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Problem: [ChE Boards April 2014] From sugar cane, ethanol is commercially produced at a rate of 100000 L/day (99.5% v/v). From here, fermentation occurs occurs at a r ate of 0.511 kg ethanol per kilogram of fermentable sugar. If the syrup is 53% f ermentable ermentable sugar and cane juice is 25% syrup with distillation and fermentation being 99% and 90% efficient, respectively, calculate the following: 1.
mass flowrate of the ethanol solution produced a. 176.32 MT/day b. 1302.54 MT/day
2.
mass flowrate of the syrup entering the fermenter a. 176.32 MT/day b. 1302.54 MT/day
3.
c. 322.38 MT/day d. 78.58 MT/day
c. 322.38 MT/day d. 78.58 MT/day
mass flowrate of the cane juice feed a. 176.32 MT/day b. 1302.54 MT/day
c. 322.38 MT/day d. 78.58 MT/day
Solution:
Density of H2O = 997.042 kg/m 3 Density of ethanol = 784.718 kg/m 3
’
(Perry s 8e, Table 2-30, p. 2-96) (Perry s 8e, Table 2-32, p. 2-98) ’
Density of ethanol soln. = 0.995(784.718) + 0.005(997.042) = 785.780 kg/m 3 1.
soln. ) 1 m (785.780 kg) ( 1 MT ) = 78. (100000 L1ethanol MT/dayay day 1000 L 1 m 1000 kg 78.58 MT/d 2.
soln. ) (1 kg fermentable sugar ) (100 kg theo. prodn. ) ( 100 kg syrup )=322.38 MT/day (78.58 MT1ethanol day 0.511 kg ethanol soln. 90 kg actual prodn. 53 kg fermentable sugar 3.
syrup ) (100 kg theo. prodn. ) (100 kg cane juice)=1302.54 MT/day (322.381 MT day 99 kg actual prodn. 25 kg syrup
