A book about basics of heat and mass transfer (preview)Descrição completa
book for chemical engineers and related fields, in heat and mass tranferDescripción completa
book for chemical engineers and related fields, in heat and mass tranferFull description
Problem Set
Heat And Mass Balance And Transfer
Welty. Momentum, Heat and Mass.
Descripción: Welty. Momentum, Heat and Mass.
Fundamentals of Momentum, Heat and Mass Transfer, Sixth Edition
Welty. Momentum, Heat and Mass.
THIS CONTAINS III UNITS OF HEAT AND MASS TRANSFER NOTES STUDENTS CAN MAKE USE OF ITFull description
Heat transfer
Hmt
Mass and Heat balance in Grinding ProcessFull description
Full description
Full description
Heat transfer is a discipline of thermal engineering that concerns the generation, use, conversion, and exchange of thermal energy and heat between physical systems. Heat transfer is classif…Full description
Scilab Textbook Companion for Fundamentals Of Engineering Heat And Mass Transfer by R. C. Sachdeva1 Created by Nittala Venkata Krishna B.TECH Mechanical Engineering Sastra University College Teacher Dr. Anjan Kumar Dash Cross-Checked by Lavitha Pereira May 23, 2016
1
Funded by a grant from the National Mission on Education through ICT, http://spoken-tutorial.org/NMEICT-Intro. This Textbook Companion and Scilab codes written in it can be downloaded from the ”Textbook Companion Project” section at the website http://scilab.in
Book Description Title: Fundamentals Of Engineering Heat And Mass Transfer Author: R. C. Sachdeva Publisher: New Age Science Ltd., New Delhi Edition: 4 Year: 2009 ISBN: 9781906574123
1
Book Description Title: Fundamentals Of Engineering Heat And Mass Transfer Author: R. C. Sachdeva Publisher: New Age Science Ltd., New Delhi Edition: 4 Year: 2009 ISBN: 9781906574123
1
Scilab numbering policy used in this document and the relation to the above book. Exa Example (Solved example) Eqn Equation (Particular equation of the above book) AP Appendix to Example(Scilab Code that is an Appednix to a particular
Example of the above book) For example, Exa 3.51 means solved example 3.51 of this book. Sec 2.3 means a scilab code whose theory is explained in Section 2.3 of the book.
2
Contents Listt of Scilab Codes Lis
4
1 Ba Basi sic c Co Conc ncept eptss
5
3 OneD OneDime imensi nsiona onall Steady State State Heat Conduct Conduction ion
11
5 Tran ransie sient nt Heat Heat Conduc Conductio tion n
46
6 Fundame undamenta ntals ls of convec convectiv tive e heat transfer transfer
72
7 Forc orced ed Conve Convecti ction on Systems Systems
77
8 Nat Natural ural Con Conve vecti ction on
106
9 The Therma rmall radiati radiation on basic basic relati relations ons
//INPUT DATA L = 0 . 0 2 ; // T h ic ne s s o f s t a i n l e s s s t e e l p l a t e i n m T = [ 5 5 0 , 5 0 ] ; // T em pe ra tu re s a t b ot h t he f a c e s i n degree C 9 k = 1 9 . 1 ; // Thermal C on d u ct iv it y o f s t a i n l e s s s t e e l a t 3 0 0 d e g r e e C i n W/m .K 10 11 //CALC9ULATIONS 12 q = ( ( k * ( T ( 1 ) - T ( 2 ) ) ) / ( L * 1 0 0 0 ) ) ; // H eat t r a n s f e r e d
p er
u n i a r e a i n kW/mˆ 2 13 14 //OUTPUT 15 mprintf ( ’ The h ea t t r a n s f e r e d t hr ou gh t he m a t e r i a l p e r u n i t a r e a i s %3 . 1 f kW/mˆ 2 ’ ,q )
10
16 17 //=================================END OF PROGRAM
==============================
Scilab code Exa 1.2 Rate of heat transfer
1 / / C h a p t e r −1 , Exa mpl e 1 . 2 , Pa ge 1 1 2 //
//INPUT DATA L = 1 ; // L en g th o f t h e f l a t p l a t e i n m w = 0 . 5 ; // Width o f t he f l a t p l a t e i n m T = 3 0 ; // A i r s tr ea m t em p er a tu re i n d e g re e C h = 3 0 ; / / C o n v e c t i v e h e a t t r a n s f e r c o e f f i c i e n t i n W/m ˆ2.K T s = 3 0 0 ; // T em pe ra tu re o f t he p l a t e i n d e gr e e C
