AglaSem Schools
H$moS> Z§.
Series OSR
Code No.
amob Z§.
42/1 (SPL)
narjmWu H$moS >H$mo CÎma-nwpñVH$m Ho$ _wI-n¥ð >na Adí` {bIo§ &
Roll No.
Candidates must write the Code on the title page of the answer-book.
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Please check that this question paper contains 16 printed pages. Code number given on the right hand side of the question paper should be written on the title page of the answer-book by the candidate. Please check that this question paper contains 30 questions. Please write down the Serial Number of the question before attempting it. 15 minutes time has been allotted to read this question paper. The question paper will be distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the question paper only and will not write any answer on the answer-book during this period.
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H¥$n`m Om±M H$a b| {H$ Bg àíZ-nÌ _o§ _w{ÐV n¥ð> 16 h¢ & àíZ-nÌ _| Xm{hZo hmW H$s Amoa {XE JE H$moS >Zå~a H$mo N>mÌ CÎma -nwpñVH$m Ho$ _wI-n¥ð> na {bI| & H¥$n`m Om±M H$a b| {H$ Bg àíZ-nÌ _| >30 àíZ h¢ & H¥$n`m àíZ H$m CÎma {bIZm ewê$ H$aZo go nhbo, àíZ H$m H«$_m§H$ Adí` {bI| & Bg àíZ-nÌ H$mo n‹T>Zo Ho$ {bE 15 {_ZQ >H$m g_` {X`m J`m h¡ & àíZ-nÌ H$m {dVaU nydm©• _| 10.15 ~Oo {H$`m OmEJm & 10.15 ~Oo go 10.30 ~Oo VH$ N>mÌ Ho$db àíZ-nÌ H$mo n‹T>|Jo Am¡a Bg Ad{Y Ho$ Xm¡amZ do CÎma-nwpñVH$m na H$moB© CÎma Zht {bI|Jo &
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^m¡{VH$ {dkmZ (g¡ÕmpÝVH$) PHYSICS (Theory)
{ZYm©[aV g_` : 3 KÊQ>o
A{YH$V_ A§H$ : 70
Time allowed : 3 hours 42/1 (SPL)
Maximum Marks : 70 1
P.T.O.
AglaSem Schools
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gm_mÝ` {ZX}e : (i) g^r àíZ A{Zdm`© h¢ & (ii) Bg àíZ-nÌ _| Hw$b 30 àíZ h¢ & àíZ g§. 1 go 8 VH$ Ho$ àíZ A{V-bKwCÎmar` àíZ h¢ Am¡a àË`oH$ EH$ A§H$ H$m h¡ & (iii) àíZ g§. 9 go 18 _| àË`oH$ àíZ Xmo A§H$ H$m h¡, àíZ g§. 19 go 27 _| àË`oH$ àíZ VrZ A§H$ H$m h¡ Am¡a àíZ g§. 28 go 30 _| àË`oH$ àíZ nm±M A§H$ H$m h¡ & (iv) VrZ A§H$m| dmbo àíZm| _| go EH$ _yë` AmYm[aV àíZ h¡ & (v) àíZ-nÌ _| g_J« na H$moB© {dH$ën Zht h¡ & VWm{n, Xmo A§H$m| dmbo EH$ àíZ _|, VrZ A§H$m| dmbo EH$ àíZ _| Am¡a nm±M A§H$m| dmbo VrZm| àíZm| _| AmÝV[aH$ M`Z àXmZ {H$`m J`m h¡ & Eogo àíZm| _| AmnH$mo {XE JE M`Zm| _| go Ho$db EH$ àíZ hr H$aZm h¡ & (vi) H¡$bHw$boQ>a Ho$ Cn`moJ H$s AZw_{V Zht h¡ & VWm{n, `{X Amdí`H$ hmo Vmo Amn bKwJUH$s` gmaUr H$m à`moJ H$a gH$Vo h¢ & (vii) Ohm± Amdí`H$ hmo Amn {ZåZ{b{IV ^m¡{VH$ {Z`Vm§H$m| Ho$ _mZm| H$m Cn`moJ H$a gH$Vo h¢ : c = 3 108 m/s
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h = 6.63 10–34 Js
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e = 1.6 10–19 C o = 4 10–7 T mA–1
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1 = 9 109 N m2 C–2 4 o
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me = 9.1 10–31 kg
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General Instructions : (i)
All questions are compulsory.
(ii)
There are 30 questions in total. Questions No. 1 to 8 are very short answer type questions and carry one mark each.
(iii)
Questions No. 9 to 18 carry two marks each, questions No. 19 to 27 carry three marks each and questions No. 28 to 30 carry five marks each.
(iv)
One of the questions carrying three marks weightage is value based question.
42/1 (SPL)
2
AglaSem Schools (v)
There is no overall choice. However, an internal choice has been provided in one question of two marks, one question of three marks and all the three questions of five marks each weightage. You have to attempt only one of the choices in such questions.
(vi)
Use of calculators is not permitted. However, you may use log tables if necessary.
(vii)
You may use the following values of physical constants wherever necessary : c = 3 108 m/s
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h = 6.63 10–34 Js e = 1.6 10–19 C o = 4 10–7 T mA–1
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1 = 9 109 N m2 C–2 4 o
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{H$gr namd¡ÚwV _mÜ`_ Ho$ ‘d¡ÚwV Y«wdU’ nX H$mo n[a^m{fV H$s{OE & BgH$m Eg.AmB©. _mÌH$ {b{IE &
(S.I.) 1
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me = 9.1 10–31 kg
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{H$gr H$U na ‘q’ Amdoe h¡, `h H$U ‘v’ doJ go {H$gr ~mø Mwå~H$s` joÌ _| J{V H$aVm h¡ & {H$Z eVm] (à{V~§Ym|) Ho$ AÝVJ©V Bg na bJZo dmbm ~b (i) eyÝ` hmoJm, (ii) A{YH$V_ hmoJm ?
