Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level
CHEMISTRY
9701/11
Paper 1 Multiple Choice
May/June 2017
MARK SCHEME Maximum Mark: 40
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for
9701/11
Cambridge International International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
1
C
1
2
D
1
3
A
1
4
C
1
5
B
1
6
A
1
7
D
1
8
C
1
9
B
1
10
C
1
11
B
1
9701/11
Cambridge International International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
1
C
1
2
D
1
3
A
1
4
C
1
5
B
1
6
A
1
7
D
1
8
C
1
9
B
1
10
C
1
11
B
1
9701/11
Cambridge International International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
29
A
1
30
B
1
31
B
1
32
D
1
33
D
1
34
A
1
35
D
1
36
A
1
37
B
1
38
D
1
39
B
1
Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level
CHEMISTRY
9701/12
Paper 1 Multiple Choice
May/June 2017
MARK SCHEME Maximum Mark: 40
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for
9701/12
Cambridge International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
1
B
1
2
B
1
3
C
1
4
D
1
5
A
1
6
D
1
7
C
1
8
C
1
9
A
1
10
A
1
11
C
1
9701/12
Cambridge International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
29
D
1
30
C
1
31
B
1
32
C
1
33
C
1
34
A
1
35
B
1
36
A
1
37
B
1
38
B
1
39
A
1
Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level
CHEMISTRY
9701/13
Paper 1 Multiple Choice
May/June 2017
MARK SCHEME Maximum Mark: 40
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for
9701/13
Cambridge International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
1
A
1
2
D
1
3
B
1
4
B
1
5
D
1
6
B
1
7
A
1
8
B
1
9
A
1
10
B
1
11
B
1
9701/13
Cambridge International AS/A Level – Mark Scheme PUBLISHED
Question
Answer
May/June 2017
Marks
29
A
1
30
C
1
31
C
1
32
B
1
33
A
1
34
B
1
35
A
1
36
A
1
37
A
1
38
D
1
39
C
1
Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level
CHEMISTRY
9701/21
Paper 2 AS Level Structured Questions
May/June 2017
MARK SCHEME Maximum Mark: 60
Published
This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers.
9701/21
Cambridge International AS/A Level – Mark Scheme
May/June 2017
PUBLISHED Question
1(a)
Answer
The mass of a molecule OR the (weighted) average / (weighted) mean mass of the molecules Relative / compared to
1 12
(the mass) of an atom of carbon–12
Marks 1
1
OR on a scale in which a carbon–12 atom / isotope has a mass of (exactly) 12 (units) 1(b)(i)
3
1
1(b)(ii)
8
1
1(b)(iii)
C3H8O + 4½O2 → 3CO2 + 4H2O
1
1(b)(iv)
1 AND propan–2–ol / 2–propanol AND propan–1–ol / 1–propanol
Alternative answers (any two): AND butan–1–ol / 1–butanol
AND butan–2–ol / 2–butanol
AND (2–)methylpropan–1–ol / (2–)methyl–1–propanol
AND (2–)methylpropan–2–ol / (2–)methyl–2–propanol
1
9701/21
May/June 2017
Cambridge International AS/A Level – Mark Scheme PUBLISHED Question
1(b)(v)
Answer
Marks
correct conversions of data to SI/consistent units p = 100 000 ; V = 20 × 10 –6 ; T = 393
1
calculation of n ( = pVIRT) from M1 values 100 × 103 × 2 0 ×10-6 n= 8.31×393
1
calculation of mass m ( = n × Mr) AND answer correct to 3sf m = 6.12 × 10 –4 × 60 = 0.0367 (g)
1
Alternative answer for using C4H10O: m = 6.12 × 10 –4 × 74 = 0.0453 (g) Total:
Question
2(a)
2(b)(i)
Answer
10
Marks
substance
type of bonding
type of lattice structure
copper
metallic
giant/metallic
ice
covalent OR hydrogen(-bonding) / H(–bonding)
hydrogen-bonded / simple / molecular
1
silicon(IV) oxide
covalent
giant (molecular) / macromolecular
1
iodine
covalent
simple / molecular
1
sodium chloride
ionic
giant / ionic
1
hydrogen bonding
1
1
9701/21
May/June 2017
Cambridge International AS/A Level – Mark Scheme PUBLISHED Question
2(b)(ii)
Answer
H-bond between O and H of different molecules
1
minimum three partial charges (in a row) over two H2O molecules, i.e.: