Programs of c++ for class 12 cbse

ARRAYS Q1. Write a program to illustrate the two types of searches in an integer type array. Make use of functions and make a menu driven program.

#include #include #include int Lsearch(int[],int,int); int Bsearch(int[],int,int); int main() { char ch1; int ch; int AR[50],i,item,N,index; do { clrscr(); cout<<"\n"<<"S E A R C H

M E N U";

cout<<"\n1. Linear Search"; cout<<"\n2. Binary Search"; cout<<"\n3. Exit"<<"\n"; cout<<" Enter your choice (1,2 or 3): "; cin>>ch; if( ch==1|| ch==2)

{ cout<< "Enter desired array size(max.50).....:"; cin>>N; } switch(ch) { case 1 :cout<<"\nEnter array elements:\n"; for(i=0;i>AR[i];} cout<<"\nEnter element to be searched for........:\n"; cin>>item; index=Lsearch(AR,N,item); if(index== -1) cout<<"\n*^*^* Sorry!! Given element could not be found *^*^*\n"; else cout<<"\nElement found at index : "<
case 2 : cout<<"\nEnter array elements(must be sorted in asc order) :\n"; for(i=0;i>AR[i]; cout<<"\nEnter element to be searched for........:"; cin>>item; index=Bsearch(AR,N,item); if(index== -1)

cout<<"\n*^*^* Sorry!! Given element could not be found *^*^*\n"; else cout<<"\nElement found at index : "<
case 3 :break ; default : cout<<"!!!!!!Wrong choice!!!!!!!\n"; break ; } cout<<"\nPress a key to continue......\n"; ch1 = getchar() ; } while(ch>=1 && ch<=2); return 0 ; } int Lsearch(int AR[],int size,int item) { for (int i=0;i
return i;

} return -1; } int Bsearch(int AR[],int size,int item) {int beg,last,mid;

beg=0;

last=size-1;

while(beg<=last) { mid=(beg+last)/2; if (item==AR[mid])

return mid;

else if (item >AR[mid])

beg=mid+1;

else last = mid-1; } return -1;

OUTPUT S E A R C H

M E N U

1.

Linear Search

2.

Binary search

3.

Exit

Enter your choice: 1 Enter desired array size (max.50)……: 3 Enter array elements : 1 4 6 Enter elements to be searched for ………..: 4

Element found at index : 1, Position: 2 Press a key to continue…….

Q2. Write a program to illustrate deletion (with position) in an array (the position can be the beginning or the end or in middle anywhere at a specified place, so all the cases should be handled). Write functions for all three separately. And make the program menu driven and user friendly. #include #include #include int size,a,ch,AR[50]; char ans; void delbeg(int AR[],int size) {for(int i=1;i
void dellast(int AR[],int size) {size=size-1; cout<<"\n The array after making changes"<
for(int i=0;i
void delany(int AR[],int size,int P) {for(int i=P;i>size; cout<<"Enter the elements of the array"; for(int i=0;i>AR[i]; { do {cout<<"Element to be deleted"<
cin>>ch; switch(ch) {case 1:delbeg(AR,size);

break; case 2:size=size-1; dellast(AR,size); break; case 3:cout<<"Enter the position of the element"; cin>>a; delany(AR,size,a); break; default:cout<<"Invalid choice"<>ans;} while(ans=='y');getch(); }}

OUTPUT: Enter the size of the array 4 Enter the elements of the array 1

2

3

4

Element to be deleted

1.From beginning 2.From end 3.From anywhere Enter your choice 1 The array after making changes 2

