MMAN1300 Shear Force and Bending Moment Laboratory Experiment for Statics
Shear and Moment Diagrams
its free
Flare analysisDescripción completa
bending moment experiment
Full description
shear force full reportFull description
some useful formula regarding beams and different cases of loads and support conditions.
Mechanic Report
Steel Design, flexural members
Simplified Assessment of Bending Moment CapacityFull description
Shear Force in a Beam
PROBLEM DEFENITION A Barge of dimension 150m × 30m × 20m and thickness 5mm is loaded as given in diagram Calculate the shear force diagram for this loading.arrangement
Given data 3
density of barge material = 7800 kg/m 3
density of cargo = 2400 kg/m
4M 2M
1M 1M
4M
LOADED AREA
Assumptions 1) Every region in the barge can be treated as a cantilever beam 2) All forces acting upwards(including shear force) are treated as positive and all acting down as negative . 3) The partitions for different regions are dimensionless.
SOLUTION SET Weight of empty barge = volume of barge × density of barge material = ( 150 × 30 × 20 - 149.95 × 29.95 × 19.95) × 7800 × 9.81 = 30.952 MN Weight of empty barge /unit length =
0.2603 MN/metre run
weight of cargo material = 29.95 × 29.95 × (4+2+1+4+2) × 2400 × 9.81 = 274.547 MN/m
Total weight weight of ship = 274.547 + 30.952 = 305.499 MN
(which is is nothing but equal to buoyant force)
Buoyant force acting per unit length = 2.03666 MN/ metre run
Calculation of loading at various regions Divide the different loading parts into five regions as shown below.
REGION 1
REGION 2
Weight of ship(empty)
REGION 3
weight of cargo
REGION 4
buoyant force
All forces per unit metre length(in MN)
Region 1 Region 2 Region 3 Region 4 Region 5
-0.2603 -0.2603 -0.2603 -0.2603 -0.2603
-2.80648 -1.40323 -0.70162 -2.80648 -1.40323
2.03666 2.03666 2.03666 2.03666 2.03666
REGION 5
REGION 1 load = weight of empty ship +weight of cargo - buoyant force
wx
V = 0.9857x At x= 30m , V = 29.571 MN
x
V
REGION 2
29.571
wx x
V
V = 29.571-0.4224x At x= 30m , V = 16.899MN
wx 16.8909
x
REGION 3
V
16.899
V = 16.899-1.12633 At x= 30m , V = -16.8909 MN
wx x
REGION 4
V
V = -16.8909+.9857x At x= 30 , V =12.6801 MN
wx
12.6801
REGION 5
x
V
V = 12.6801-0.4224x At x= 30m ,
Length(m) Shear force(MN)
V = 0.0129 MN
0
30
60
90
12 0
150
0
2 9 .5 7 1
1 6 .8 9 9
- 1 6 .8 9 0 9
1 2 .6 8 0 1
0 .0 1 2 9
1
4 5
2
3
Effect of shear force on different sections. sections.
