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KVPY Solutions 16-10-10
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KVPY Solutions 22-10-10
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KVPY QUESTION WITHANSWER 1.
In a right angled ABC (right angled at C), the perpendicular drawn from C on the hypotenuse hypotenuse meets the hypotenuse at D and the bisector of C meets the hypotenuse at E. If
( AE) (EB)
=
3 and (DB) = 4 cm, 2
what is (CD) ? (A)
8 cm (C) 11 cm
(B*) 6 cm (D) Data insufficient
A E D Sol.
B
C ( AE) (EB)
=
( AC) (BC)
2
AE AC2 = .....(i) EB BC2 From the principles of similarlty of triangle we have also BC2 = BD × BA and AC2 = AD × BA AC2
BC
2
=
AD BD
...(ii) 2
AE AD = From (i) & (ii), BD EB 9 × 4 = 9 cm 4 Using properties of similarity in right , CD = 6 cm.
2.
AD =
CD2 = DB × DA = 4 × 9
The velocity-time graph of a body falling from rest under gravity and rebounding from a solid surface is represented by which of the graphs shown in figure ?
v
v (A*)
t
v
v
(B)
(C)
t
(D)
t
t
Sol.
In downward motion velocity increases. as it strikes the surface, surf ace, changes its direction and start decreasing and become zero and initial point.
3.
If the specific gravity of liquid Hg metal is 13.6, the volume occupied by one atom of Hg is about : (Assume no empty space to be present between Hg atoms) (A) 1.2 × 10 –23cm3 (B*) 2.4 × 10 –23 cm3 (C) 1.8 × 10 –23 cm3 (D) 3 × 10 –23 cm3
4.
In humans lungs. How many m any lobes are (A*) 2 in Left and 3 in right lungs (C) 3 in each lung
(B) 3 in left and 2 in right lungs (D) 2 in each lung