Elastomeric bearings EN 1337-3 (ENG).pdfDescripción completa
aaFull description
Ensayo de calificación de Juntas Flexibles para tuberías
PROJECT:
Jaigaon – Hasimara – Dhupguri section and Mainaguri – Changrabandha section including proposed Pasakha access road of AH 48corridor
TITLE:
Design of Minor Bridge at Ch:104+580
TYPE OF SUPERSTRUCTURE
:
DOCUMENT NO.
DATE
BBRD/MNB/104+580/02
18-Apr-16
DESIGNED
CH CHECKED
KKK
MPB
SHEET
15.00 m RCC-I Girder
FOR MAXIMUM LOAD (NORMAL CASE)
Reaction due to Dead Load on One bearing = Reac eactio tion due due to Super Imposed Dead Dead Load on One beari earin ng = Reaction due to Live Load on One bearing =
230 KN 32 KN 656 KN 92 t
From STAAD From STAAD with Impact Impact
Nmax
Design vertical load on bearing
Fh
Hbd
External horizontal force No. of Bearings Bearings External horizontal force per bearing Horizontal force rce long. Direction due to deformation Horizontal force along b (long. Direction)
Hld
Horizontal force along l (trans. Direction)
Dbd
Translation along b (long. Direction)
5.00 5.00 mm
Dld
Translation along l (trans. Direction)
0.0 mm
abd ald
Rotation along b (long. Directio {From STAAD} Rotation along l (trans. Direction)
10.00 4 3.47 0.974 4.448
t t t t
0.00 t
918. 918.0 0 KN
Due to 1L-70R
Calculations as shown below) 43.7 43.7 KN 0.0 KN
0.001 0.001 radia radians ns 0.0000 0.0000 radians radians
Dimension details of bearings b0 l0 hi n
Overall breadth (long. Direction) Overall length (trans. Direction) T c ness o eac ayer o e astomer Number of internal elastomer elastomer layer layer
he
Thickness of outer elastomer layer
(=hi/2 <=6mm)
5 mm
hs
Thickness of outer steel layer
= 3/4/6 FOR hi<=8,10/12/16
3 mm
hc
Side elastomer cover
h
total elastomer thickness
=nhi+2he
50 mm
h0
Outer dimension (overall thickness)
=h+(n+1)hs
65 mm
b
Eff. width of brg.(excluding cover) cover)
=b0-2hc
263 mm
=l0-2hc = =GA/h =V.Dbd
363 mm
Eff. length of brg.(excluding cover) cover) .p an area o rg. rg. exc u ng cover V Shear rating of elastomeric bearing V.Lrc Hor. Force one bearing l
275 mm 375 mm 10 mm 4 Nos.
6 mm
194.83 t/m 0.97 t
Jaigaon – Hasimara – Dhupguri section and Mainaguri – Changrabandha section including proposed Pasakha access road of AH 48corridor
PROJECT:
TITLE:
Design of Minor Bridge at Ch:104+580
Check for plan dimensions a)
DATE
BBRD/MNB/104+580/02
18-Apr-16
DESIGNED
CHECKED
KKK
MPB
SHEET
(Clause 916.3.3 of IRC : 83 part II )
= 375/275
l0/b0
DOCUMENT NO.
=
1.364
<= 2 Thus OK
b)
= 50
h
b0/5
<=
275/5
<=
<= 55 Thus OK
b0/10
> c)
Check for elastomer stress
> 27.5 Thus OK >6 < 12 Thus OK
7.63
IRC : 83 part II
= 918*1000/95469
smax
275/10
. = A/2/(b+l)/hi = 95469 2 (263+363) 10 =
Shape factor S =
ec
>
or trans at on
=
ause
. . o
:
part
)
gdb = Hb/A+Dbd/h
=43.7*1000/95469+5/50 =
0.558
gdl = Hl/A+Dld/h
=0*1000/95469+0/50
0.000
gd = sqrt(gdb +gdl )
=sqrt(0.558*0.558+0*0)
=
< 10MPa Thus OK
9.62
0.558 <= 0.7 Thus OK
Check for rotation aall
(Clause 916.3.5 of IRC : 83 part II )
= 0.5*n*sm*hi/(b*S*S)
= 0.5*4*9.62*10/(263*7.63*7.63)
=
0.01257 radians
abd
=
0.0010 radians
ald
=
0.00000 radians
ad
= (0.0010*263+0*363)/263
= (abd*b+ald*l)/b
0.0010 radians <
Check for friction gd 0.2+0.1*sm
0.01257 radians Thus OK
(Clause 916.3.6 of IRC : 83 part II ) < 0.2+0.1*sm
= 0.2+0.1*9.62 = 1.16
>
gd calculated above
=
0.558 Thus OK
Check for total shear stress tc+tg+ta
(Clause 916.3.7 of IRC : 83 part II ) <
tc
= 1.5*sm/S
tg
= gd
5 Mpa
= 1.5*9.62/7.63=
1.892 Mpa
=
0.558 Mpa
Jaigaon – Hasimara – Dhupguri section and Mainaguri – Changrabandha section including proposed Pasakha access road of AH 48corridor
PROJECT:
TITLE:
Design of Minor Bridge at Ch:104+580
ta
2
2
= 0.5*(b *abi+l *ali)/hi
DOCUMENT NO.
