BARE CONDUCTOR ACSR SPLN 435/55 (PT KABELINDO MURNI) Tegangan maksimum konduktor yang diizinkan (Kg) Diameter konduktor (mm) Berat Konduktor (kg/m) Luas penampang Alumunium (mm^2) Luas penampang kawat baja (mm^2) Modulus elastisitas konduktor (kg/mm2) Koefesien muai panjang (1/derajat Celsius) Solusi : 1 kg = 1 kgf dc = overall diamter of conductor (mm) Leq = Ekuivalen Span atau Rulling Span A = Conductor Area (mm2) ( Al Area + St Area ) t0 = Ba Basic temperature w0 = Basic weight per length of conductor at basic temperature (t1) t1 = Initial condition temperature t2 = Final condition temperature ε = Linear coeffecient of expansion E = Modulus elasticity of conductor (N/mm²) P = Wind pressure (kg/m²) wp = wind load = P . (dc / 1000) we = Effective weight of conductor per unit length = √ (wp² + wo²) w1 = Basic weight per length of conductor at initial temperature (t1) = we / lt 1 (at (at init initia iall tem tempe pera ratu ture re)) lt 1
w2
= =
y1
= = = =
y2
σ1
σ2 Stress
σ2
=
lo (1 + ε (t1-to))
=
1 x (1 +
0.0000193 (
10
-
3,400.00 28.80 1.67 434.30 56.30 7,000.00 1.93E-05
= = = = = = = = = = = = = =
9.81 28.80 152.000 490.600 20.00 1.67 10.00 80.00 0.000019 68,67 ,670.00 40.00 1.15 2.0271 2.0275
N mm² met mm² °C kg/m °C °C 1/°C N/m kg/m kg/m kg/m kg/m
20 ))
0.999807 = 1x 0.999807 lt 1 = m Basic weight per length of conductor at final temperature (t2) w1 / lt 2 (at (at fi fina nall tem tempe pera ratu ture re)) lt 2 = lo (1 + ε (t1-to)) 0.000019 ( 80 20 )) = 1 x (1 + 1.001158 = 1x 1.001158 lt 2 = m Initial condition weight of conductor per unit volume (lt 1 x g)/ A Final condition weight of conductor per unit volume (lt 2 x g)/ A
= Initial condition tension of co conductor (Max. Working Tension) = (max (max tens tensio ion n x gra gravi vity ty)) / tot total al area area 3,400.00 x 9.81 / 490.60 = 67.986 N/mm² = = Final condition tension of co conductor (Max. Working Tension) = (Final (Final tensio tension n x Total Total Con Conduc ductor tor Secti Sectiona onall Area Area)) / Grav Gravity ity 38.42 x 490.60 / 9.81 = 1,921.183 N/mm² = value obtain form equation where:
: : : : : : :
=
2.0252 kg/m
=
0.04054 N/m
=
0.04050 N/m
=
67.986 N/m
=
38.416 N/m
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A
5.32
=
5.32 10.64
Y(σ2) ==> σ2^3 + Y'(σ2) ==> 3σ 3σ2^2 +
B σ2^2 σ2
-
943.66
= 943.7
= 0 = 0
Newton - Rhapson Iteration (trial error method) langkah 1 2 3 4 5 6 7 8 9 S max
σ2
Y'(σ2)
39 38.5 38.42 38.416 38.4159 38.41582 38.415819 38.4158196
4,978.136 4,856.564 4,837.251 4,836.287 4,836.262 4,836.243 4,836.243 4,836.243
Y (σ2) 66,470.490 64,011.878 63,624.126 63,604.779 63,604.295 63,603.908 63,603.903 63,603.906
38.41581965
4,836.243
63,603.906
= =
3.0460 meter
Andongan min = Tegangan tarik kabel t0 Tegangan tarik kabel t max
=
1.7222 3,403.49 1,920.16
σ2+1 25.648 25.320 25.267 25.264 25.264 25.264 25.264 25.264 25.264
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r
² ²
².m ².m
²
²
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350 48 48.35 48.353 48.3531 48.35312 48.35315 48.353157 48.3531574 48.35315745
280 43 43.3 43.32 43.327 43.3276 43.32766 43.327668 43.3276684 43.32766843