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Define the term ‘electric polarisation’ of a dielectric medium. Write its S.I. unit.
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3.
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Under what conditions does a particle of charge ‘q’ moving with velocity ‘v’, experience (i) no force, (ii) maximum force, in an external magnetic field ?
{H$gr MmbH$ _| Amdoe dmhH$m| H$m Andmh doJ {H$Z Xmo H$maH$m| na {Z^©a H$aVm h¡ CëboI H$s{OE &
? 1
Write any two factors on which drift velocity of charge carriers in a conductor depends. 4.
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ì`mnH$sH¥$V Eopån`a Ho$ n[anW {Z`_ H$m J{UVr` ì`§OH$ {b{IE & Write the mathematical expression for the generalized Ampere’s circuital law.
42/1 (SPL)
3
P.T.O.
AglaSem Schools 5.
Ý`ypŠbAm°Zm| Ho$ EH$ `w½_ H$s pñW{VO D$Om© VWm CZHo$ ~rM H$s Xÿar Ho$ \$bZ Ho$ ê$n _| AmaoI It{ME &
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Draw a plot showing variation of potential energy of a pair of nucleons as a function of their separation. 6.
g§Mma ì`dñWm _| ‘nwZamdV©H$’ ([anrQ>a) H$m àH$m`© Š`m hmoVm h¡
?
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State the function of a ‘Repeater’ in a communication system.
namdVu XÿaXe©H$ _| EH$ b|g Ho$ ñWmZ na AdVb Xn©U H$mo A{^Ñí`H$ Ho$ ê$n _| à`moJ H$aZo H$m EH$ H$maU {b{IE &
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7.
Give one reason for using a concave mirror, rather than a lens, as an objective in a reflecting type telescope. 8.
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c(t)
H$mo Bg àH$ma ì`º$ {H$`m J`m h¡
c(t) = 3 sin (4t) volt
Xem©E AZwgma EH$ dJ© Va§J h¡ &
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m(t)
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_m°Sw>bZ {g½Zb
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BgH$m _m°Sw>bZ gyMH$m§H$ kmV H$s{OE &
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A carrier wave c(t) is given by
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c(t) = 3 sin (4t) volt
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The modulating signal m(t) is a square wave as shown.
Find its modulation index. 42/1 (SPL)
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AglaSem Schools (a)
dmZ S>o J«m\$ O{ZÌ Ho$ ~‹S>o Jmobr` MmbH$ Imob na Cƒ {d^dmÝVa H$mo$ EH$ gr_m VH$ hr ~‹T>Zo XoZo Ho$ {bE H$maH$ H$s nhMmZ H$s{OE & EH$ g_mÝVa ßboQ> (n{Å>H$m) g§Ym[aÌ H$s à^mdr Ym[aVm 1 F h¡ VWm BgH$s Xmo ßboQ>m| Ho$ ~rM H$s Xÿar 1 cm h¡ & BgH$s Xmo ßboQ>m| Ho$ ~rM _| 9 106 V/m namd¡ÚwV gm_Ï`© H$m EH$ namd¡ÚwV _mÜ`_ ^a {X`m OmVm h¡ & Vmo g§Ym[aÌ na Amdoe H$m {ZYm©aU H$s{OE &
(b)
(b)
A dielectric medium of dielectric strength 9 106 V/m is filled between the plates of a parallel plate capacitor having effective capacitance of 1 F and plate separation 1 cm. Determine the charge on the capacitor.
{ZåZ{b{IV J«mµ\$ (AmboI), Xmo n¥WH²$ loUr (V) VWm Ymam (I) Ho$ n[adV©Z H$mo Xem©Vo h¢ &
LCR
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In a Van de Graaff generator, identify the factor which limits the build-up of a high potential difference on a large spherical conducting shell.
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Ho$ gmW dmoëQ>Vm
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10.
(a)
2
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9.
(XL)
go
(i)
A{YH$ hmoJr 2
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BZ_| go {H$g n[anW _| g§Ym[aÌ à{V~mYm (XC), àoa{UH$ à{V~mYm (ii) H$_ hmoJr ? AnZo CÎma Ho$ {bE H$maU {b{IE &
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The following graphs depict the variation of voltage (V) and current (I) versus (t) for two different series LCR circuits.
State, giving reason, in which of the circuits capacitive impedance (XC) is (i) greater, (ii) smaller than the inductive impedance (XL). 42/1 (SPL)
5
P.T.O.
AglaSem Schools 11.
(a)
+ z-Aj
Va§JX¡¿`©
Ho$ AZw{Xe J_Z H$aVr hþB© EH$ {dÚwV²-Mwå~H$s` Va§J H$s Amd¥{Îm ‘’
‘v’
VWm
h¡ & Bg Va§J go g§~Õ {dÚwV² VWm Mwå~H$s` joÌ Ho$ KQ>H$m| Ho$ {bE
J{UVr` {Zê$nU ({MÌU) H$mo {b{IE & (b)
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Ho$ AZw{Xe g§MaU H$aVr hþB©, {H$gr g_Vb {dÚwV²-Mwå~H$s` Va§J H$m,
CgHo$ Xmobm`_mZ {dÚwV² VWm Mwå~H$s` joÌ Ho$ KQ>H$m| Ho$ gmW EH$ aoIm{MÌ (ñHo$M) 2
~ZmBE & Write the mathematical expressions for electric and magnetic field
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(a)
components associated with an electromagnetic wave of frequency ‘v’ and wavelength ‘’ propagating along the + z-axis. (b)
Draw the sketch of the plane electromagnetic wave propagating in
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Xn©U gyÌ H$m Cn`moJ `h Xem©Zo Ho$ {bE H$s{OE {H$ CÎmb Xn©U Ûmam ~Zm Am^mgr à{V{~å~ gX¡d AmH$ma _| N>moQ>m Am¡a Xn©U Ho$ Y«wd d \$moH$g Ho$ ~rM pñWV hmoVm h¡ &
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the z-direction along with the components of oscillating electric and magnetic fields.
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`hm± AmaoI _| `§J Ho$ {Û{Par à`moJ Ho$ EH$ ì`dñWmnZ H$mo Xem©`m J`m h¡, {Og_| Ho$ÝÐr` q\«$O ‘O’ na h¡ &
nX} na ~Zo ì`{VH$aU n¡Q>Z© na Š`m à^md n‹S>oJm, `{X, (i) òmoV S H$mo S1S2 g_Vb Ho$ g_mÝVa D$na H$s Amoa {dñWm{nV H$a {X`m OmE VWm (ii) òmoV S H$mo ídoV àH$me Ho$ {H$gr òmoV go à{VñWm{nV H$a {X`m OmE ? 42/1 (SPL)
6
2
AglaSem Schools Use the mirror formula to show that the virtual image produced by a convex mirror is always diminished in size and is located between the focus and the pole. OR
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The figure shows an experimental set-up of Young’s double slit experiment with the central fringe at ‘O’.
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How will the interference pattern on the screen be affected when (i) the source S is displaced upwards parallel to the plane S1S2 and (ii) the
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13.
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source S is replaced by white light ?
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Write Einstein’s photoelectric equation in terms of the stopping potential (V0) and the frequency of the incident radiation (v) for a given
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photosensitive surface. Draw a suitable graph to show how one can get the information about (i) the work function of the material and (ii) value of Planck’s constant from this graph. 14.
Cn`wº$ {MÌ H$s ghm`Vm go p-n g§{Y Ho$ {Z_m©U _| _w»` à{H«$`mAm| H$m {ddaU Xr{OE & õmgr joÌ Ho$ ~ZZo H$m g§jon _| dU©Z H$s{OE &
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Explain, with the help of a diagram, the basic processes involved in the formation of p-n junction. Write briefly how the depletion region is developed.
42/1 (SPL)
7
P.T.O.
AglaSem Schools 15.
(a)
A§H$s` ({S>{OQ>b) VWm AZwê$n (EZmbm°J) g§Ho$Vm| Ho$ ~rM AÝVa {b{IE &
(b)
Cg _yb JoQ> H$m VH©$ àVrH$ VWm CgHo$ {bE gË`_mZ gmaUr ~ZmBE Omo {Zdoe H$m 2
ì`wËH«${_V ê$nmÝVa CËnÞ H$aVm h¡ & (a)
Distinguish between digital and analogue signals.
(b)
Write the logic symbol and truth table of the basic gate which
Xmo bå~o, nVbo g_mÝVa Vmam| H$m aoIr` Amdoe KZËd H«$_e… 2 10–9 C/m VWm – 3 10–9 C/m h¡ & `o dm`w _| EH$-Xÿgao go 20 cm Xÿa aIo JE h¢ & BZ àË`oH$ Vmam| go 10 cm Xÿa pñWV {H$gr {~ÝXþ na {dÚwV² joÌ H$m n[a_mU (_mZ) VWm CgH$s {Xem kmV H$s{OE & $
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produces an inverted version of the input.
Two long thin parallel wires having linear charge density 2 10–9 C/m
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and – 3 10–9 C/m are kept 20 cm apart in air. Find the magnitude and
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direction of the electric field at a point 10 cm from each wire.
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h¡ & Vmo BboŠQ´>m°Z H$s
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17.
2
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An electron and a photon each have a wavelength 3.315 nm. Find the
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ratio of the kinetic energy (K) of the electron to the energy of the photon.
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EH$ Amdo{eV H$U na 2 nC H$m Amdoe h¡ & `h H$U doJ v = 105 ^i (m/s) go Mwå~H$s` joÌ B _| J{V H$aVm hþAm EH$ Mwå~H$s` ~b, F = 2 10–5 (– ^j ) N H$m AZw^d H$aVm h¡ & Bg Mwå~H$s` joÌ H$s {Xem VWm n[a_mU (_mZ) kmV H$s{OE &
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A charged particle having a charge of 2 nC moving in a magnetic field B with a velocity v = 105 ^ i (m/s) experiences a magnetic force ^ F = 2 10–5 (– j ) N. Find the direction and magnitude of the magnetic field. 42/1 (SPL)
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AglaSem Schools 19.
Xmo g§Ym[aÌm| H$s Ym[aVm H«$_e… C1 VWm C2 h¡, Am¡a C1 = 2C2 & (i) nhbo BZHo$ loUrH«$_ _| g§`moOZ H$mo Am¡a (ii) {\$a BZHo$ g_mÝVa-H«$_ _| g§`moOZ H$mo, EH$ hr ~¡Q>ar go Omo‹S>m OmVm h¡ & BZ Xmo XemAm| go {H$g_| (a) g§{MV D$Om© VWm (b) Cnm{O©V Amdoe, A{YH$ hmoJm ? AnZo CÎma H$s nw{ï> H$s{OE &
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Two capacitors of capacitances C1 and C2 such that C1 = 2C2 are connected in turn (i) in series and (ii) in parallel across the same battery. In which of the two cases will the (a) energy stored and (b) charge
{H$gr EH$dUu òmooV go àH$me 0.2 mm Mm¡‹S>r EH$b {Par (pñbQ>) na n‹S>Vm h¡, Am¡a Bggo {Par Ho$ g_Vb go 1 m Xÿa pñWV nX} na {ddV©Z n¡Q>Z© ~ZVm h¡ & `{X _w»` C{ƒð> H$s Hw$b aoIr` Xÿar 4.8 mm h¡, Vmo AZwà`wº$ àH$me H$s Va§JX¡¿`© () H$m n[aH$bZ H$s{OE & Ho$ Bg _mZ Ho$ Cn`moJ Ûmam, {ÛVr` (Xÿgar) AXrá q\«$O H$s aoIr` Mm¡‹S>mB© H$m n[aH$bZ H$s{OE & {H$gr {ddV©Z n¡Q>Z© _| q\«$Om| H$s Vrd«Vm _| H¡$go n[adV©Z hmoVm h¡ ?