3

4

Want to continue?(y/n) N Q3. Write a program to illustrate all the three sorts – Insertion, Selection and Bubble sort in an array. Make use of functions to do the same. Make a menu driven and user friendly program.*/ #include #include void selectionSort(int Array[10]); int bubblesort(int array[10]); void insertion_sort(int x[],int length); void main() { clrscr(); int a[10]; cout<<"Enter the numbers in the array:"; for(int i=0;i<10;i++) { cin>>a[i]; } int ch;

do {cout<<"\nMENU" <<"\n1.selection sort" <<"\n2.insertion sort" <<"\n3.bubble sort" <<"\n4.exit\n" ; <<"\nenter your choice(1-4):"; cin>>ch; switch(ch) {case 1: selectionSort(a); break; case 2: bubblesort(a); break; case 3: insertion_sort(a,10); break; } }while(ch<4); getch(); } void selectionSort(int A[10]) { int i, j, min, min1; for(i = 0; i<10; i++) {

min1 = i;

min = A[i];

for(j = i+1;j<10;j++) { {

if(min > A[j]) min1 = j;

min = A[j]; } } int temp = A[i]; A[i] = A[min1]; A[min1]=temp; } cout<<"Array After selection Sorting is:"<
} int bubblesort(int array[10]) { int len=10; int temp; for(int i=1;iarray[j+1] && (j+1)
// then swap

{ temp=array[j]; array[j]=array[j+1]; array[j+1]=temp; } }

}

cout<<"Array After Bubble Sorting is(ascending order):"<key && i>=0) { x[i+1]=x[i];

i--; } x[i+1]=key; } cout<
OUTPUT Enter number:1 9 7 5 0 2 4 6 3 8 MENU 1.

selection sort

2.

insertion sort

3.

bubble sort

4.

exit

enter your choice(1-4):1 array after selection sorting is : 0 1 2 3 4 5 6 7 8 9 MENU 1.

selection sort

2.

insertion sort

3.

bubble sort

4.

exit

enter your choice(1-4):2 array after bubble sorting is(ascending order) : 0 1 2 3 4 5 6 7 8 9

MENU 1.

selection sort

2.

insertion sort

3.

bubble sort

4.

exit

enter your choice(1-4):3 array after insertion sort is : 0 1 2

3 4 5 6 7 8 9 MENU 1.

selection sort

2.

insertion sort

3.

bubble sort

4.

exit

enter your choice(1-4):4

Q4. Write a program to sum the elements above and below the main diagonal of a matrix.*/

#include #include void main() { char ch; do { clrscr();

int a[20][20], i, j, m, n , csum, dsum; //Input rows and column of Matrix A\n"; cout<<"\n Input row and column of Matrix A\n"; cin>>m>>n; cout<<"\n Input Matrix A\n"; for(i=0;i>a[i][j]; } cout<<"\n Matrix A \n";

// Display Matrix-A\par

for(i=0;i
elements above the main diagonal\par

for(i=0;i
cout<j) dsum+=a[i][j]; } } cout<<"\n Below the main digonal is:"; cout<>ch; }while((ch=='y')||(ch=='Y')); getch(); } //end of main

OUTPUT Input row and column of Matrix-A 2 3 Input Matrix-A 1 2 3

4 5 6 Matrix A 1 2 3 4 5 6 Sum of elements Above the main diagonal is:11 Below the main diagonal is:4 Want to continue(y/n)? : n Q5. Write a program to merge two given arrays into the third array C. Use switch case and implement the same with at least 4 different combinations. Make use of functions. #include #include #include

//FUNCTION TO MERGE IF ONE IS ASCENDING AND ONE IS DESCENDING void merge(int[],int,int[],int); //FUNCTION TO MERGE IF BOTH IS ASCENDING void merge1(int[],int,int[],int); //FUNCTION TO MERGE IF BOTH IS DESCENDING void merge2(int[],int,int[],int);

int f_asc(int a[]) { int M; cout<<"How many elements do u want to enter in the first array?[ascending]\n"; cin>>M ; cout<<"\nEnter first arrays element..\n"; for(int i=0;i>a[i]; return M; }

int f_desc(int a[]) { int M; cout<<"How many elements do u want to enter in the first array?[descending]\n"; cin>>M; cout<<"\nEnter first arrays element..\n"; for(int i=0;i>a[i]; return M; } int s_asc(int a[]) { int M;

