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Indices@Indeks
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VisnuVaratan
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Indices
Paper 1 1.
(e3)2 = e3 = e6
Answer:
2.
1 — 2 8
7.
2
×
p4 ––– 9
3 — 2
—
(9) 2 4
D
p6 = –––– (3)3 p6 = ––– 27
(h ) = h = h4
B
Answer: 3.
5
3
=
−
1 53
Answer:
4.
−
t
4 — 3
8.
(m2)4
×
= m2 4 × m = m8 + ( 2) = m6 ×
2
−
−
A
1 4 —
Answer:
9.
( p p3)4
÷
p5 = p3 4 ÷ p5 = p12 5 = p7
D
1 — 4 2
1 — 2
4
= �� 9 (n = 3 n2
×
10.
1 — 2
)
( x x4)2 = x2n x4 2 = x2n x8 = x2n ∴ 8 = 2 n n = 4 ×
C
Answer: 2 — 3 3
2 — 3
B
2 — 3 3
(8 x ) = (8) ( x ) = ( 3�� 8 )2( x x 2 2 = (2) ( x x ) = 4 x2
Answer:
C
1 — 4 2
(9n ) = (9) (n )
Answer:
×
−
Answer:
6.
2
−
B
t 3 1 = –––– 3�� t4 t
5.
D
m
Answer: =
3 —
×
p 2 = –––––– (�� 9 )3
1 — × 8 2
Answer:
3 —
( p p4) 2 = ––––– 3
3
×
2 — 3
)
11.
3 2 × 27 3 2 × 3 3 3 2+3 31 ∴ m −
−
−
D
Answer:
1
= 3m = 3m = 3m = 3m =1 C
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Penerbitan Pelangi Sdn. Bhd.
Mathematics
12.
(2q3)2 × 3 q
4
−
SPM
Chapter 3
= (2 q3)(2q3) × 3 q 4 = 2 × 2 × 3 × q3 + 3 + ( = 12q2
1 —
−
4)
−
4.
(16m4) 4 –––––––– 2n 4
Answer: 13.
3
×
) ÷ 4 e
=
1
(5
−
3 ) = (5 1)2 × (3 = 5 2 × 3 1 1 = ––– × 3 52 3 = ––– 25
×
1 — 4
m3n4
×
n4 – 1
×
Answer:
−
1 — × 2 2
5.
)
−
Answer:
4
C
D
1 — 2 2
×
2m 2n
= m1 + 3 = m4n3
−
14.
1 — 4
2 m 3 4 = × m n 2n
C
(2e2)3 ÷ 4 e = (2)3(e2 8e6 = –––1 4e = 2e6 1 = 2e5
Answer:
×
m3n4
×
p3 p3q –3 = 4q3 4 Answer:
C
5 —
6.
n4 n × ––––– 1 —
C
n4 1 —
= n2
5 —
n4
×
×
1 – — 4
n
1 5 1 — + — + (– —) 4 4
= n2
3 —
= n2
Paper 1 1.
Answer:
1 – — 2
1 =6 t n
1 – — 2
1 = 6, n = t = 2
∴
Answer: (h4k 3) –1 h2k –5 h – 4k –3 = h2k –5 = h – 4 2 k = h –6k 2 −
Answer:
3.
3 — 5
20
–5
=
� �
=
� �
=
� �
B
2 3 2 3 3 2
–5
1 — 2
5 – — 2
5 — 2
Answer:
C
3 − ( −5)
5 —
D
(2a3 × 3 b 2 )2 8. ––––––––––– a2b3 5 —× 2
22a3 2 × 3 2b 2 = –––––––––––––– a2b3 ×
y = x 20
3 —
y — x
=
x = 5, y = 3
Answer:
4a6 × 9 b5 a2b3
= 36a6 – 2 b5 – 3 = 36a4b2
A
Answer:
©
×
−
20 5 = 20 ∴
� � 2 3
7.
t –n = 6
2.
C
Penerbitan Pelangi Sdn. Bhd.
2
C
Mathematics
9.
(n3)5 ÷ n7 = n3 5 ÷ n7 = n15 ÷ n7 = n15 7 = n8
2.
×
10.
×
×
−
−
A
Answer:
16 2 x = ––– 23 x 24 2 x = ––– 23 x 2 x = 2 4 3 x ∴ x = 4 − 3 x x + 3 x = 4 4 x = 4 x=1
3.
(3h 2k )3 −
1 — h2k 1 3 −
×
= (3 3h 2 3k 1 3) × 3 1h2k 1 = 3 3 + ( 1)h 6k 3 × h2k 1 = 3 2h 6 + 2 k 3 + ( 1) = 9 h 4k 2 −
×
−
−
×
−
−
−
−
Answer:
B
D
2m3n –––––––– (3mn 2)2 −
2m3n = ––––––––––– 32m1 2n 2 2 2m3n = –––––– 9m2n 4
1 – — 2
6
×
1 = –––– 1 —
−
×
−
62
2m3 2n1 ( 4) = ––––––––––– 9 2mn5 = ––––– 9 Answer: C −
D
Answer: 1 —
12.
−
−
−
4.
11.
−
−
C
Answer:
Chapter 3
(2t 3m)2 × 5 t 2 = (2 2t 3 2m1 2) × 5 t 2 = 4 t 6m2 × 5 t 2 = 20t 6 + 2 m2 = 20t 4m2 −
−
Answer:
SPM
42 × 3 2 ––––––– 62
4
−
−
1 — × 4 2
2 × 4
× 3 4 = ––––––––––– 62 4 8 4 × 3 2 –––––– = 68 (22)8 × 3 2 = –––––––– (2 × 3) 8 ×
16
5.
−
−
×
×
−
−
−
−
−
−
2
2 × 3 = ––––––– 28 × 3 8 = 2 16 8 × 3 2 = 2 8 × 3 6
(ef 4)2 ÷ e 3 f 9 = ( e1 2 f 4 2) ÷ e 3 f 9 = e2 f 8 ÷ e 3 f 9 = e2 ( 3) f 8 9 = e5 f 1
Answer:
A
8
−
−
6.
B
Answer:
( x x 2 y3)3 × x7 y2 = ( x 2 3 y3 3) × x7 y2 = x 6 y9 × x7 y2 = x 6 + 7 y9 + 2 = xy11 −
−
×
×
−
−
Answer:
Paper 1 1.
5 —
1 —
h4
4 —
( h 4
k 3 )3
×
×
5 — 4
1 4 — × 3 — × 3 4 3
=h
5 — 4
=h
( h
× ×
k
7.
=h = h2k 4
Answer:
×
1 —
(2 p2q 3 )3
)
×
p3q
4
−
1 — × 3
= (2 3 p2 3q 3 ) = 8 p6q1 × p3q 4 = 8 p6 + 3 q1 + ( 4) = 8 p9q 3
3 — 4 4
×
h k
5 3 —+— 4 4
C
×
p3q
4
−
−
−
k 4
−
Answer:
D
3
B
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Penerbitan Pelangi Sdn. Bhd.
Mathematics
8.
1 —
(27m3n9) 3 1 — 3
3
SPM
9 m2n
1
13.
−
÷
1 — 9 3
×
Chapter 3
1 — 3
×
= (27 m ) ÷ 9 m2n n = 3 m1n3 ÷ 9 m2n 1
1
−
6
−
×
−
4
3)
−
×
1 — 3
4
−
3 1
×
−
−
−
−
−
−
C
Answer:
×
= (27 × 2 ) × 2 = 3 1 × 2 2 × 2 4 × 3 1 = 3 1 + 1 × 2 2 + ( 4) = 3 2 × 2 6 32 = ––– 26 9 = ––– 64
3m1 2n3 ( 1) ––––––––––– = 9 1 4 m n = ––––– 3 −
(2
−
1 — 3
−
−
1 —
(27 × 2 6) 3
1 —
B
Answer:
3g × (16 h6) 2 9. ––––––––––– 1 —
(g9h –3) 3
1 — 6 2
×
1 — 2
3g × 16 h = –––––––––––– 1 1 9
— 3
×
g
3
−
h
×
14.
— 3
10.
−
−
D
1 —
= ( x 6
2 — 3
= x y
1 — × 2 3
÷
2
) ÷ ( x
x y
2 — 6 − 2 3
= x y = x4 y 1
−
6
×
1 — 5 3
y
×
1 — 3
) 15.
5 — 3
5 — 3
C
1 — 4 2
5 )
×
5 — 2
5 —
×
1 — 2
3
×
5
4
3 — 4
×
3
−
3 —
) × 3 4
3 —
5 2 × 3 4
5
×
×
5
×
÷
h2 ––– k 1 — × 2
= (2 2h 1 2k 2 ) ÷ ( h2k 1) = 4 h 2k 1 ÷ h2k 1 = 4 h 2 2k 1 ( 1) = 4 h 4k 2 ×
−
−
Answer:
−
−
3
−
3)
−
A
−
−
Answer:
16.
A
1 —
(9 × 2 6) 2
(2
−
1 —
÷
6
−
×
5
−
3 4)
×
1 —
2 = (9 2 × 2 ) ÷ (2 5 × 3 4) = (3 1 × 2 3) ÷ (2 5 × 3 4) = 3 1 4 × 2 3 ( 5) = 3 3 × 2 2 22 = ––– 33 4 = ––– 27 −
12.
1 — 2 −4
1 —
−
(2 3 × 3 5)
(16 × 3 )
−
÷
4
−
×
−
1 —
2 = (16 2 × 3 ) ÷ (2 3 × 3 5) = (2 2 × 3 2) ÷ (2 3 × 3 5) = 2 2 3 × 3 2 ( 5) = 2 1 × 3 3 33 = ––– 21 27 = ––– 2 −
−
−
−
−
−
−
−
−
Answer:
©
Answer:
A
Penerbitan Pelangi Sdn. Bhd.
−
−
4
C
−
−
3
−
−
1 —
−
5
×
1 — 2
×
2+( × 5 =3 = 3 2 × 5 1 32 = ––– 51 9 = –– 5
C
−
56 ––– 24
−
5 3 —+— 4 4
(2h 1k 2 )2
−
(3
= 34
Answer:
−
5 — 2
= (3
−
11.
−
Answer:
1 —
y
÷
−
( x x3 y 3 )2 ÷ ( x6 y5) 3 3 × 2
5 3)
×
−
−
Answer:
1 — × 3 3
56 ––– 24
÷
= (2 2 × 5 3) ÷ (5 6 × 2 4) = 2 2 ( 4) × 5 3 6 = 2 6 × 5 3 26 = ––– 53 64 = –––– 125
( −1)
−
5) 3
×
= (4
3g × 4 h3 = –––––––– g3h –1 = 12g1 3 h3 = 12g 2h4 12h4 = ––––– g2
1 —
(4 3
Mathematics
17.
1 —
−
27 3 21. –––––––––– 1
−
−
−
×
−
×
−
9
×
−
−
−
5 — 3
−
3
(3 ) = –––––––––––– 1
−
— × 6
(32) 4 × 4 3 35 = ––––––– 8 3 × 4 2 −
−
−
A
Answer:
—
(4 3 )6
4
−
−
−
Chapter 3
5 —
−
(64 3 × 5 1)2 ÷ (5 4 × 2 3) = (4 × 5 1)2 ÷ (5 4 × 2 3) = (2 2 2 × 5 1 2) ÷ (5 4 × 2 3) = (2 4 × 5 2) ÷ (5 4 × 2 3) = 2 4 3 × 5 2 ( 4) = 2 1 × 5 2 = 2 × 25 = 50
SPM
= 3 5 ( 8) × 4 = 3 3 × 4 2 33 = ––– 42 27 = ––– 16 −
−
−
2
−
−
3 — 4
18.
81 × (3 2)3 –––––––––– 96 3 —
(34) 4 × 3 2 3 = ––––––––––– (32)6 ×
= 33 + 6 =3 3 1 = ––– 33
22.
12
−
4 — 3
8 ––– 27
(5
C
2 — 3
2 — 3
4
×
1 — 2
−
5 2 × 3 2 = ––––––– 54 −
Answer:
−
= 5 2 ( 4) × 3 2 = 5 2 × 3 2 = 25 × 9 = 225 −
23.
7 ) −
×
6
×
1 — 3
D
(7
÷
7
×
−
2 — 3
4 — 3
) ÷ (7 −
−
9 1) −
×
1 — 3
) ÷ (7
×
= 3 2 ( 2) × 7 = 3 4 × 7 2 34 = ––– 72 81 = ––– 49 −
4
−
= (3 2 × 7
4 — 3
−
2 — 3
2 — 3
3 2)
×
−
3 2)
×
−
2 — 3
−
32 ––––––––––– 1 —
(212 × 7 4) 2 −
4 — 5 5
(2 ) = –––––––––––– 1 — 2
(3
= (3
4 — 5
×
6
A
1 — 4 3
−
Answer:
12
)
24 – 4 2 = –––– × 5 34 20 × 52 = –––––– 34 25 = ––– 81
1 — 4 2
−
2
1 — × 4
4 2
×
−
(5 ) × 3 –––––––––––– – = ––––––––––– 2 2 (5 )
20.
1 — × 4 2
−
÷
2 4 = — ÷ (5 2 × 4 2) 3 24 2 4 ÷ (5 × 2 ) = ––– 34
125 × (3 ) –––––––––––– 25 –2
−
(5
1 —
4 2 )4
×
−
Answer:
3
4 — 3
23 = ––– 33
1 = ––– 27
19.
1 — 2
−
÷
−
−
B
Answer:
33 × 3 6 = –––––– 312
7
×
4
−
×
1 — 2
Answer:
4
2 = ––––––– 6 2 × 7 2 = 2 4 6 × 7 2 = 2 2 × 7 2 72 = ––– 22 49 = ––– 4 Answer: C
24.
−
2 — 9 3
(2 ) −
9
−
−
×
D
(4
×
2 — 3
1 — 2 4
6 )
×
1 — × 4
2 2 4 × (2 × 6 =2 = 2 6 × 2 8 × 6 2 = 2 6 + 8 × 6 2 = 2 2 × 6 2 = 4 × 36 = 144
−
×
)
−
−
Answer: 5
D
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Penerbitan Pelangi Sdn. Bhd.
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