EJERCICIO TAMIZADO El análisis por tamizado que presenta la tabla 28! "orresponde a una muestra de "uarzo triturado# $a densidad de las part%"ulas es 2&'( )*+m, -(((2&' *+mm,. / los 0a"tores de 0orma son a12 / 1('3!# 4ara el material "on tama5o de part%"ulas "omprendido entre 6 / 2(( mallas "al"ule7 a. A en mil%metro mil%metros s "uadrados "uadrados por *ramo *ramo / 9 en part%"ulas part%"ulas por *ramo# b. D: ". Ds d. D e. 9i para el el in"rement in"remento o !'(+2(( !'(+2(( mallas mallas## 0. ;n del n?mero total de pa parrt%"ulas @a/ en el in"remento !'(+2(( mallas TAB$A DE DATO7 MA$$A
6 & 8 !( !6 2( 28 ,' 68 &' !(( !'( 2(( 4an
ABERTRA RACCIO9 DE$ TAMIZ DE MAA Dpi -mm. RETE9IDA Fi 6&HH ,,23 2,&2 !&'! !!&8 (8,, ('8H (6!3 (2H' (2(8 (!63 (!(6 ((36
((((( ((2'! (!2'( (,2(3 (2'3( (!'H( ((',8 ((2!( ((!(2 (((33 ((('8 (((6! (((,! (((3'
D MEDIO 4ARTIC$A E9 E$ I9CREME Dpi mm 6(!, 286' 2((3 !6(H !((! (3!! ('(, (,'& (2'2 (!38 (!2& ((8H ((,3
RACCIO9 ACM$ATI GA I9E I9 ERI RIOR OR A Dpi !(((( (H36H (86HH ('2H2 (2322 (!!,2 (('H6 ((,86 ((282 ((2(' ((!63 ((!(& (((3' (((((
O$CIO9 4OR E$ METODO DIERE9CIA$7
9 TAMIZ 6a& &a8 8 a !( !( a !6 !6 a 2( 2( a 28 28 a ,' ,' a 68 68 a &' &' a !(( !(( a !'( !'( a 2((
Dpi prom 6(! , 286 6' 2(( &' !6( H' !(( (' (3! ! ('( , (,' & (2' !' (!3 3' (!2 '' ((8 H
umato ria
-Dpi prom.K, &6&2&(, (2 2,(!',& 222 8(382', 33' 28((2,H H(3 !((!'(( 3' (,'H62' 6,! (!232&, '23 ((6'!!8 (!& ((!'H(3 H6! (((''H2 ,'H (((!H3& &'& ((((3(6 H&H
Fi ((2 '! (!2 ' (,2 (3 (2' 3 (!' H ((' ,8 ((2 ! ((! (2 ((( 33 ((( '8 ((( 6! ((( ,! ((( 3'
Fi+Dpi prom (((&2'6 &32 ((6,H66 6'6 (!'H8,( ''! (!82,,6 !&! (!'8H2( '6 ((3'&&8 (3, ((6!36H '(, ((28&'! &8' ((,(&!& ,(2 ((,2&3& ('& ((,2&&H ,2, ((,68,! 6&!
Fi+-Dpi Fi L Dpi prom.K, prom ((((,88 (!((32& ,88 , ((('6,! (,'''&2 !'' ' ((,H&HH (&6,686 !36 '' ((H!333 (,&226! 8'! ' (!'83&! (!'H(3H 3,8 ' (!6H&8, ((,82'! ,6, 8 (!&'(!! H28 ((!('&, (22&(3, (((,&,! 33! 2 (686(,6 (((!H,& HH '' !(,3!2H (((!(2H ,62 ' 2(362(H (((('!6 388 '' 6,H3,'& ((((23' 68 H
(828!6& 38!
882H''3 H63
4rimero @allamos el área total / la super"ie espe"i"a7 Aw =
6∱
n
X i
∑ ρ Ф = D p
i 1
pi
!&332H& 8'
(
0,001884 g 3
mm
Aw =
)
0,571
(3(,!H2'36
6 (1 )
¿❑ ¿ ×
Aw =3965,2 ×( 0,828147 ) Aw =3283,768
4ara @allar la super"ie espe"i"a di:idimos entre !F i 7 3283,768
Aw =
1 − X i
N tenemos que Fi1(((3' Aw =
3283,768
Aw =
3283,768
1−0,0075
0,9925
=3308,58 mm2 / seg
A@ora @allamos 97 Nw =
n
X i ∑ ρ p a i=1 D´ 3 1
pi
Nw=
1
(
0,00265 g
mm
3
)( )
× ( 8,829557947 )
2
Nw = 188,679 ×( 8,829557947 )
Nw =1665,952
4ara @allar el 9 espe"i"o di:idimos entre !Fi 7 Nw especifico=
Nw especifico=
1665,952 1 − X i 1665,952 0,9925
Nw especifico =1678,54 particulas / g
A@ora @allamos D:7
[ ] 1
´ = Dv
n
i=1
[(
3
X
∑ D i
´ = Dv
1
3
pi
1 8,8295579
)]
1 3
´ =0,48382 mm Dv
A@ora @allamos el diámetro medio :olumen de super"ie7
´ = Dsv
1 n
X
∑ D i i =1
pi
´ = Dsv
1 0,828147
´ =1,20751 mm Dsv
allamos el diámetro medio de masa7
´ = Dw
n
X D ∑ = i
pi
i 1
´ =1,6772 mm Dw Cal"ulamos el n?mero de part%"ulas en el in"remento !'(+2(( mallas7 N i=
X i 3 a ρ p D´ pi
N 150 / 200=
N 150 / 200=
X 150 /200 ´ /200 3 a ρ p D pi 150
0,0031
( 2 ) ( 0,00265 ) (0,00070496 )
N 150 / 200= 829,70 particulas / g
A@ora @allamos la 0ra""i>n del n?mero total de part%"ulas7 829,70 1665,952
× 100= 49,8
allamos el diámetro medio aritm=ti"o7 9 TAMIZ 6a&
-Dpi prom.K 9i P Dpi , Fi 9i prom &6&2&( ((3,2 (2H6(3'H , ((2'! 8! &&
&a8 8 a !( !( a !6 !6 a 2( 2( a 28 28 a ,' ,' a 68 68 a &' &' a !(( !(( a !'( !'( a 2(( umato ria
2,(!', &2 8(382' ,8 28((2, HH !((!'( (8 (,'H62 '6 (!232& ,' ((6'!! 8 ((!'H( 3H (((''H 26 (((!H3 &3 ((((3( '
(!2' (,2(3 (2'3 (!'H ((',8 ((2! ((!(2 (((33 ((('8 (((6! (((,! (((3'
!(263 6& 36H(6 ! !3,!& '8 2HH'' (6 28262 !6 ,!!,6 ,, 62&'' 6, H!,23 ,& !H'&8 68 ,H!,& (, 82H&8 HH
2H!68H(& ' !'(2H'(3 H6 266(33!, , 2HH3((22 6H 2((8(!&! &' !'&&('&& (, !'!8',,2 '2 22H&88,( !8 ,63,6(68 32 6H!!'322 ,, 3,8626(! 2&
!&&'H ,(62(,23 '6 ,
n
n
∑ N i D pi ∑ N i D pi
i =1 D´ N = n
=
i =1
∑ N i
N t
i =1
304,203273 =0,1826 D´ N = 1665,954
4OR E$ METODO DE $A I9TEQRA$7 9 TAMIZ
Dpi 6&HH 6 ,,23 &
-Dpi. K,
Fi !(,3' ((2'! &3 ,&82& ,,
Fi - a"umulati:o . ((2'!
(!2'
(!'(!
2,&2 8 !&'! !( !!&8 !6 (8,, 2( ('8H 28 (6!3 ,' (2H' 68 (2(8 &' (!63 !(( (!(6 !'( ((36 2((
!,!33 3 6'((2 H3 !'H,6 !6 ('38( ! (2(6, ,& ((32' !2 ((2'& 32 (((8H HH (((,! 33 (((!! 2' ((((6 ('
(,2(3 (63(8
(2'3 (3238
(!'H (88&8
((',8 (H6(&
((2! (H&!&
((!(2 (H3!8
(((33 (H3H'
((('8 (H8',
(((6! (H8H6
(((,! (HH2'
(((3' !
4rimero @allamos el área total / la super"ie espe"i"a7 Aw =
(
6∱
ρ p
1
mm
pi
0
0,00265 g
Aw =
d X i
∫ Ф D
3
6 (1 )
)
0,571
¿❑ ¿ × 1,47364
Aw =3965,2 ×( 1,47364 )
Aw =5843,27
4ara @allar la super"ie espe"i"a di:idimos entre !F i 7 Aw =
5843,27 1 − X i
N tenemos que Fi1(((3' Aw =
Aw =
5843,27 1−0,0075
5843,27 0,9925
=5887,42 mm 2 / seg
A@ora @allamos 97 Nw=
1
ρ p
1
∫ a 0
dX i 3 D´ pi
Nw=
1
(
0,00265 g
mm
3
)( )
× ( 9,95504 )
2
Nw = 188,679 ×( 9,95504 )
Nw=1878,31
4ara @allar el 9 espe"i"o di:idimos entre !Fi 7 Nw especifico =
1878,31
Nw especifico =
1878,31
1 − X i
0,9925
Nw especifico=1892,50 particulas / g
A@ora @allamos D:7
[ ]
´ = Dv
1
1
[(
´ = Dv
3
dX i
∫ D 0
1
3
pi
1 9,95504
)]
1 3
´ =0,465 mm Dv
A@ora @allamos el diámetro medio :olumen de super"ie7
´ = Dsv 1
1
dX i
∫ D 0
pi
´ = Dsv
1 1,47364
´ =0,679 mm Dsv
DAIRA $Z ONO RIGERA CARME9 $CIA E4I9OA ARAJO