DATE
BBRD/MNB/104+580/02
18-Apr-16
DESIGNED
CHECKED
KKK
MPB
SHEET
2
= 0.5*(263*263*0.0010+363*363*0)/10/10 0.346 Mpa
FOR MINIMUM LOAD (NORMAL CASE)
Reaction due to Dead Load on One pier = eac on ue o uper mpose ea oa on Reaction due to Live Load on One bearing =
ne ear ng =
230 KN 0 KN 26 t
rom From STAAD with Impact
Nmax
Design vertical load on bearing
Fh Hbd
External horizontal force Horizontal force along b (long. Direction)
10.00 t 3.47 t
Hld
Horizontal force along l (trans. Direction)
0.00 t
Dbd
Translation along b (long. Direction)
5.00 mm
Dld
Translation along l (trans. Direction)
0.0 mm
abd
Rotation along b (long. Directio {From STAAD}
ald
Rotation along l (trans. Direction)
262.0 KN
Due to 1L-70R +1L-ClassA 34.1 KN 0.0 KN
0.00100 radians 0.0000 radians
Dimension details of bearings b0
Overall breadth (long. Direction)
275 mm
l0
Overall length (trans. Direction)
375 mm
hi n
Thickness of each layer of elastomer Number of internal elastomer layer
he
Thickness of outer elastomer layer
(=hi/2 <=6mm)
5 mm
hs
Thickness of outer steel layer
= 3/4/6 FOR hi<=8,10/12/16
3 mm
hc
Side elastomer cover
h
total elastomer thickness
=nhi+2he
50 mm
h0
Outer dimension (overall thickness)
=h+(n+1)hs
65 mm
b
Eff. width of brg.(excluding cover)
=b0-2hc
Eff. length of brg.(excluding cover) Eff.plan area of brg.(excluding cover) V Shear rating of elastomeric bearing V.Lrc Hor. Force one bearing l A
10 mm 4 Nos.
6 mm
263 mm
=l0-2hc =l0-2hc
363 mm 95469 mm
=GA/h =V.Dbd
194.83 t/m 0.97 t
Jaigaon – Hasimara – Dhupguri section and Mainaguri – Changrabandha section including proposed Pasakha access road of AH 48corridor
PROJECT:
TITLE:
Design of Minor Bridge at Ch:104+580
Check for plan dimensions a) l0/b0 = 375/275 b)
DATE
BBRD/MNB/104+580/02
18-Apr-16
DESIGNED
CHECKED
KKK
MPB
(Clause 916.3.3 of IRC : 83 part II ) = 1.364
= 50
h
DOCUMENT NO.
b0/5
<=
<= 2 Thus OK <= 55
275/5
<=
SHEET
Thus OK
b0/10
>= c)
>=
275/10
. = A/2/(b+l)/hi
Shape factor S =
= 95469/2/(263+363)/10 = Check for elastomer stress
>6 < 12 Thus OK
7.63
IRC : 83 part II
= 262*1000/95469
smax
>= 27.5 Thus OK
Check for translation
=
> 2MPa Thus OK
2.75
(Clause 916.3.4 of IRC : 83 part II )
gdb = Hb/A+Dbd/h
=34.1*1000/95469+5/50 =
0.458
gdl = Hl/A+Dld/h
=0*1000/95469+0/50
0.000
2
2
gd = sqrt(gdb +gdl )
=
=sqrt(0.458*0.458+0*0)
0.458 <= 0.7 Thus OK
Check for rotation aall
(Clause 916.3.5 of IRC : 83 part II )
= 0.5*n*sm*hi/(b*S*S)
= 0.5*4*2.75*10/(263*7.63*7.63)
abd
= =
0.00359 radians 0.0010 radians
ald
=
0.00000 radians
= (0.0010*263+0*363)/263
0.00100 radians
ad
= (abd*b+ald*l)/b
< Check for friction gd 0.2+0.1*sm
0.00359 radians Thus OK
(Clause 916.3.6 of IRC : 83 part II ) < 0.2+0.1*sm