PULLEY & BELT CALCULATION 1. Selection of belt belt section :
Select the type of a belt depending on the power to be transmitted. (see V-Belt Table in pg no:7.58 )
Example :
Motor power = 100 kW Motor speed(N1) = 1440 rpm Pump speed(N2) = 340 rpm
For power 100 Kw,D section is selected. (see V-Belt Table in pg no:7.58 )
2. Selection of pulley diameters (d and D)
For power given, select small pulley diameter diameter (d) from V-Belt Table in pg no: no: 7.58.then using the speed ratio, ratio, Calculate the larger pulley diameter (D). Speed ratio =
=
These pulley diameters should be rounded off to a standard diameter by using Table in (pg no:7.54). For Power 100 Kw, small pulley diameter d = 355 mm For power given,select small pulley diameter diameter (d) from V-Belt Table in pg no: no: 7.58 Speed ratio =
= = 4.235
Larger pulley diameter,, D = Speed ratio x d D = 4.235 x 355 D = 1503.53 mm Preferred larger pulley diameter, D = 1600 mm. Consulting Table, (pg no:7.54). 3. Selection of centre distance (C) :
Considering Speed ratio,
ratio can be obtained (see Table in pg no:7.61).
Centre distance, C = D x (C/D) C max = 2(D+d) C min = 0.55(D+d) +T
Centre distance,C = D x ( (
)
ratio can be obtained see Table in pg no:7.61).
= 1600 x 0.95 C = 1520 mm C max = 2(D+d) = 2(1600+355) C max = 3910 mm C min = 0.55(D+d)+T (T value taken from table,see pg no: 7.58) = 0.55(1600+355)+19 = 1075.25+19 C min =1904.25 mm
4. Determination of nominal pitch length :
Determine the length of the t he belt L ( Which is also known as nominal inside length ) by using formula. 2
L = 2C + ( /2 ) (D + d ) + (D-d) /4C For the Calculated nominal inside length and belt section,Consulting Table in 7.58,7.59 & 7.60),select the next standard pitch length. L = (2 x 1520) + (/2)(1600+355) + = 3040 + (1.57 x 1955) +
= 3040 + 3069.35 +254.938 L = 6364.28 mm
For this nominal inside length and D section,Consulting Table,pg no:7.58,7.59 @ 7.60, the next standard pitch length is selected as 6124 mm 5. Calculation of maximum power capacity :
For selected section,calculate the maximum power capacity (in kW) of a V-belt using the formula given in Table in pg no: 7.62
Where Kw = Maximum power in kW AT 180° arc of contact for a belt of average length, S = Belt speed,
m/s,
De = Equivalent pitch diameter = d p x Fb, dp = Pitch diameter of the smaller pulley = d Fb = Pitch diameter factor to account for variation of arc of contact, from Table in pg no: 7.62 -0.09
kW = ( 3.22 S
-4 2 - 4.78 x 10 S )S
-
maximum power capacity (in KW) of a V -belt using the formula given in Table in pg no: 7.62 where =
S = Belt speed =
= 26.76 m/s de = dp x Fb dp = diameter of the smaller pulley Fb = Small diameter factor, for speed ratio of 4.235, From Table = 1.14 = 355 x 1.14 de = 404.7 0.09
Power, Kw = (3.22 x 26.76
-
-4 2 - 4.78 x 10 x 26.76 )26.76
Power = 21.44 kW
6. Determination of number of belts(nb) :
Determine the number of belts (n b) nb =
(see pg no : 7.70)
P = Motor power, kW, (i) Length correction factor (Fc) : For selected section,referring section,refer ring Table in pg no: 7.58,7.59 & 7.60) Length correction factor (Fc) can be obtained. (ii) Correction factor for arc of contact (Fd) :
Arc of contact = 180° - (
) x 60°
For this arc of contact, consulting Table in pg no 7.68,correction factor for arc of contact is selected. (iii) Service factor (Fa) : Consulting Table in pg no 7.69 Select the service factor (Fa). Note: The details of driving units & driven machines under different duties are available in the data book,pg no 7.69 Kw = Rated power
nb =
(see pg no : 7.70)
FC= 1.00 referring Table in pg no: 7.58,7.59 & 7.60) Arc of contact,= 180° - (
) x 60°
For this arc of contact, consulting Table in pg no 7.68, correction factor for arc of contact is selected.
) x 60°
= 180° - (
= 180° - (
) x 60°
= 130.85° For,130.85°,consulting Table,correction factor for arc of contact,Fd= 0.86 Service factor, consulting Table ,Fa= 1.3 nb =
nb = 7.05 nb = 7 Belts
7.Calculation of actual centre distance:
C = A + √ Where
A = - ( B=
)
C = A + √ A=
- ( )
A=
- ( )
= 1531 – 1531 – 3.14(244.375) = 1531 – 1531 – 767.337 A = 763.663 B= B=
B=
B = 193753.125
C = 763.663 + √ C = 763.663 + √
C = 763.663 + √ C = 763.663 + 624.041 C = 1387.704 mm
8. Calculation of belt tensions (T 1-T2) :
Power transmitted per belt = (T1-T2)v
…… (i)
Determine mass per metre length( see Table in pg no : 7.58) Determine groove angle (2β) = 34° ( see Table in pg no : 7.70) Already found that arc of contact for smaller pulley, α =
radians
We know that the tension ratio for V-belts considering centrifugal tension, = e^µα/sin β = e^µα. βcosec
Solving (i) & (ii), T 1 & T2 can be obtained Power transmitted per belt = (T1-T2)v = (T1-T2)26.76,
…….(ii)
S = v = Belt speed =
= = =26.76 m/s
= (T1-T2)
(T1-T2) = 467.12
……..(i) ……..(i)
Mass per metre length m = 0.596 kg/m ( see Table in pg no : 7.58) groove angle (2β) = 34° see Table in pg no : 7.70) Arc of contact, α = 180° - ( α = 180° - (
) x 60°
) x 60°
α = 180° - (
) x 60°
α = 130.85° α = 2.283 radians The tension ratio for V-belts considering centrifugal tension, = e^µα/sin β = e^µα. Cosec β = e^0.3x2.283. Cosec 17° = 10.53
T1-10.53T2 = -4067.79 -4067.79
……..(ii)
Solving (i) & (ii),we get T1 = 942.93 N T2 = 475.81 N 9. Calculation of stress induced: i nduced:
Consulting Table in pg no 7.58,cross-sectional area of selected section =
2
mm
Stress induced = N/mm^2
Consulting Table in pg pg no 7.58,cross-sectional area area of selected section = Stress induced = N/mm^2 Stress induced = = 1.985 N/mm^2
2
475 mm
10.Maximum power transmitted :
P = (T1-T2)v v = S = 26.76 m/s
T1 = 942.93 N T2 = 475.81 N P = (T1-T2)v P = (942.93-472.81)26.76 P = (470.12)26.76 P = 12.58 kW