cout<<"How many elements do u want to enter in the second array?[ascending]\n"; cin>>M ; cout<<"\nEnter second arrays element..\n"; for(int i=0;i>a[i]; return M; } int s_desc(int a[]) { int M; cout<<"How many elements do u want to enter in the second array?[descending]\n"; cin>>M ; cout<<"\nEnter second arrays element..\n"; for(int i=0;i>a[i]; return M; } void main() { int a[50], b[50], M, N, choice; menu:; clrscr(); cout<<"\nMERGING ARRAYS\n"; cout<<"1. Both Arrays Ascending\n";

cout<<"2. Both Arrays Descending\n"; cout<<"3. Fisrt Ascending, Second Descending\n"; cout<<"4. Fisrt Descending, Second Ascending\n"; cout<<"0. Exit\n"; cout<<"Enter your choice:\t"; cin>>choice; switch(choice) { case 1 : M=f_asc(a); N=s_asc(b); merge1(a,M,b,N); break;

case 2 : M=f_desc(a); N=s_desc(b); merge2(a,M,b,N); break; case 3 : M=f_asc(a); N=s_desc(b); merge(a,M,b,N); break;

case 4 : M=f_desc(a); N=s_asc(b); merge(b,N,a,M);

//SWITCHES CASE AS PER USERS CHOICE

break;

case 0 : exit(0);

default : cout<<"Wrong Choice!!\n"; getch(); break; }; goto menu; }

void merge(int A[],int M, int B[],int N) { int C[50],MN=M+N; int a,b,c,i; for(a=0,b=N-1,c= 0;a=0;) { if(A[a]<=B[b]) C[c++] = A[a++]; else C[c++] = B[b--]; } if(a
} else { while(b>=0) C[c++] = B[b--]; } cout<<"\n\nThe merged array is as shown \n"; for(i=0;i
} else { while(b=0 && b>=0;) { if(A[a]<=B[b]) C[c++] = A[a--]; else C[c++] = B[b--]; } if(a>=0) {while(a>=0) C[c++] = A[a--];

} else { while(b>=0) C[c++] = B[b--]; } cout<<"\n\nThe merged array is as shown \n"; for(i=0;i
OUTPUT MERGING ARRAYS 1.

Both Arrays Ascending

2.

Both Arrays Descending

3.

First Ascending, Second Descending

4.

First descending, second ascending

0.

Exit

Enter your choice : 1 How many elements do you want to enter in the first array? [ascending] 5 Enter first arrays element..

1 3 5 7 9 How many elements do you want to enter in the second array? [ascending] 5 Enter second arrays element.. 2 4 6 8 10 The merged array is as shown 1 2 3 4 5 6 7 8 9 10

MERGING ARRAYS 5.

Both Arrays Ascending

6.

Both Arrays Descending

7.

First Ascending, Second Descending

8.

First descending, second ascending

1.

Exit

Enter your choice : 0

Q6. Write a program to illustrate insertion (with position) in an array( the position can be the beginning or the end or in middle anywhere at a specified place)(all three cases are to be handled).Write functions for all three separately. And make the program menu driven and user friendly.*/

#include #include #include

int FindPos(int[], int, int);

void main() { char s; do { int AR[50], ITEM, N, index; //array can hold maximum 50 elements clrscr(); cout<<"How many elements do you want?(max. 50)..."; cin>>N; cout<<"\nEnter Array elements (in increasing order)\n"; for(int i=0; i>AR[i]; char ch='y'; while((ch=='y')||(ch=='Y')) { cout<<"\nEnter Element to be inserted..."; cin>>ITEM;

if(N==50) { cout<<"Overflow!!"; exit(1); } index=FindPos(AR, N, ITEM); for(i=N; i>index; i--) AR[i]=AR[i-1]; AR[index]=ITEM; N+=1; //Number of elements updated cout<<"\n Want to insert more elements? (y/n): "; cin>>ch; } cout<<"\nThe array is now as shown below.....\n"; for(i=0;i
";

cout<>s; }while((s=='y')||(s=='Y')); getch(); }

int FindPos(int AR[], int size, int item) determine the position for new element { int pos;

//function to

if(item
if(AR[i]<=item && item
{ pos=i+1; break; } } if(i==size-1) pos=size; } return pos; }

OUTPUT How

many elements do you want?
Enter Array elements

50>. . .3

1 6 9 Enter Element to be inserted. . .5 Want to insert more elements?

