Sol uti on to Pr oblem 203 Str ess- str ai n Di ag r am | St Str eng th of M ater i als Revi ew
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Solution to Problem 203 Stress-strain Diagram Tags: stre stress-stra ss-strain in diagr diagram am yie yield ld poin pointt ul ulti tim mate streng strength th rup ruptur ture e strength strength pro propor porti tiona onall lim limit mod odul ulus us of el elasti asticity c ity
Problem 203 The following data were recorded during the tensile test of a 14-mm-diameter mild steel rod. The gage length was 50 mm.
Lo ad (N)
Elo n g atio n (mm)
Lo ad (N)
Elon g atio n (mm)
0
0
46 200
1 .2 5
6 310
0.010
52 400
2 .5 0
12 600
0.020
58 500
4 .5 0
18 800
0.030
68 000
7 .5 0
25 100
0.040
59 000
1 2 .5
31 300
0.050
67 800
1 5 .5
37 900
0.060
65 000
2 0 .0
40 100
0.163
65 500
F racture
41 600
0.433
Plot the stress-strain diagram and determine the following mechanical properties: (a) proportional limits; (b) modulus of elasticity; (c) yield point; (d) ultimate strength; and (e) rupture strength. Solution 203 Click here to to show or hide h ide the solution Area, A = 0.25 0.2 5π(14 2) = 49 π mm2 Length, L = 50 mm Strain = Elongation/Length Stress = Load/Area Lo ad (N)
Elo n g atio n (mm)
Str ain (mm/mm)
Str e ss (M Pa)
0
0
0
0
6 310
0.010
0.0002
40.99
12 600
0.020
0.0004
81.85
18 800
0.030
0.0006
122.13
25 100
0.040
0.0008
163.05
31 300
0.050
0.001
203.33
37 900
0.060
0.0012
246.20
40 100
0.163
0.0033
260.49
41 600
0.433
0.0087
270.24
46 200
1.250
0.025
300.12
52 400
2.500
0.05
340.40
58 500
4.500
0.09
380.02
68 000
7.500
0.15
441.74
59 000
12.500
0 .2 5
383.27
67 800
15.500
0 .3 1
440.44
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