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1) Weight Weight of conduc conductor tor/le /lengt ngth, h, w W = (1145k (1145kg/k g/km m ÷ 100 1000) 0) x 2 (where (where no. no. of conduc conductor tor/s /span pan = 2, or or accor accordin ding g to design) = 2.29kg/m 2)
XL = 2.28m .28m + 2.2 2.28m 8m x 0.4 0.473 73m m 2 8 x 0.15m = 2.0387m
3)
XR = 2.28m .28m - 2.28m .28m x 0.473 .473m m 2 8 x 0.15m = 0.2413m
4)
H = 2.29kg/m x (2.28m)2 8 x 0.15m = 9.92kg
5)
L = 2.28m + [(2.0387m)3 + (0.2413m) 3] x [(2.29kg/m) 2 /{6 x (9.92kg)2}] = 2.36m
6)
DR = 2.29k .29kg/ g/m m x (0 (0.24 .2413m) 13m)2 2 x 9.92kg = 6.72 x 10-3m
7)
DL = 2.29k .29kg/ g/m m x (2 (2.038 .0387m 7m))2 2 x 9.92kg = 0.48m
8)
TR = 9.92 9.92kg kg + 2.2 2.29kg/ 9kg/m m x 6.7 6.722 x 10-3m = 9.94kg = 97.37N
9)
TL = 9.92 9.92kg kg + 22.2 .29k 9kg/ g/m m x 0.48m .48m = 11.02kg = 107.99N
CONCLUSION The conductor tension must be less than the Terminal Load capacity of both CT and LISO, for any size of AAC selected.
Plan view of of typical substation arrangement need to be review to get the actual conductor span, where the span between equipment/support might be varies at different phases when view from the top.