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20.
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acquired be more ? Justify your answer.
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Light from a monochromatic source falls on a single slit of width 0 .2 mm to produce a diffraction pattern on a screen kept at a distance of 1 m from the plane of the slit. If the total linear width of the principal maxima is 4.8 mm, calculate the wavelength () of the light used. Using this value of , calculate the linear width of the second dark fringe.
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How does the intensity of fringes in a diffraction pattern vary ?
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Draw the transfer characteristic of base biased transistor in CE configuration. Use this characteristic to identify the regions where transistor can be used as (i) an amplifier and (ii) a switch. Briefly explain the working of a transistor as a switch. 42/1 (SPL)
9
P.T.O.
AglaSem Schools 22.
g§jon _| dU©Z H$s{OE {H$ AmH$me Va§J g§MaU {d{Y Ûmam ao{S>`mo Va§Jm| H$m g§MaU H¡$go hmoVm h¡ & EH$ àofr E|Q>rZm H$s D±$MmB© 20 m VWm A{^J«mhr E|Q>rZm H$s D±$MmB© 80 m h¡ & LOS {dYm _| g§VmofOZH$ g§Mma Ho$ {bE XmoZm| Ho$ ~rM H$s A{YH$V_ Xÿar H$m n[aH$bZ H$s{OE & [{X`m J`m h¡, n¥Ïdr H$s {ÌÁ`m = 6.4 106 m]
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Describe briefly how radio waves are propagated in space wave mode of propagation.
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A transmitting antenna has a height of 20 m and the height of the receiving antenna is 80 m. Calculate the maximum distance between them for satisfactory communication in LOS mode. [Given, radius of Earth = 6.4 106 m]
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1 = 1.5 V, 2 = 2.0 V VWm 3 = 3 V r1 = 0.3 , r2 = 0.4 VWm r3 = 0.6 h¢ & BZ
VrZ gobm| Ho$ {dÚwV² dmhH$ ~b (B©.E_.E\$.) h¢, BZHo$ AmÝV[aH$ à{VamoY H«$_e…,
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VrZm| gobm| H$mo g_mÝVa-H«$_ _| g§`mo{OV {H$`m J`m h¡ & `{X Bg g§`moOZ Ho$ ñWmZ na EH$
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gob {b`m OmE, Vmo Cg gob H$m Vwë` {dÚwV² dmhH$ ~b (B©.E_.E\$.) VWm Vwë` à{VamoY 3
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kmV H$s{OE &
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Xem©E JE d¡ÚwV OmbH«$_ _| {H$aImoµ\$ Ho$ {Z`_m| Ho$ Cn`moJ Ûmam {dÚwV² YmamAm| Ho$ _mZ kmV H$s{OE &
42/1 (SPL)
10
I1
VWm
I2 3
AglaSem Schools Three cells of e.m.f., 1 = resistances r1 = 0.3 ,
1.5 V, 2 = 2.0 V and 3 = 3 V, having internal r2 = 0.4 and r3 = 0.6 respectively are
connected in parallel. Find out the equivalent e.m.f. and the equivalent resistance of a cell which can replace this combination. OR Use Kirchhoff’s rules to find out the values of the currents I1 and I2 in the
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electrical network as shown.
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Bg {Z`_ Ho$ Cn`moJ Ûmam, AmaoI _| Xem©E JE Xmo g_Vbr` bynm| (nmem|) _| ào[aV {dÚwV² Ymam H$s {XemE± H$maU XoH$a kmV H$s{OE•& `o byn (nme) {H$gr Eogo EH$g_mZ Mwå~H$s` joÌ _| {dÚ_mZ h¢ {OgH$s {Xem nmem| Ho$ g_Vb Ho$ A{^bå~dV² VWm nmR>H$ (Amn) H$s Amoa h¡ & nme ‘abcd’ Bg Mwå~H$s` joÌ go ~mha {ZH$b ahm h¡ VWm nme ‘pqrs’ Mwå~H$s` joÌ _| àdoe H$a ahm h¡ &
42/1 (SPL)
11
3
P.T.O.
AglaSem Schools State Lenz’s law. Describe a simple example to show that this law is in conformity with the principle of conservation of energy. Using this law, predict, giving reasons, the directions of the induced currents in each of the two planar loops shown in the figure. The loop ‘abcd’ is moving out whereas the loop ‘pqrs’ is moving into the region of a uniform magnetic field directed normal to the planes of the loop and
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25.
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towards the reader.
(c)
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g§`wº$ gyú_Xeu _| A{^Ñí`H$ VWm Zo{ÌH$m XmoZm| hr Aën µ\$moH$g Xÿar Ho$ hmoVo h¢ &
(a)
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Explain the following giving reason : If light from an ordinary source (like a sodium lamp) passes through a polaroid sheet, its intensity is reduced to half and rotating the polaroid has no effect on the transmitted intensity.
(b)
A convex lens when immersed in a medium whose refractive index is more than that of the material of the lens, behaves like a diverging lens.
(c)
Both the objective and the eyepiece of a compound microscope have short focal lengths.
42/1 (SPL)
12
3
AglaSem Schools 26.
EH$ loUr LCR (Eb gr Ama) n[anW Ho$ {bE _mÜ` e{º$ j` H$m ì`§OH$ e{º$ JwUm§H$ Ho$ nX _| ì`wËnÞ H$s{OE & AV… Xem©BE {H$ _mÜ` e{º$ j` H$m _mZ AZwZmX H$s pñW{V _| A{YH$V_ hmoVm h¡ &
3
Deduce the expression for the average power dissipated in a series LCR circuit in terms of power factor. Hence show that average power dissipated at resonance is maximum.
