Home
Add Document
Sign In
Register
Mathematics Form3
Home
Mathematics Form3
...
Author:
Intan Adriana
30 downloads
543 Views
233KB Size
Report
DOWNLOAD .PDF
Recommend Documents
Affidavit of Discrepancy-Form3
Affidavit of Discrepancy-Form3Full description
Mathematics
mathematics
mathematics exercise
Mathematics
preboard reviewer for mathFull description
Mathematics
Mathematics
Mathematics
Form3 SK Development and Financial Plan
Full description
Dinesh Mathematics
Mathematics Book for IITians
Discrete Mathematics
Lab Manual For Discrete Maths SEM #3 (As per syllabi of 2015-16)Full description
Engineering Mathematics
Full description
Engineering Mathematics
Mathematics
Vedic Mathematics
Mathematics Today
Análisis de los más recientes descubrimientos y avances en la matemática moderna.
GRE Mathematics
GREFull description
B.sc. Mathematics
Full description
Mathematics Books
M
Mathematics Books
MFull description
Dinesh Mathematics
Mathematics Book for IITiansFull description
Discrete Mathematics
A book on Discrete Mathematics usefull in Computer Science and Math courses in general.
Actuarial Mathematics
A great ebook on Actuarial Science. Presented in a simple but accurate way.Full description
Business Mathematics
Niche
Foundation Mathematics
summary and contents of the book - Foundation Mathematics by K Stroud
Engineering Mathematics
Descripción: fz
Engineering Mathematics
GATEFull description
Fast Track to Success: Success Maths PMR (Form 3) Paper 2 Questions (Fully-Worked (Fully-W orked Solutions) 5 (a) 3p – 18 pq = 3 p(1 – 6q) (b) 3e2 – 108 = 3( e2 – 36) = 3( e2 – 6 2) 3(ee – 6)(e 6)(e + 6) = 3(
Chapter 5: Indices 1 42 x – 1 = (2 x)(23) 22(2 x – 1) = 2 x + 3 2(2 x–1) = x + 3 4 x – 2 = x + 3 4 x – x = 3 + 2 3 x = 5 5 x = — 3 1 — 2
2 2 × 12 × 3 3
5 — 2
1 — 2
= 2 × (2 × 3) × 3 3
6 20 – 5m2 = 5(4 – m2) = 5(22 – m2) = 5(2 + m)(2 – m)
2
1 —
7 (a) 3 x + 9 = 3( x + 3) (b) 32 – 2y 2 = 2(16 – y 2) = 2(42 – y 2) )(4 – y ) = 2(4 + y )(4
5 — 2
5 —
= 23 × 2 × 3 2 × 3 2 1 + 5 — —
= 23 + 1 × 3 2 2 = 24 × 33 = 16 × 27 = 432 m5 × m2 m5 + 2 3 ———— = ——— –3 m m–3 = m7 – (–3) = m10 2 —
5 —
4 (a) 6 3 ÷ 6 3 2 5 —–— 3
= 63 = 6–1 1 =— 6
1 1 – —p 5 3 8 —– – ————— 3m
mp
(b) (pq5)2 × p3 = p2q10 × p3 = p2+3q10 = p5q10
Chapter 6: Algebraic Expressions (III) 1 (2 x – 3) 2 – (5 x + 4) = 4 x2 – 12 x + 9 – 5 x – 4 17 x x + 5 = 4 x 2 – 17 2 (a – 2 b)2 + b(2a – 3 b) = (a2 – 4 ab + 4 b2) + (2ab – 3b2) = a2 – 2ab + b2 = (a – b)(a – b) = (a – b)2 3 (a) p(7 + q) = 7 p + pq (b) (5m – n)2 = (5 m – n)(5m – n) = 25 m2 – 10mn + n2 4 (a) 10ab – 5 a2 (2b = 5a(2 b – a) 2 (b) x – 5( x + 2) – (5 – 7 x) = x2 – 5 x – 10 – 5 + 7 x = x2 + 2 x – 15 3)( x + 5) = ( x – 3)( x