:

y

Enter Element to be inserted. . .8 Want to insert more elements? The array is now 1

5

:

n

as shown below . . . .

6

8

9

Want to continue with new array ?

:

n

Q7. Write a program to wap in c++ to implement stack as an array.


int pop(int[],int&); int push(int[],int&,int); void display(int[],int);

const int size=50;

void main() { clrscr(); char m,ch; int k,stack[size],item,top=-1,res; do

{

cout<<"\nChoose from the following : \n\n" <<"\n 1. Push" <<"\n 2. Pop" <<"\n 3. Display" <<"\n 4. Exit" <<"\n\nEnter your choice : ";

cin>>k;

switch(k) { case 1: ch='y'; while(ch=='y'||ch=='Y') {

cout<<"\nEnter the element : ";

cin>>item; res=push(stack,top,item); if(res==-1) {cout<<"\nOverflow !!!!"; exit(1); } cout<<"\nThe stack formed is : \n\n"; display(stack,top); cout<<"\n\n\nWant to enter again ?: "; cin>>ch; } break;

case 2: ch='y';

while(ch=='y'||ch=='Y') { res=pop(stack,top); if(res==-1) { cout<<"\nUnderflow !!!!"; exit(1); } else { cout<<"\nThe deleted Element is : "<>ch; } break;

case 3: cout<<"\nThe resultant stack is

: ";

display(stack,top); break;

case 4: exit(0); break;

default: cout<<"\nPlease enter desired keyword : ";

}

// end of switch

cout<<"\n\nChoose from the menu again ? : "; cin>>m;

}while(m=='y'||m=='Y');

// end of do-while

loop getch(); }

// end of main()

int push(int stack[],int &top,int el) { if(top==size-1) return -1; else { top++; stack[top]=el; return 0; } }

int pop(int stack[],int &top) { int ret;

if(top==-1) return -1; else { ret=stack[top]; top--; return ret; } }

void display(int stack[],int top) { cout<=0;i--) cout<
Output:

Choose from the following : 1. Push 2. Pop 3. Display 4. Exit


Enter the element : 1 The stack formed is :

Want to enter again ?: y






Want to enter again ?: N

Choose from the menu again ? : y


Enter your choice : 2 The deleted Element is : 4 The resultant stack is :

Want to delete again ? : y

The deleted Element is : 3 The resultant stack is :

Want to delete again ? : n

Choose from the menu again ? : y



The resultant stack is

:

2 1 

Choose from the menu again ? : n

CONSTRUCTOR DESTRUCTOR Q1. Write a program using constructor and destructor to find the area of rectangle.

#include using namespace std;

// A class CRectArea with a constructor and descructor // to determine the area of a rectangle. class CRectArea { int *width, *height; public: CRectArea (int,int); ~CRectArea (); int areaofrect () { return (*width * *height); } };

// Constructor CRectArea::CRectArea (int x, int y) {

//Dynamically allocate some memory width = new int;

height = new int;

*width = x; *height = y; }

// Destructor CRectArea::~CRectArea () { //Delete the allocate memory delete width; delete height; }

int main () { CRectArea myrectangle (2,2); cout << “The area of the rectangle is: ” << myrectangle.areaofrect() << endl; return 0; }

Q2.Define a class Outfit in C++ with the following descriptions : Private members :

OCode

Of type string

OType

Of type string

OSize

Of type integer

OFabric

Of type string

OPrice

Of type float

A function InitPrice( ) which calculates and assigns the values of OPrice as follows : For the value of OFabric “DENIM”, OType

OPrice(Rs)

TROUSER

1500

JACKET

2500

For fabric other than “DENIM” the above mentioned OPrice gets reduced by 25%.

Public members: • A constructor to assign initial values of OCode, OType and OFabric with the word “NOT INITIALISED” and OSize and OPrice with 0. • A function Input ( ) to input the values of the data members OCode, OType, OSize and OFabric and invoke the InitPrice( ) function. • A function Display ( ) which displays the content of all the data members for an Outfit.