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emo_m EH$ {Z_‚mZ N>‹S> (am°S>) Ûmam H$m±M Ho$ EH$ nmÌ _| nmZr J_© H$aZo H$m à`ËZ H$a ahr Wr (`h am°S> grYo hr _oZ nm°da gßbmB© go Ow‹S>r Wr) & O~ `h OmZZo Ho$ {bE {H$ nmZr n`m©á J_© hþAm `m Zht, dh AnZr C±Jbr nmZr _| S>mbZo Om hr ahr Wr Vmo CgHo$ {ejH$ Zo Cgo Eogm Z H$aZo Ho$ {bE gMoV {H$`m & Bg KQ>Zm na AmYm[aV {ZåZ{b{IV àíZm| H$m CÎma Xr{OE : `h gbmh XoH$a emo_m Ho$ {ejH$ Zo {H$g _yë` H$m àXe©Z {H$`m
(ii)
O~ nmZr _| {dÚwV² àdm{hV H$s Om ahr h¡ Vmo Cgo Ny>Zm ˜VaZmH$ Š`m| hmoVm h¡ ? `{X emo_m Zo AmgwV Ob {b`m hmoVm, Vmo Š`m `h A{YH$ gwa{jV hmoVm ?
(iii)
EH$ CXmhaU Xr{OE {Og_| AmnZo ñd`§ H$mo `m {H$gr AÝ` ì`{º$ H$mo dmñV{dH$ OrdZ _| Bg àH$ma Ho$ _yë` H$m àXe©Z H$aVo hþE nm`m hmo &$
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27.
3
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Shoma was trying to heat water by means of immersion rod (connected
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directly to the main power supply) in a glass vessel containing water. As
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she tried to put her finger into the water to check if the water was warm
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enough, her teacher cautioned her against doing it. Based on the above information, answer the following questions : (i)
What value did Shoma’s teacher display by giving this advice ?
(ii)
Why is it considered dangerous to touch water when current is being passed into it ? Will it be safer if Shoma had used distilled water ?
(iii)
42/1 (SPL)
Give an example where you have displayed or observed someone else displaying similar value in real life situation. 13
P.T.O.
AglaSem Schools 28.
(a)
Cn`wº$ AmaoI H$s ghm`Vm go {H$gr EH$g_mZ Mwå~H$s` joÌ B _| pñWV, A joÌ\$b H$s EH$ Am`VmH$ma I Ymamdmhr Hw§$S>br na bJZo dmbo ~bAmKyU© (Q>m°H©$) Ho$ {bE EH$ ì`§OH$ (g{Xe ê$n _|) àmá H$s{OE & CZ eVm] H$m C„oI H$s{OE {OZ_| (i) D$na {XE JE ~b-AmKyU© H$m ì`§OH$ Mb Hw§$S>br J¡ëd¡Zmo_rQ>a _| Cn`wº$ hmoVm h¡; (ii) Mb Hw§$S>br J¡ëd¡Zmo_rQ>a H$s gwJ«m{hVm ~‹T> gH$Vr h¡ & AWdm n¥Ïdr Ho$ n¥ð> Ho$ {H$gr {~ÝXþ na Mwå~H$s` joÌ H$m {ddaU XoZo Ho$ {bE Amdí`H$ VrZ am{e`m| (Ad`dm|) H$m g§{já dU©Z, Amdí`H$ AmaoIm| Ho$ Cn`moJ Ûmam H$s{OE & AZwà`wº$ Amdí`H$ gyÌ ^r {b{IE & à{VMwå~H$s` VWm AZwMwå~H$s` nXmWm] H$mo EH$g_mZ Mwå~H$s` joÌ _| aIm J`m h¡ & BZ nXmWm] Ho$ g_rn Mwå~H$s` joÌ aoImAm| H$m ì`dhma {MÌ Ûmam àX{e©V H$s{OE & AnZo CÎma H$s nwpîQ> H$s{OE &
(b)
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(a)
(b)
Derive, with the help of a suitable diagram, the expression (in vector form) for the torque acting on a rectangular loop of area A carrying current I, placed in a uniform magnetic field B .
(b)
Mention the conditions under which (i) the above expression for the torque is applied in moving coil galvanometer; (ii) the sensitivity of the moving coil galvanometer is increased.
5
ch
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(a)
5
Give a brief description using necessary diagrams, of the three elements (quantities) required to specify the magnetic field of the Earth at a point on its surface. Also write the necessary formulae used. Specimens of a paramagnetic material and a diamagnetic material are placed in a uniform magnetic field. Draw the behaviour of magnetic field lines near these specimens. Justify your answer.
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(a)
OR
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(b)
29.
{H$gr {ÌH$moUr` {àµÁ_ go hmoH$a JwµOaVr hþB© àH$me H$s {H$aU H$m _mJ© Xem©Zo Ho$ {bE EH$ {H$aU AmaoI ~ZmBE & Bg AmaoI Ho$ Cn`moJ go, {àµÁ_ Ho$ H$moU VWm Ý`yZV_ {dMbZ H$moU Ho$ nXm| _|, {àµÁ_ Ho$ nXmW© Ho$ AndV©Zm§H$ Ho$ {bE gå~ÝY àmá H$s{OE & {H$gr {àµÁ_ Ho$ {bE, AmnVZ H$moU VWm {dMbZ H$moU Ho$ ~rM J«mµ\$ H$s àH¥${V H$mo Xem©BE & AWdm
42/1 (SPL)
14
5
AglaSem Schools (a)
Va§JmJ« H$s n[a^mfm {b{IE & {H$gr g_` t = 0 na {H$gr Va§JmJ« H$m AmH$ma g_Vb Va§J Ho$ ê$n _| h¡ & hmBJoÝg H$s aMZm Ûmam Xem©BE {H$ (i) Hw$N> g_` t Ho$ níMmV², {ÛVr`H$ Va§{JH$mAm| Ho$ EZdobn (C^`{Zð> ñne©H$), g_Vb Va§J H¡$go CËnÝZ H$aVo h¢ VWm (ii) CÎmb b|g go JwµOaZo Ho$ níMmV² {ZJ©V Va§JmJ« {H$g àH$ma JmobmH$ma hmo OmVm h¡ Am¡a µ\$moH$g na A{^g[aV hmo OmVm h¡ & hmBJoÝg Ho$ {gÕmÝV Ho$ Cn`moJ Ûmam {H$gr gKZ _mÜ`_ go {dab _mÜ`_ H$mo g§M[aV hmoVr hþB© g_Vb Va§J Ho$ AndV©Z Ho$ ñZ¡b Ho$ {Z`_ H$m gË`mnZ H$s{OE &
5
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(b)
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Draw a ray diagram to show the passage of a ray of light through a triangular prism. Use this diagram to obtain the relation for the refractive index of the material of the prism in terms of the angle of minimum deviation and the angle of the prism. Plot the nature of the graph for the angle of deviation versus the angle of incidence in a prism. OR
Define a wavefront. Given the shape of a wavefront as a plane wave at time t = 0, show using Huygens’ construction, (i) how the envelopes of secondary wavelets produce the plane wave at a later time t and (ii) how the emergent wavefront becomes spherical and converges to the focus after passing through a convex lens ?
