Combine 8 Bank Math Solution From Www.affairscloud

Combine 8 Bank Math Solution www.affairscloud.com all math copied from www.affairscloud.com Q-1: Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance dist ance between A and B is 50 km. what is the t he speed of the slower rabbit? Explanation: Let second rabbit takes x hr with speed s2 First rabbit takes x-5/6 hr with speed s1 Total distance = 50km S1 = 50/(x-(5/6)) S2= 50/x As they cross each other in 1hr… Total speed = s1 + s2  Now, T = D / S 50/(s1+s2) = 1 x = 5/2, 1/3 Put x= 5/2 in s2 –  s2  – > 20km/hr Answer:20 kmph

Q-2: A Bag contains some White and Black Balls. The probability of picking two white ball s one after other without replacement from that bag is 14/33. Then what will be the probability of picking two Black balls from that Bag if ba g can hold maximum 15 balls only? Explanation: Wc2/ (B+W)c2 = 14/33 W (W-1)/(W+B)*(B+W-1) = 14/33  Now expressing 14/33 in the above above format by multiplying 4 in numerator and denominator W (W-1)/(W+B)*(B+W-1) = 8*7/12*11 (note = balls <15) W =8 W+B =12 B =4 Probability = 4c2/12c2 = 1/11 Answer: 1/11

Combine 8 Bank Math Solution www.affairscloud.com all math copied from www.affairscloud.com Q-3: A jar contains ‘x’ liters of Milk, a seller withdraws 25 liters of it and sells it at Rs.20 per liter. He then replaces it water. He repeated the process total three times. Every time while selling he reduces selling price by b y Rs.2. After this process Milk left in the mixture is only 108 liters so he decided to sell the entire Mixture at Rs. 15 per liter. Then how much profit did he earned if bought Milk at Rs.20 per liter? Explanation: Seller sells Milk at Rs.20,18 and 16 respectively for three times = 25*(20+18+16) = 1350 108 = x(1-25/100) 3 x =256 liter He sold entire 256 at Rs.15 =256*15 = 3840 Cost price = 256*20 = 5120  profit = 5190-5120 = 70 Answer: 70 tk

Q-4: A man rows to a place 40 km distant and back in a total of 18 hours. He finds that he can row 5 km with the stream in the same time as 4 km against the stream. What is the speed of boat in still water? Explanation: Suppose he moves 5km downstream in x hours Then, downstream speed a= 5/x km/hr Speed upstream speed b = 4/x km/hr 40 / (5 /x) + 40 / (4/x) = 18 8x + 10x = 18 x=1 a = 5 km/hr, b = 4 km/hr speed of boat = ½ (5 + 4) = 9/2 km/hr Answer: 4.5 km

Combine 8 Bank Math Solution www.affairscloud.com all math copied from www.affairscloud.com Q-5: Pipe A can fill a Tank in 18 Hours, Pipe B can empty a Tank in 12 Hours, Pipe C can fill Tank in 6 Hours. The Tank is already filled up to 1/6 of its capacity. Now Pipe A is opened in the First Hour alone, Pipe B is opened in the Second Hour alone and Pipe C is opened in the Third Hour alone. This cycle is repeated until the Tank gets f illed. Then in How many Hours does the rest of Tank gets filled? Explanation: In First Hour, Tank filled = 1/6+1/18 Second Hour = 1/6+1/18-1/12 Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled 25/36 is left From then 3 hours work = 1/18-1/12+1/6 = 5/36 5*3 Hours = 5*5/36 = 25/36 Total = 5*3+3 = 18 Hours Answer: 18 Hours

Q-6: A can contains milk and water in the rati o 3:1. A part of this mixture is replaced replac ed with milk, and now the new ratio of milk to water is 15:4. What proportion of original mixture had  been replaced by milk? Explanation: Let total original quantity = x liters, Let y liters replaced. After y liters of mixture drawn out, Milk = [3/(3+1)] * x –  x  –  [3/(3+1)]  [3/(3+1)] * y Water = [1/(3+1)] * x –  x –  [1/(3+1)]  [1/(3+1)] * y  Now y liters of milk poured in can. Milk becomes (3/4)*x –  (3/4)*x –  (3/4)*y  (3/4)*y +y = (3/4)*x +(1/4)*y  Now [(3/4)*x +(1/4)*y] +(1/4)*y] / [(1/4)*x –  [(1/4)*x  –  (1/4)*y]  (1/4)*y] = 15/4 Solve, y = (3/19)* x So 3/19 of original mixture removed Answer: 3/9