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Mechanics...
Author:
mogoric
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Q1 (a)
Point C is the instantaneous center of rotation (b)~(d) ππ
ππ
Μ Μ Μ Μ = 6 β 150 = 900 ππ· = Οπ΅π· β π·πΆ (β) π ππ
ππ΅ = 75 β 16 = 1200 π ππ (β) π
1200
π΅πΆ
200
Οπ΅π· = Μ Μ Μ π΅Μ =
=6
πππ π ππ
Μ Μ Μ Μ = 6 β 125 (βπ ππ Ξ² π β cos Ξ²π) = 750 (βπ ππ Ξ² π β cos Ξ²π) ππ ββββ ππΊ = Οπ΅π· β πΊπΆ π ππ
π½ = πππ β1
100 = 36.87Β° = 0.643 πππ 125
(e) ππ
ππ΅ = β75 β Οπ΄π΅ 2 = β 19200 π ππ 2 π ββββ (f) ππ· = ββββ ββββ ππ΅ + ββββββββββββ π(π·β ) π΅
= ββββ ππ΅ + (π ββββββββββββ ββββββββββββ (π·β ) )π‘ + (π (π·β ) )π π΅
π΅
=π ββββπ΅ (β) + Μ Μ Μ Μ π΅π· πΌ(βπ πππ½ π + πππ π½π) + π΅π· β Οπ΅π· 2 β (βπππ π½ π β π πππ½π)
ππ· = ππ· π + 0π = β19200π + Μ Μ Μ Μ ββββ π΅π· πΌ(βπ πππ½ π + πππ π½π) + π΅π· β Οπ΅π· 2 β (βπππ π½ π β π πππ½π) Μ Μ Μ Μ π΅π· πΌπππ π½ β Μ Μ Μ Μ π΅π· Οπ΅π· 2 π πππ½ = 0 β πΌ = 26.97
πππ π ππ 2
Μ Μ Μ Μ πΌπ πππ½ β π΅π· Μ Μ Μ Μ Οπ΅π· 2 πππ π½ = β30445.50 ππ· = β19200 β π΅π·
ππ π ππ 2
Μ Μ Μ Μ πΌ(βπ πππ½ π + πππ π½π) + π΅πΊ Μ Μ Μ Μ βββββββββ (g) βββ ππΊ = βββ ππ΅ + (π ββββββββββ ββββββββββ ππ΅ + π΅πΊ Οπ΅π· (βπππ π½ π + π πππ½π) (πΊβ ) ) + (π (πΊβ ) ) = βββ π΅
π‘
π΅
π
ππ Μ Μ Μ Μ πΌ π πππ½ β π΅πΊ Μ Μ Μ Μ Οπ΅π· πππ π½ β π΅πΊ π ππ 2 ππ = β19200 β 2021.398 β 600.225 = β21821.623 π ππ 2
ββββ πΆππππππππ‘π : (ππΊ )π₯ = β19200 +
Μ Μ Μ Μ πΌ πππ π½ + π΅πΊ Μ Μ Μ Μ Οπ΅π· π πππ½ = 2698.1 + 449.70 = 3147.799 β + πΆππππππππ‘π : (ππΊ )π¦ = π΅πΊ ππΊ = 22047.491
ππ π ππ 2
ππ π ππ 2
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