(b)
Verify using Huygens’ principle, Snell’s law of refraction of a plane wave propagating from a denser to a rarer medium.
(a)
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(a)
(b)
5
AWdm 42/1 (SPL)
15
P.T.O.
AglaSem Schools
Eoë\$m ()-j` VWm (ii) ~rQ>m– (–)-j` _| àË`oH$ H$m EH$ CXmhaU Xr{OE & BZ j`-àH«$_m| H$mo gm§Ho${VH$ ê$n _| {b{IE &
(a)
(i)
(b)
Xr JB© Zm{^H$s` A{^{H«$`m, 2 H 21 H 1
32 He 01 n 3.27 MeV
_| `Ú{n Ý`ypŠbAm°Zm| H$s g§»`m XmoZm| Amoa g§a{jV ahVr h¡, {\$a ^r D$Om© {Z_©wº$ hmoVr h¡ & ñnï> H$s{OE & (c)
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Xem©BE {H$ EH$ Zm{^H$ Ho$ {bE {dñV¥V ûm¥§Ibm _| Zm{^H$ KZËd pñWa ahVm h¡ VWm Ðì`_mZ g§»`m A go ñdV§Ì hmoVm h¡ & State the first two postulates of Bohr’s theory of hydrogen atom. Also explain briefly the necessity for invoking these postulates to describe the structure of the atom.
(b)
Using Bohr’s third postulate, write the Rydberg formula for the spectrum of the hydrogen atom. With the help of this formula, calculate the wavelength of the first member of the spectral line in the Lyman series of the hydrogen spectrum.
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(Take the value of Rydberg constant R = 1.03 107 m–1)
(b)
In a given nuclear reaction,
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(a)
OR Give one example each for (i) -decay and (ii) –-decay by writing the decay processes in symbolic form.
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32 He 01 n 3.27 MeV although number of nucleons is conserved on both sides, yet energy is released. Explain.
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2 H 21 H 1
(c)
42/1 (SPL)
Show that nuclear density in a nucleus, on a wide range of nuclei is constant and independent of mass number A.
16
5
AglaSem Schools
MARKING SCHEME SET 42/1 (SPL) Expected Answer / Value Points
Q. No.
4.
=
om
3.
+ Alternatively : = (
½ ½ ½
1
½
1
½ ½
1
1 1
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2.
Net dipole moment per unit volume developed in the dielectric medium in presence of an external electric field is called electric polarization. SI unit : coulomb/m2 i. When a charged particle is moving parallel/anti parallel to the magnetic field. ii. When a charged particle is moving perpendicular to the magnetic field. Two factors on which drift velocity of charge carriers depends; Applied electric field and temperature of the conductor. (or any other correct 2 factors.)
Total Marks
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1.
Marks
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1
A repeater picks up the signal from the transmitter, amplifies and retransmits it to the receiver. i. There is no chromatic aberration. ii. Spherical aberration is reduced. iii. Easy mechanical support. (Any one /any other one correct reason.)
= =
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8.
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7.
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6.
1
= 0.5 [Note: Award this one mark, if a student writes answer directly without calculation.]
1
1
1 ½
1
½ 1
9. (a) Identification of factor (b) Determination of charge on the capacitor 1 a) Limiting factor – break down field of air. b) c = as dielectric strength E = Page 1 of 13
½ 1½ ½
= Final draft
13/4/14 12:00noon
AglaSem Schools
c=
½ ½
q= 9 x 10-2 C = 90mC
½
2
½ ½ ½ ½
2
10. Identification of circuits Reasons
½+½ ½+½
i. For circuit I, Xc > XL Reason: Current is leading the voltage in phase. ii. For circuit II, Xc < XL Reason: Current is lagging the voltage in phase. 11.
= =
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(a) Mathematical expressions for electric and magnetic field components ½+ ½ (b) Drawing of the sketch of the plane electromagnetic wave 1
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b)
½ ½
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12.
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Showing, that the virtual image produced by convex mirror is always diminished and between focus & pole 2 and for an object on left side i.e.
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For a convex mirror, Using the mirror formula
½ ½
=
,
(as
and
)
<
½
Image is between Pole and focus of the mirror, Linear magnification m=
½
for
Hence, image is diminished
OR Page 2 of 13
Final draft
13/4/14 12:00noon
2
AglaSem Schools
Effect on interference pattern when i. Source S is displaced upwards. ii. Source S is replaced by white light. i.
1 1
Fringe pattern on the screen will shift downwards with central fringe below point 0, on the screen. Central fringe will be white, fringe closest on either side of central white fringe will be red and farthest will appear blue, after a few fringes, no clear pattern will be seen.
ii.
1
1 13
Einstein’s photoelectric equation Drawing of suitable graph
½ 1½
½
½
intercept on the y-axis)
½
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i. ii.
2
work function = -(e
slope of the curve.
½
Processes involved in the formation of p-n junction
2
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14.
