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Laterally Loaded Piles Broms
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Laterally Loaded Piles Broms
Laterally Loaded Piles BromsFull description...
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ASCE - Lateral Resistance of Piles in Cohesive Soils - March 1964 - By Bengt B Broms
Design of piles
q = 10 kN/m (No access)
2
Ph = 46 kN = 19.8 kN/m 2 cu = 50 kN/m s
1.17m
3
p = 17.5 kN/m2
s = 19.8 kN/m
cu = 50 kN/m
3
2
D
Actual Structure
Calculation Model (For soldier pile stability and integrity)
2
At z = 0 m bgl :
p
= 1.0×10 - 2×50 = -90.00 kN/m
At z = 3.5 3.5 m bgl bgl :
p
= 1.0× 1.0×(1 (10 0 + 3.5× 3.5×19 19.8 .8)) - 2×50 ×50 = -22. -22.68 68 kN kN/m /m < 0
2
2
MEFP= 5z = 5×3.5 = 17.50 kN/m
(From: CIRIA Special Publication 95, p. 36)
Ph = ½×17.5×3.5 = 30.63 kN/m × 1.5m = 45.95 kN/№ yh = ⅓ × 3.5 = 1.17 m
MEFP governs
The stability and integrity of the soldier piles will be assessed according to a laterally loaded pile by the method of Broms (refer charts next page).
□
DESIGN LOAD FH = e= ɣ Lf FH =
□
PILE DATA Pile Top Condition:
46 kN/ № 1.17 m 64.4 kN/ №
{ Horizontal load } { Load application from GL } (( ɣLf = 1.4 ))
FREE
Pile Size: H-200x200x8x12 My = py Sx = b OR d = D OR L = □
▪
275 N/mm² ))
=
19 kN/m³
{ Average unit weight of soil }
cu =
50 kN/m²
{ Ave undr shear strength }
SOIL DATA
CAPACITY AS SHORT PILE Ultimate Lateral Resistance in Cohesive Soils (( L/d = 17 e/d = 5.85 )) Hu,c =
▪
(( py =
{ Breadth of pile } { Embedment of pile }
Hu,c / (cu d²) =
□
525 cm³ ))
0.2 m 3.4 m
ɣs
□
144.375 kNm/№
(( Sx =
33.28
{Read from chart}
66.57 kN/№
CAPACITY AS LONG PILE Ultimate Lateral Resistance in Cohesive Soil s (( My / (c u d³) =
360.9
Hu,c / (c u d²) =
45.18
Hu,c =
e/d =
5.85 )) {Read from chart}
90.37 kN/№
Apply factor by embedment, provide embedment length D = 1.2 × 3.4 = 4.08m Required total length of soldier pile = 3.50 + 4.08 = 7.58 say 8.0m
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