//CALCULATIONS A = ( L * w ) ; // Area o f t he p l a t e i n mˆ2 Q = ( h * A * ( T s - T ) / ( 1 0 0 0 ) ) ; // H eat t r a n s f e r i n kW //OUTPUT mprintf ( ’ H eat t r a n s f e r
r a t e i s %3 . 2 f kW ’ ,Q )
//=================================END OF PROGRAM ==============================
Scilab code Exa 1.3 Rate of radiant heat
11
1 / / C h a p t e r −1 , Exa mpl e 1 . 3 , Pa ge 1 1 2 //
//INPUT DATA T = 5 5 ; // S u r f a ce t em p er at u re i n d e g re e C //CALCULATIONS q = ( 5 . 6 6 9 7 * 1 0 ^ - 8 * ( 2 7 3 + T ) ^ 4 ) / 1 0 0 0 ; // The r a t e a t wh ic h
t h e r a d i a t o r e mi ts r a di a n t h ea t p er u n i t a re a i f i t b e ha v es a s a b l a c k body i n kW/mˆ 2 11 12 //OUTPUT 13 mprintf ( ’ The r a t e a t wh ich t he r a d i a t o r e mi ts
r a d i a n t h e at p e r u n i t a r e a i s %3 . 2 f kW/mˆ 2 ’ ,q ) 14 15 //=================================END OF PROGRAM
==============================
Scilab code Exa 1.5 Overall heat transfer coefficient
1 / / C h a p t e r −1 , Exa mpl e 1 . 5 , Pa ge 2 0 2 //
//INPUT DATA k = 0 . 1 4 5 ; / / Therma l c o n d u c t i v i t y o f F i r e b r i c k i n W/m. K e=0.85; / / E m i s s i v i t y L = 0 . 1 4 5 ; // T hi ck ne ss o f t he w a ll i n m 12
10 11 12 13 14 15 16 17
T g = 8 0 0 ; // Gas t e m pe r a tu r e i n d e g r e e C T w g = 7 9 8 ; // Wall t em pe ra tu re i o n g as s i d e i n d e g r ee C h g = 4 0 ; / / F il m c o n d u ct a n c e on g a s s i d e i n W/mˆ 2 . K h c = 1 0 ; / / Fi lm c o nd u ct a nc e on c o o l a n t s i d e i n W/mˆ 2 .K F = 1 ; // R a d i at i o n Sh ap e f a c t o r b et we en w a l l and g a s
//CALCULATIONS
R 1 = ( ( ( e * 5 . 6 7 * 1 0 ^ - 8 * F * ( ( T g + 2 7 3 ) ^ 4 - ( T w g + 2 7 3 ) ^ 4 ) ) / ( T gT w g ) ) + ( 1 / h g ) ) ; // Thermal r e s i s t a n c e i n v e r s e 18 R 2 = ( L / k ) ; // T herm al r e s i s t a n c e 19 R 3 = ( 1 / h c ) ; / / Th erma l r e s i s t a n c e 20 U = 1 / ( ( 1 / R 1 ) + R 2 + R 3 ) ; // O v er a l l h ea t t r a n s f e r
c o e f f i c i e n t i n W/mˆ 2 .K 21 22 //OUTPUT 23 mprintf ( ’ O v e r a l l h e a t t r a n s f e r W/mˆ2.K’ ,U )
coefficient
i s %3 . 3 f
Scilab code Exa 1.6 Heat loss per unit length
1 / / C h a p t e r −1 , Exa mpl e 1 . 6 , Pa ge 2 1 2 //
//INPUT DATA D = 0 . 0 5 ; // O ut si de d i am et er o f t he p i pe i n m e=0.8; // Emmissi vity T = 3 0 ; / /Room T e mp e ra t ur e i n d e g r e e C T s = 2 5 0 ; // S u r f a ce t em p er at u re i n d e gr e e C h = 1 0 ; / / C o n v e c t i v e h e a t t r a n s f e r c o e f f i c i e n t i n W/m ˆ2.K
12
13
13 //CALCULATIONS 14 q = ( ( h * 3 . 1 4 * D * ( T s - T ) ) + ( e * 3 . 1 4 * D * 5 . 6 7 * 1 0 ^ - 8 * ( ( T s + 4 7 3) ^ 4 - ( T + 2 7 3 ) ^ 4 ) ) ) ; // Heat l o s s p er u n i t l e n g t h o f
p i p e i n W/m 15 16 //OUTPUT 17 mprintf ( ’ H eat l o s s p er u n i t l e n g t h o f p ip e i s %3 . 1 f W/m ’ ,q ) 18 19 //=================================END OF PROGRAM
==============================
Scilab code Exa 1.7 Surface temperature
1 / / C h a p t e r −1 , Exa mpl e 1 . 7 , Pa ge 2 1 2 //
//INPUT DATA A = 0 . 1 ; // S u r f ac e a r ea o f w at er h e a t er i n mˆ2 Q = 1 0 0 0 ; // Heat t r a n s f e r r a t e i n W T w a t e r = 4 0 ; // T em pe ra tu re o f w at er i n d e g re e C h 1 = 3 0 0 ; / / H e a t t r a n s f e r c o e f f i c i e n t i n W/m ˆ 2 . K T a i r = 4 0 ; // T em per at ure o f a i r i n d e gr e e C h 2 = 9 ; / / H e a t t r a n s f e r c o e f f i c i e n t i n W/m ˆ 2 . K
//CALCULATIONS T s w = ( Q / ( h 1 * A ) ) + T w a t e r ; / / T e m pe r at u re when u s e d i n
w at er i n d e g r ee C 16 T s a = ( Q / ( h 2 * A ) ) + T a i r ; / / T em pe ra tu re when u s ed i n