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Planek’s constant = e
1
Two processes involved during the formation of p-n junction are diffusion and drift. Due to the concentration gradient, across p and n sides of the Page 3 of 13 Final draft 13/4/14 12:00noon
2
AglaSem Schools
junction , holes diffuse from p n, and electrons from n p. This movement of charge carriers leaves behind ionised acceptors on the p-side and donors on the n- side of the junction. This space charge region on either side of the junction, together, is known as depletion region.
1 2
15. a) Distinction between digital & analogue signals b) Logic symbol and truth table i.
1 ½+½
Analogue signals are in the form of continuos, time varying voltage or current. Digital signals are those which can take only discrete stepwise values i.e. only two levels of voltage / current.
½ ½
½
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ii.
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½ 2
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16.
2
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Finding the magnitude and direction of the electric field.
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½
Electric field at a point distant 10cm from each wire, E= [ ]
=
+ ½
= 9 x 109 x (2 ) = 9 x 5 x 2 x 10 N/C = 900 N/C (towards the wire having negative linear charge density.) [Note : Give full credit, if a student doesn’t draw diagram.]
½ ½
17. Calculation of ratio of kinetic energy of electron and energy of photon. 2 for electron Page 4 of 13
½ Final draft
13/4/14 12:00noon
2
AglaSem Schools
K.E. = For photon, energy(E) =
½
=
½ ½
66 x 10-4
2
18. Finding the direction and magnitude of magnetic field.
2 ½
gl
as
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= q( ) Since, charged particle is moving along +x axis and experiences the force along –y axis, therefore magnetic field should be along +z axis . (using right hand thumb rule/ fleming’s left hand rule/ any relevant rule.) i.e. should be along . F = qvBSin 2 x 10-5 = 2 x 10-9 x 105 B(as angle = )
½
½
2
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= 0.1 T
½
19.
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Calculation of energy stored and charge acquired in given cases. 1½+1½ For series combination of the given capacitors
ii.
For parallel combination of the given capacitors
½
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i.
½ ½ ½ ½ ½
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a) As energy stored U , for same voltage source. Energy stored in parallel combination of capacitors will be more, b) Charge acquired, Q for same Voltage source, Hence charge acquired will be more in parallel combination. [Note : Also give full credit, for alternative methods.] 20.
Calculation of wavelength ( ) of light used Calculation of linear width of second dark fringe Variation of Intensity of fringes.
3 1½ ½ 1
Linear width of principal maxima(w) ½
4.8
½
= 4.8 x 10-7m = 480nm Page 5 of 13
Final draft
13/4/14 12:00noon
AglaSem Schools
Linear width of second dark fringe
= half of the linear width of principal maxima
=
½
= 2.4mm Intensity of bright fringes, falls rapidly as one moves from centre to the ends of the screen, and for the dark fringes intensity remains zero. [Note : Also accept the intensity distribution curve of diffraction for this part.]
½
1
3
21. 1 ½+½ 1
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Draw of the transfer characteristic Identification of regions for amplifier and switch Brief working of a transistor as a switch
gl
as
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1
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Brief description of propagation of radio waves in space wave mode. Calculation of maximum distance.
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Space wave travels in a straight line from transmitting antenna to receiving antenna. Maximum distance = +
23.
= + 3 = 2 x 8 x 10 + 4 x 8 x 103 = 48 x 103m = 48Km
Calculation of equivalent e.m.f. Calculation of equivalent resistance
½ ½
1 3
1 2
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22.
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i. Region for transistor to be used as an amplifier : Active region. ii. Region to be used as a switch : cut off region and saturation region. Working: when input voltage ( ) is low and unable to forward bias the transistor, is high. If is high enough to drive the transistor into saturation then is low. Therefore when transistor is not conducting, it is switched off and when it is driven into saturation it is switched on.
1 ½ ½ ½ ½
1½ 1½
=
½
=
½
Page 6 of 13
Final draft
13/4/14 12:00noon
3
AglaSem Schools
½
=
½
= =
½ = 5+5+5 = = 2.0V
½
3
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OR Finding the value of I1 and I2
3
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In loop abcda
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½
24.
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½
A
Statement of Lenz’s law Description of a simple example Prediction of direction of induced current
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And I1 =
½
½
.a
I1 +2 I3 = 2 ----------(1) As I3= I1 + I2 I1 +2 I1 +2 I2 = 2 3 I1+ 2I2 = 2 ----------(2) In loop adefa 40 I3 – 40 – 80 +20 I2 = 0 2 I3 + I2 = 6 -----------(3) Substituting I3 = I1 + I2 2 I1 + 2I2 +I2= 6 2 I1 + 3I2 =6 -----------(4) solving equation 2 and 4 I2= A
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-20 I1 + 40 – 40 I3 = 0
½
3
1 1 ½+½
The polarity of induced emf is such that it tends to produce a current which 1 opposes the change in magnetic flux that produced it. This law is in conformity with the principle of conservation of energy, consider a situation where induced current is in the direction opposite to that 1 given by lenz’s law. Then in this situation kinetic energy will continuously increase without expanding any energy and hence one can construct a perpetual motion machine by a suitable arrangement, which violates the conservation of energy. In irregular loop induced current will be in the sense. pqrsp, as induced ½ current will oppose the increase in magnetic flux. In other loop, induced current will be in the sense abcda, as the induced ½ current will oppose the decrease in magnetic flux. 3 Page 7 of 13 Final draft 13/4/14 12:00noon
AglaSem Schools
25. Explanation of parts a, b and c
1 +1+1
a) It is because, light which is produced from an ordinary source (like a sodium lamp) is unpolarised, when an unpolarised light wave is passed through a Polaroid sheet, it gets linearly polarised with the electric vector oscillating along the direction perpendicular to the aligned molecules. b) Ray of light parallel to the pricipal axis, gets deviated away from the normal at the first surface and towards the normal at the second surface since deviation at two surfaces is in same sense, net deviation from both the surfaces make the ray diverge away from the principal axis. Alternatively: It is because the relative refractive index of lens
1
1
om
becomes less than 1 and
1
as
3
Deduction of the expression for the average power 2 Showing the average power dissipation is maximum at resonance 1
.a
gl
26.
em
.c
becomes –ve. Hence, lens behave like a diverging lens. [Note : Also accept the explanation through diagram.] c) Due to short focal length of eye piece, angular magnification of eye piece increases and magnification of objective is large when is slighty greater than , since the microscope is used for viewing very close object therefore is small and hence , should be small.
V= I= Instantaneous power ‘p’ supplied by the source P = VI = .
oo
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½
= [ Average power over a complete cycle P= (because the average of time dependent term is zero.)
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½
w
=
½
w
= At resonance V and I are in same phase i.e. P= , which is maximum
w
½ 1
27.
Answer of the parts i, ii and iii i. ii.
iii.
1+1+1
Concerned/ Caring(or any other one relevant value) Because, one can get electric shock, as water conducts electricity, Yes, relatively safer, because distilled water is a bad conductor of electricity. Any example displaying similar value in real life situation.
1 1 1
28. a) Derivation of the expression for torque b) Mentioning the conditions for (i) & (ii)
Page 8 of 13
3
Final draft
3 1+1
13/4/14 12:00noon
3
AglaSem Schools
a) ½
.c
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½
=
gl
as
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Forces on the arms BC and DA are equal, opposite and act along the axis of coil, being collinear along the axis, they cancel each other, Forces on arms AB and CD are and which are equal and opposite, but not collinear. = =IbB therefore magnitude of torque acting on the loop
.a
+
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ii.
In moving coil galvanometer, this expression is applied at i.e. = NIAB Senstivity of a galvanometer is increased by increasing number of turns/ increasing area of coil/ increasing magnetic field/ by decreasing torsional constant.
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i.
ls
=I X
½
½ ½
(Area of the loop A = ab)
b)
½
1
1
OR
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a) Brief description of three elements Necessary diagram Necessary formula b) Drawing the behavior of magnetic field lines Justification
½+½+½ ½ ½ +½ ½ +½ ½ +½
a)
½
Page 9 of 13
Final draft
13/4/14 12:00noon
5
AglaSem Schools
Three physical quantities are Magnetic declination, angle of dip (inclination) and horizontal component of Earth’s field. The angle between the true geographic north and north shown by compass needle is called magnetic declination. Dip is the angle that the total magnetic field of earth makes with the surface of Earth. Component of total magnetic field of earth along the surface of earth is called horizontal component. = , = And tanI =
.c
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where and are horizintal and vertical component of the earth’s field and I is the inclination at a place. b)
as
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The field lines gets concentrated inside the material and field inside is enhanced.
½ ½ ½
½
½
½
½
gl
½
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The field lines are repelled or expelled and the field inside the material is reduced. 29.
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Ray diagram showing the passage of ray Obtaining the relation for refractive index Nature of graph.
1 3 1
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a)
½
In the quadrilateral AQNR --------------------(1) From the triangle QNR + -----------------(2) Comparing these two equations + =A -----------------------------------(3) The total devation is the sum of derivations at the two faces. = Page 10 of 13 Final draft
1
½
½
13/4/14 12:00noon
5
AglaSem Schools
That is = i+ -------------------(4) At the minimum derivation Dm, the refracted ray inside the prism becomes parallel to its base. = Dm, i = e which implies = Equation (3) becomes
½
½
2r = A or r = In the same way equation (4) becomes ½
Dm = 2i-A, => i= The refractive index of the prism is
½
=
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=
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gl
as
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1
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5
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OR
.s ch
a) Definition of wave front Showing (i) and (ii) using Huygen’s construction b) Verification of Snell’s law.
1 1+1 2
a) Wave front is the surface of constant phase Alternatively: locus of points, which orscillate in phase. i.
w
w
w
1
½
To produce the plane wave at a later time t, draw spheres of radius vt from each point on the plane wave front . By drawing the common tangent to all these spheres a plane wave at a later time t is obtained. (where v is the speed of waves in the medium) Page 11 of 13
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ii.
½
½
em
.c
om
The central part of the incident plane wave traverses the thickest portion of the lens and is delayed the most. Therefore the emerging wavefront has a depression at the centre and hence it becomes spherical and converges at the focus. b)
ls
.a
gl
as
1
==
30.
(Refractive index of rarer medium wrt denser
.s ch
medium.)
oo
=
½ 1+1 1 1 1
w
w
w
a) Statement of the first two postulates of Bohr’s theory. Brief explanation of the necessity b) Rydberg formula c) Calculations of wavelength a)
½
i.
ii.
An electron in an atom revloves in certain stable orbit without the emission of radiant energy. Electron revolves around the nucleus only in those orbit for which the angular momentum is an integral multiple of
Final draft
1
.
Alternatively: where n is an integer According to classical electromagnetic theory, an accelerated electron emits radiation in the form of electromagnetic waves. Therefore energy of electron would decrease continuously and electron would spiral inward and eventually fall into the nucleus, such an atom can not be stable. As the electrons spiral inwards, their frequency would change continuously, thus they would emit a continuous spectrum in contradiction to the line spectrum observed. To overcome above shortcomings, Bohr’s theory came into existence. Page 12 of 13
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b) Bohr’s third postulate
, gives the Rydberg Formula 1
=R For first member of spectral line in lyman series,
om
½
= 129nm
½
5
.c
OR
em
a) One example each for (i) and (ii) 1+1 b) Explanation of release of energy 1 c) Showing that nuclear density is independent of mass number 1
as
a)
1
ls
.a
gl
i. Alternatively
1
oo
ii.
.s ch
Alternatively:
1
w
w
w
b) Binding energy per nucleon of the fussed muclei is more than the binding energy per nucleon of the lighter nuclei i.e. final system is more tightly bound than the initial system therefor energy is released. c) Let A be the mass number and m be the average mass of a nucleon, Nuclear density =
= Substituting R =
½ ½
½
½ Which is constant and independent of Mass Number(A).
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