1 5p – 3 1 – —p 3 = ———————— 3mp 5p – 3 + p = ————– 3mp 6p – 3 = ———– 3mp 1 3(2p – 1) = ————– 1 3mp 2 p – 1 = ———– mp m+5 2 6m – m – 5 9 –— – –——– = –——–——– 5m 15m2 15m2 5m – 5 = –——–– 15m2 1 5(m – 1) = –——–— 2 3 15m m–1 = –——– 3m2
1 4–v 3v – 4 + v 10 –— – –——– = –——–—— 4m 12mv 12mv 4v – 4 = –——–– 12mv 1 4(v – 1) = –——–— 3 12mv v – 1 = –——– 3mv
Weblink
1
Chapter 7: Algebraic Formulae 3(p – 1) 1 –——–— = 7 k 3(p – 1) = 7k 7k p – 1 = –— 3 7k p = –— + 1 3 7k + 3 p = –——–– 3 6y – 1 2 –——–– = 4 y + 2 p 6y – 1 = 4y + 8 p 2y = 8 p + 1 8p + 1 y = –——–– 2 1 y = —(8 p + 1) 2 8n – nk 3 F = –——–– 3 3F = n(8 – k) 3F n = –——– 8– k 2 4 p +3 = q p2 = q – 3
Chapter 10: Transformation (II) 2 40°
85°
55°
85°
40°
55°
(a) The corresponding angle to ∠HFG is RPQ.. RPQ
(b) The corresponding side to FG is PQ PQ..
Chapter 12: Linear Inequalities 4 5 – 3 x 4 – x –3 x + x 4 – 5 –2 x –1 1 x — 2 5 (a) m – 5 2 m 2+ 5 7 m (b) 7 + 4n 10 – 2n 4n + 2 n 10 – 7 6n 3 1 — n 2
p = √q – 3
6 (a) 2 + x 7 x 5 x (b) — – 4 1 3 x —5 3 x 15
Chapter 9: Scale Drawings 1
9
10
9 – x ∴ x
11
12
13
0 9
14
15
1 cm
∴ 9 x 15 ⇒ x = 10, 11, 12, 13, 14, 15
1 cm
2
x 7 — 3 x
1
3
1 – 2 x –2 x x
–3
–2
–1
0
∴ –3 x 3 ⇒ x = –2, –1, 0, 1, 2, 3
2
Weblink
1
2
7 6 –3
3
Chapter 13: Graphs of Functions 7 y
AB = 8 cm AC = √82 + 62 = 10 cm 8 DE sin y ° = –— = –— 17 AE
12
AD = √172 – 8 2 = 15 cm ∴ CD = AD – AC = 15 – 10 = 5 cm
10
8
6
4
2
–2
–1
0
1
2
–2 –4 –6
–8
Chapter 15: Trigonometry AB 1 tan x° = –— BM BC = √172 – 82 = 15 cm 15 BM = –— 2 16 8 tan x° = ——– = —– 15 15 —– 2 5 2 cos PRQ = — 7 5 ∴ cos x° = – — 7 3 3 tan x° = — 4 BC = –— AB 6 = –— AB 3 6 ⇒ — = –— 4 AB
3
4
x
3 AD 4 (a) tan x° = — = –— 4 BD 3 9 ⇒ — = –— 4 BD BD = 12 cm BD cos x° = –— AB AB = √122 + 92 = 15 cm 4 12 ⇒ cos x° = –— = — 5 15 4 BD (b) sin y ° = — = –— 7 CD 4 12 ⇒ — = –— 7 CD CD = 21 cm LM 5 5 (a) cos x° = –— = –— 13 26 5 LM ⇒ –— = –— 13 26 LM = 10 cm KM = √262 – 102 = 24 cm 12 KM 24 ∴ tan x° = –— = –— = –— 5 LM 10 8 16 (b) sin y ° = –— = –— 17 PN ⇒ PN = 34 cm PM = √342 – 16 2 = 30 cm ⇒ KMP = KM + PM = 24 + 30 = 54 cm
Weblink
3
×
Report "Mathematics Form3"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
×
Sign In
Email
Password
Remember me
Forgot password?
Sign In
Our partners will collect data and use cookies for ad personalization and measurement.
Learn how we and our ad partner Google, collect and use data
.
Agree & close