#include #include #include #include class Outfit { private: char OCode[20]; char OType[20]; char OFabric[20]; int OSize; float OPrice; void InitPrice() {if((strcmp(OFabric,"DENIM")==0)||(strcmp(OFabric,"denim")== 0)) { if((strcmp(OType,"TROUSER")==0)||(strcmp(OType,"trouser")==0 )) OPrice=1500; else if ((strcmp(OType,"JACKET")==0)||(strcmp(OType,"jacket")==0)) OPrice=2500; }

else

{ if((strcmp(OType,"TROUSER")==0)||(strcmp(OType,"trouser")==0 )) OPrice=1500-0.25*1500; else if((strcmp(OType,"JACKET")==0)||(strcmp(OType,"jacket")==0)) OPrice=2500-0.25*250; } }

public: Outfit() { strcpy(OCode,"NOT INITIALISED"); strcpy(OType,"NOT INTIIALISED"); strcpy(OFabric,"NOT INTIALISED"); OSize=0; OPrice=0; } void Input() {

cout<<"\n Enter Outfit Code :";

cin>>OCode; cout<<"\n Enter Outfit type :"; cin>>OType; cout<<"\n Enter Outfit Fabric :"; gets(OFabric);

cout<<"\n Enter Outfit Size :"; cin>>OSize; InitPrice(); } void Display() { cout<<"\n outfit code :"<
OUTPUT:

Enter Outfit Code: 34 Enter Output type: trouser

Enter Output Fabric: DENIM

Enter Output Size: 40

Outfit code: 34 Outfit type: trouser Outfit size: 40 Outfit price: 1500 Output fabric : DENIM

Q3. Program defining a class TravelPlan with the given specifications and testing this class */ #include #include #include class TravelPlan

{ long PlanCode; char Place[25]; int Number_of_travellers; int Number_of_buses; public: TravelPlan()

{ PlanCode=1001; strcpy(Place,"Agra"); Number_of_travellers=5; Number_of_buses=1; } void NewPlan() { cout<<"Enter plancode"; cin>>PlanCode; cout<<"Enter place"; cin>>Place; cout<<"Enter number of travelers"; cin>>Number_of_travellers; int buses=0; if(Number_of_travellers<20) buses=1; else if(Number_of_travellers<40) buses=2; else if(Number_of_travellers>40) buses=3; Number_of_buses=buses; } void ShowPlan() { cout<<"Plancode:"<
cout<<"no. of travelers:"<
OUTPUT Enter plancode 1234 Enter place delhi Enter number of travelers 10 Plancode : 1234 Place :delhi No. of travelers : 10 No of buses :1

Q3. Write a program to print student details using constructors and destructors.

#include #include class stu { private: char name[20],add[20]; int roll,zip; public: stu ( );//Constructor ~stu( );//Destructor void read( ); void disp( ); }; stu :: stu( ) { cout<<”This is Student Details”<>name; cout<<”Enter the student roll no “; cin>>roll;

cout<<”Enter the student address”; cin>>add; cout<<”Enter the Zipcode”; cin>>zip; } void stu :: disp( ) { cout<<”Student Name :”<
is

:”<
cout<<”Address is

:”<
cout<<”Zipcode is

:”<
} stu : : ~stu( ) { cout<<”Student Detail is Closed”; }

void main( ) { stu s; clrscr( ); s.read ( ); s.disp ( ); getch( ); }

OUTPUT-: Enter the student Name James Enter the student roll no 01 Enter the student address Newyork Enter the Zipcode 919108

Student Name : James Roll no is : 01 Address is : Newyork Zipcode is :919108

FUNCTION OVERLOADING Q1. Write a program to calculate the area of circle,rectangle and triangle using function overloading.

