi