IWCF Principles & Procedures Test Paper (Answer)

PRINCIPLES & PROCEDURES TEST PAPER ANSWERS 17)

18)

372FT. 240PSI Overbalance ÷ .6448psi/ft mud gradient = 372.208ft. (1) (1) (2) (3) (3) (4) (4)

Incre Increas asee in in R.O R.O.P .P.. (Dr (Dril illi ling ng Brea Break) k) Connection Gaz Incr Increa ease se in Torq Torque ue and and Drag Drag Incre Increas asee in in Flow Flow line line temp temper erat atur ure. e.

19)

E

20)

B (Tripping in)

21)

A&C

22)

D&E

23)

1ppg (468 ÷ 9000) ÷ 0.052

24)

A&C

25)

32bbls (.6448psi/ft -.12psi/ft) = .5248psi/ft 240psi + .5248psi/ft = 457.317ft. 457.317ft. x .0702bbls/ft OH capacity = 32.1036bbls

26)

= 12.8 ppg 7987psi + 12,000ft + .052 = 12.7996 ppg

27)

(1) (2) (3) (4)

Fonnula no. 5

Minimize pressures on the well bore and BOP equipment Allow for smooth operation of the Remote Choke Disperse of the Kick fluids at a controlled rate Allow time for the Mud to be weighted up

PRINCIPLES & PROCEDURES TEST PAPER

28)

(1) (2) (3) (4)

At the start of each shift Any time the Mud weight is changed After Bit and Nozzle changes After changes to the mud pumps

29)

B

30)

B

31)

C

32)

B

33)

C

34)

(a) (b) (c)

35)

B

36)

C

37)

True

38)

D

39)

C

40)

B 148psi Formula No. 26 [ (.6448 x .0744) x 420ft. ]÷ (.0744 + .0622) = 147.318psi

41)

3.87bbls (P1 x V1) ÷ P2 = V2

4900 psi (10.3 x 6200 ft x .052) + 1580 psi = 4900.72 psi 15.2 15.2 ppg ppg 490 4900. 0.72 72 + .05 .052 2 + 6200 6200'' = 15.2 15.200 007 7 ppg ppg Fonn Fonnul ulaa no. no. 17 902 902 psi psi (15. (15.2 2 -12 -12.4 .4)) x .052 .052 x 620 6200' 0' = 902 902.7 .72 2 psi psi Fonn Fonnul ulaa no. no. 18

[(12,000' x12.4 ppgx.052) x 2bbls ] (6200 ftx12.4 ppgx.052)


=

3.8709bbls

42)

A

43)

Soft = A, G, E, D, C Hard = B, G, D, E

44)

D

45)

E

46)

C

47)

A

48)

B

49)

B

50)

13.2ppg [ (500 ÷ .052 ÷ 12,000’) + 12.4ppg ] = 13.2012ppg

51)

A = 114psi/ft Gas Formula No. 13 11bbls ÷ 0292bbls/ft = 376.712 Height of influx 6448psi/ft [(700SICP – 500 SIDPP) ÷ 376.712] = 1138psi

52)

(a) 349 feet 225psi ÷ 6448psi/ft = 348.94 feet

53)

3 bbls 225psi x 11bbls ÷ 8238psi = 3004bbls

54)

(a) 900psi 500 SIDPP + 400 PSCR = 900psi (b) 426psi 400psi x (13.2ppg ÷ 12.4ppg) = 425.806psi


Formula No. 10

Formula No. 27

55)

(a) Surface to bit strokes (b) Bit to shoe stokes (c) Time from bit to surface (d) Volume from shoe to surface (e) psi/stroke reduction (f) MAASP with kill mud

56)

664psi [(900 – 426) ÷ 2010stks] = 2358psi / reduction per stroke 1000 strokes x 2358 = 235.82psi reduction 900 – 235.82 = 664.18psi circulating pressure

57)

812psi Well effects = 500psi _________________ _________________ 0 psi Kill Kill mud at Bit Pump effects = 400psi __________________ 426psi Kill Mud at Bit Well effects at 1005stks 1005stks = 250psi Pump effects at 1005stks 1005stks = 413psi 413 x (35 ÷ 30) 2 = 562.1388psi pump pressure 562.1388psi + 250psi = 812.1388psi circulating pressure at 35spm.

58)

A 2010 strokes to the bit, DP pressure should be FCP @ 426psi 600 – 426 = 174psi overbalance

59)

B (Should be decreasing) Pressure above the Gas-Kick must reduce otherwise there cannot be any expansion.


= = = = = =

2010 strokes 2470 strokes 178.6 mins or 2hr 58min 36sec 295bbls 2358psi/storke 644.8psi

60)

B (Decreasing) Less mud going into the Hole, pressures will reduce, reducing BHP

61)

B (Staying the same) More strokes to give same Volume, BHP will be restored

62)

644 psi (15.2 – 13.2) x 052 x 6200’ = 644.8psi


Formula No. 18

IWCF Principles & Procedures Test Paper (Answer)

Recommend Documents