#include #include #include #define pi 3.14 class fn { public: void area(int);

//circle

void area(int,int);

//rectangle

void area(float ,int,int);

//triangle

};

void fn::area(int a) {

cout<<"Area of Circle:"<
void fn::area(int a,int b) { cout<<"Area of rectangle:"<
void main() { int ch; int a,b,r; clrscr(); fn obj; cout<<"\n\t\tFunction Overloading"; cout<<"\n1.Area of Circle\n2.Area of Rectangle\n3.Area of Triangle\n4.Exit\n:”; cout<<”Enter your Choice:"; cin>>ch;

switch(ch) { case 1: cout<<"Enter Radious of the Circle:";

cin>>r; obj.area(r); break; case 2: cout<<"Enter Sides of the Rectangle:"; cin>>a>>b; obj.area(a,b); break; case 3: cout<<"Enter Sides of the Triangle:"; cin>>a>>b; obj.area(0.5,a,b); break; case 4: exit(0); } getch(); } Output:

Function Overloading 1. Area of Circle 2. Area of Rectangle 3. Area of Triangle 4. Exit

Enter Your Choice: 2

Enter the Sides of the Rectangle: 5 5

Area of Rectangle is: 25

1. Area of Circle 2. Area of Rectangle 3. Area of Triangle 4. Exit Enter Your Choice: 4

Q2) Program to illustrate working of function overloadind(as compared to default arguments).Calculate interest amount using function overloading. */

#include #include Void amount(float

princ, int

time, float

rate)

{ Cout <<”\nPrincipal Amount:”<
amount(float princ,int time)

{ Cout<<”\nPrincipal Amount:”<
} Int main() { Clrscr(); Cout<<”Case 1”; Amount(2000.0F); Cout<<”Case 2”; Amount(2500.0F,3); Cout<<”Case 3”; Amount(2300.0F,3,0.11F); Cout<<”Case 4”; Amount(2,0.12F); Cout<<”Case 5”; Amount (6,0.07F); Retun 0; }

OUTPUT Case 1 Principal Amount : 2000 Interest Amount : 320

Time : 2 years

Rate : 0.08

Case 2 Principal Amount : 2500 Interest Amount : 600

Time : 3 years

Rate : 0.08


Time : 3 years

Rate : 0.11


Time : 2 years

Rate : 0.12


Time : 6 years

Rate : 0.07

Q3) Write a program to demonstrate how function overloading is carried out for swapping of two variables of the various data types, namely integer, floating point number and character types

#include #include void swap(int &ix,int &iy); void swap(float &fx,float &fy); void swap(char &cx,char &cy); void main() { int ix,iy; float fx,fy; char cx,cy; clrscr(); cout<<"Enter 2 integers:";

cin>>ix>>iy; cout<<"Enter 2 floating point no:s:"; cin>>fx>>fy; cout<<"Enter 2 characters:"; cin>>cx>>cy; cout<<"\nIntegers:"; cout<<"\nix="<
{cin >> ver[i];}cout << "Entered vector :"; cout << endl;for (i=0;i<10;i++){cout << " " << " " << ver[i];}} void vector_ :: modify() {cout << endl << endl << "Enter the index :"; cin >> ind; cout << endl << "Enter the modify value :"; cin >> x; ver[ind] = x; } void vector_ :: displ() { large=ver[0]; for(i=0;i<10;i++) { if(large
} void vector_ :: display() { for (j=0;j<10;j++){cout << " " << " " << ver[j];

} } void main() { vector_ ve; clrscr(); ve.create(); ve.modify(); ve.display(); ve.displ(); getch(); }

OUTPUT: Enter the vector: 1 2 3 4 5 6 7 8 9 7

Entered vector: 1

2

3

4

5

6

7

8

9

7

9

7

Enter the index: 7 Enter the modify value: 1 1

2

3

4

5

6

7

1

Largest value: 9

Q2. Program modelling a ticketselling booth with a class called ticbooth and testing this class.

#include #include class ticbooth {

int people;

float amount; public: ticbooth(); void notsold(); void sold(); void disptotal(); }; ticbooth::ticbooth() { people=amount=0; } void ticbooth::notsold() { people++;

} void ticbooth::sold() { people++; amount+=2.5; } void ticbooth::disptotal() { cout<<"people="<
void main() { clrscr(); ticbooth t1; int i=1,n; char ch; do { cout<<"Person:"<>n; if(n==1) t1.sold(); else if (n==0) t1.notsold(); i++; cout<<"more people???(y/n):"; cin>>ch;

} while (ch=='y'||ch=='Y'); t1.disptotal(); getch(); }

OUTPUT: Person 1: Want ticket?(1 for yes, 0 for no): 1 More people???(y/n): y Person 2: Want ticket?(1 for yes, 0 for no): 1 More people???(y/n): n people=2 amount=5

Q3. Write a program to define the classes PERSON, GAME and STUDENT & to access the essential data using multiple inheritance.*/


class person{ char name[21]; int age; public: void indata() {cout<<"\n\nEnter the name of Student: " ; gets(name); cout<<"\n\nEnter the age : "; cin>>age; } void outdata();

};

void person::outdata() // since the function contains loop so it is not made inline { cout<<"\n\n"; for(int i=0; i<79; i++)

cout<<"-"; cout<<"\n\nName of the student is: "<
}

class game { char game_name[20]; public: void input() { cout<<"\n\nEnter the game name : "; cin.get();cin.getline(game_name,20); } void output() { cout<<"\n\nGame opted by the student is : "<
class student: public person, public game { float Tmarks; int rollno; public:

char calgrade() {if(Tmarks>90) return 'A'; else if(Tmarks>80&&Tmarks<=90) return 'B'; else if(Tmarks>70&&Tmarks<=80) return 'C'; else if(Tmarks>60&&Tmarks<=70) return 'D'; else return 'E'; } void enter() { indata(); // indata() of class person called here

cout<<"\n\nEnter the roll number: "; cin>>rollno;

input(); // input() of class game called here

cout<<"\n\nEnter total marks (out of 100) : "; cin>>Tmarks;

} void display()

{ outdata(); cout<<"\n\nRoll number : "<
{ char c[40]; cout<<"\n\t"; for (i=0;a[i]|='\0';i++) c[i]=a[i]; int k=i; for(i=0;obj2.a[i]|='\0';i++) { c[k]=obj2.a[i]; k++; } c[k]='\0'; cout<<"\n\tConcatenated String is"; for(i=0;c[i]|='\0';i++) cout<
cout<<"This program is meant to accept a string,reverse"; cout<<"it, check if it\n\t is palindrome or not and then display"; cout<<"it in alphabetical order \n\n\t"; cout<<"\n\n\n\tPress any key to continue...."; getch(); clrscr(); cout<<"\n\t"; cout<<"\n\tEnter the string"; x.read(); cout<<"\tEntered string is "; x.display(); x.rev(y); cout<<"\tThe reversed string is"; y.display(); x.copy(y); cout<<"\tThe copied string is:"; y.display(); cout<<"\tEnter the string for concatenation:"; y.read(); x.merge(y); cout<<"\n\n\t\tbye|"; getch(); }

OUTPUT This program is meant to accept a string ,reverse it ,check if it is palindrome or not and then display in alphabetical order Press any key to continue…. Enter the string- peter Enter string is peter The reversed string is retep The entered string- peter The copied string is: Enter the string for concatenation: sarah Concatenated string is petersarah Bye!

Q5. Write a program to create a binary file and write objects of class WORKER to it and display worker details on screen after reading from the binary file. */ #include #include class WORKER { char Wname[20]; int Wno; int HRWK; // Hours work float wgrate; // wage rate float totwage; float calcwage (int HRWK, float wgrate)

