Decanter Mass Balance-09!07!2007 Sati Sir

12/24/2012

1

Decanter mass balance calculations Basis Sludge feed rate Solids in sludge Solids in cake TSS in centrate Sp. gr feed sludge Sp. gr cake Sp. gr centrate

1 hr 3 43 m 2.0% 24.0% 0.60% 1.02 1.07 1.01

Polymer consumption, kg/ton 3 Polymer feed rate 1.4 m /hr  Polymer concentration 0.5% Polymer consumption = 1000kg/ton x (Poly. feed rate x poly. conc.) (Sludge feed rate x Feed solids) = 1000kg/ton x 1.4 m3/hr x0.5 43m3/hr x 2 = 8. 8.14 kg/ton solids

W et solids Dry solids

43860 kg 878 kg

Solids loading, ton/hr   Feed solids (%/100) x Sludge feed m3/hr   0.860 0.860 ton/hr  ton/hr 

Solids in feed = Solids in cake + Solids in centrate Dry solids = Cake volume * Sp Gr of cake * % Solids +Centrate volume*Sp Gr of centrate*% Soilds in centrate 878 = S(liter) x1.07x0.24 + F(liter) x1.01x 0.006 Centrate capture or TSS recovery R = TSSP (TSSF - TSSC ) x 100 TSSF(TSSP - TSSC)

Sludge flow = cake flow + centrate flow

72%

43000 = S+F S = 43000 - F 878 = (43000 - F) x 0.2568 + Fx 0.00606 3 Cent Ce ntra rate te vo volu lume me,, F = 40.5 m Cake volume, S = 2.5 m Centrate Mass DS Tons = Centrate Volume* Cenrate % solids

0.25

Cake Mass DS Tons=Cake volume *Cake % solids

0.63

Mass Balance Sum

0.878

Polymer consumption, kg/ton 3 Polymer feed rate 1.4 m /hr  Poly Polyme merr conc concen entr trat atio ion n 0.5% 0.5% Polymer consumption = 1000kg/ton x (Poly. feed rate x poly. conc.) (Sludge feed rate x Feed solids-Cenrate Solids) Polymer consumption Kgs/ton of dry solids

Mafraq-W wTW -Sludge Management

11.62790698

Zaffrulla -Decanter mass balance

You have mentioned the following Centrate Mass DS Tons = Centrate Volume*Cenrate % solids Cake Mass DS Tons=Cake volume *Cake % solids Mass Balance Sum

0.24 0.59 0.83

These rows i have highlighted in your excel sheet ( Attached ) What do you mean by this What conclusion can be drawn from the figure 0.83 % ....Please advise When i compare the decanter feed of 43 m3/hr with centrate volume and cake volume ( please advise sir

MASS BALANCE SUM what does this indicate ??

0.5+ 2.5 m3) it matches to 43 m3/hr -Highlighted in red font