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Pump Foundation Design.pdf
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DESIGN OF P!P FONDATION '(eference: 4o&ndation nal6sis and Design> 5th dition %6 ?oseph . @owles> @ N !!2AA:2##B A Design of Concrete tr&ct&res (einforced Concrete A nal6sis and Design %6 .. (a6* Description: ACF FEED Pumps Tag No.: WT3-P-74001A/B A. Input Data γconc = 25
kN/m
3
Unit weight of reinforced concrete
3
Unit weight of soil
γsoil =
!
kN/m
"all =
5#
k $a
2.,#
kN
Net allowa%le %earing press&re '(eference: )))) ))))** mpt6 weight of p&mp with #7 additional to acco&nt for the weight of the
+p e =
connected pipes '+p e = .#825#8!.9/###*
B X
Fy Fx
My
"pe
Mx Y
Y
Z
A ep
Fy
hp
Fy
ax
Fz
hf
Fx
My
Mx
Mx
xA
X
NOZZLE CENTERLINE LEVEL (SUCTION & DISCARGE! GRADE GRADE LEVEL LEVEL
#OINT A
B
ay
SECTION 'T(N;(*
PLAN
"pe
"pe
Fx Fz
Z
Fx
My
Fz
My
NOZZLE CENTERLINE LEVEL (SUCTION & DISCARGE! ep hp hf
xB A
SECTION '
-aim&m ndi0id&al No11le oading &ction 4orces and -oments:
#OINT B
GRADE GRADE LEVEL LEVEL
4s =
#.B#9
kN
$&mp load along hori1ontal Adirection
46s =
B.2,#
kN
$&mp load along hori1ontal 6Adirection
41s =
B.2,#
kN
$&mp load along 0ertical 1Adirection
-s =
.,22
kNm
-oment along hori1ontal Adirection
-6s =
#.2!9
kNm
-oment along hori1ontal 6Adirection
-1s =
#.2!9
kNm
-oment along 0ertical 1Adirection
Discharge 4orces and -oments: 4d = E.22, kN $&mp load along hori1ontal Adirection 46d =
E.##5
kN
$&mp load along hori1ontal 6Adirection
41d =
B.B5E
kN
$&mp load along 0ertical 1Adirection
-d =
#.9!5
kNm
-oment along hori1ontal Adirection
-6d =
#.9!5
kNm
-oment along hori1ontal 6Adirection
-1d =
#.9!5
kNm
-oment along 0ertical 1Adirection
eps =
#.9B
m
&ction p&mp loads eccentricit6
epd =
#.9B
m
Discharge p&mp loads eccentricit6
hp =
#.2#
m
Thickness of plinth 'incl&ding gro&t thickness*
hf =
#.B#
m
Thickness of fo&ndation pad
= @= a =
B.## 2.## #.,5
m m m
ength of pad along Adirection +idth of pad along 6Adirection ength of plinth along Adirection
a6 =
#.,5
m
ength of plinth along 6Adirection
p =
#.5E
m
2
rea of plinth 'p = a 8 a6*
m
2
rea of fo&ndation pad ' f = 8 @*
f =
9.##
B. B"a#$n% P#"ssu#" C&"'( -add = E. kNm
dditional moment a%o&t A '-add = 2846s8'epsFhpFhf * F 2846d8'epdFhpFhf **
-6add =
2E.#9
kNm
dditional moment a%o&t 6A6 '-6add = 284s8'epsFhpFhf * F 284d8'epdFhpFhf **
+ p =
5.E3
kN
+eight of each plinth '+ p = $%&'% ( Ap ( hp!
+ f =
9#.##
kN
+eight of fo&ndation '+ f = $%&'% ( Af ( hf !
$=
3B.#
kN
Total 0ertical load G$ = 28'+p eF+ pF41sF41d* F + f H
- =
2.35
kNm
Total moment a%o&t A G- = 28'- s F -d* F -addH
-66 =
29.B,
kNm
Total moment a%o&t 6A6 G-66 = 28'-6 sF-6d* F -6addH
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