{ totwage=HRWK*wgrate; return totwage; } public: WORKER () { Wno=1; wgrate = 500; HRWK =5; } void INDATA(); void OUTDATA(); }; void WORKER::INDATA () { cout<<"\n\n\nEnter Worker's name : "; cin.get(); cin.getline(Wname,80); cout<<"\n\nEnter worker Number : "; cin>>Wno; cout<<"\n\nEnter wage rate of worker : "; cin>>wgrate; cout<<"\n\nEnter hours work : ";

cin>>HRWK; }

void WORKER :: OUTDATA() { cout<<"\n\nWorker's name => "< "<>n; if(n<=0) { cout<<"\n\nEnter again. "; goto l; } WORKER w[80],z[80];

fstream o;

for(int i=0; i
w[i].INDATA(); o.open("www.dat",ios::binary|ios::out); o.write((char*)&w[i],sizeof(w[i])); o.close();

o.open("www.dat",ios::binary|ios::in); o.read((char*)&z[i],sizeof(z[i])); o.close(); }

cout<<"\n\n\n\n--------------------------------------------------- # Worker Details # -------------------------------------------------------"; for(i=0; i
getch(); }

Output:

Enter the total number of workers : 2

Enter Worker's name : Shivam Enter worker Number : 1 Enter wage rate of worker : 120 Enter hours work : 5

Enter Worker's name : Gopal Enter worker Number : 2 Enter wage rate of worker : 150 Enter hours work : 8 --------------------------------------------------------------- # Worker Details # ----------------------------------------------------------------Worker's name => Shivam Worker number => 1 Wage rate = 120 Hours Work = 5 Total Wage = 600 Worker's name => Gopal Worker number => 2 Wage rate = 150 Hours Work = 8 Total Wage = 1200

Q 6. Write a program in c++ to define a class BANK and to perform its basic functions . #include #include #include int n, am; class bank { char name[80]; int acc_no; enum acctype{S,C}; void account_type(int n); float balance; public: float add_bal(float n); float withdrawl (float k); void initial(); void display(); }acc; float bank:: add_bal(float n) { cout<<"\n\nYour balance is : "<>k; goto m; } balance-=k;

return balance; } void bank :: initial() {cout<<"Enter your name : "; cin.getline(name,80); cout<<"\n\nEnter your acc. number : "; cin>>acc_no; l:cout<<"\n\nEnter your acc. type (S/N) -> '1 for S' and '2 for N' : "; cin>>n; if(n==1||n==2) {} else goto l; m:cout<<"\n\nEnter your acc. balance : "; cin>>balance; if(balance<1000) { cout<<"\n\nInitial balance cannot be less than 1000.\n\n"; goto m; } } void bank :: account_type(int n) { switch(n) { case S+1 : cout<<" Saving account."; break; case C+1 : cout<<" Current account."; break; } } void bank::display() { cout<<"\n\nName of the account holder => "<
cout<<"\n\nAccount number => "< ";account_type(n); cout<<"\n\nBalance in account = "<>ch; switch(ch) { case 1: cout<<"\n\n\t\t Enter the amount to be deposited : "; cin>>am; cout<<"\n\nNow balance is : " <>am; cout<<"\n\nNow balance is : " <
} cout<<"\n\n\n\n\nWant to chose again : "; cin>>choice; } while(choice=='y'||choice=='Y'); getch(); }//end of main Output: Enter your name : Rahul Verma Enter your acc. number : 20073312 Enter your acc. type (S/N) -> '1 for S' and '2 for N' : 1 Enter your acc. balance : 5000

What do you want to do : 1. Add balance 2. Withdraw balance 3. Display account details and its status 4. Exit Enter your choice : 1

Enter the amount to be deposited : 5000 Your balance is : 5000 Now balance is : 10000

Want to chose again : y

1. Add balance 2. Withdraw balance 3. Display account details and its status 4. Exit Enter your choice : 2

Enter the amount to be withdrawn : 9500

Your balance is : 10000

Unable to withdraw money, as minimum of Rs. 1000 has to be in account. Enter the amount to be withdrawn : 6000

Your balance is : 10000 Now balance is : 4000

Want to chose again : y

1. Add balance 2. Withdraw balance 3. Display account details and its status 4. Exit Enter your choice : 3

--------------------------------------------------------------- # Account Details # --------------------------------------------------------Name of the account holder => Rahul Verma Account number => 19296 Account type => Saving account. Balance in account = 4000

Want to chose again :y 1. Add balance 2. Withdraw balance 3. Display account details and its status 4. Exit Enter your choice : 4

Programs of c++ for class 12 cbse

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