Allen Asat 2015 Paper

ASAT ASA T (ALLEN Scholarship Cum Admission A dmission Test)

(ACADEMIC SESSION 2015-16)

Corporate Corporate Office Off ice ALLEN CAREER INSTITUTE “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005 +91-744-2436001 +91-744-24 36001

[email protected]

www.allen.ac.in

INSTRUCTIONS (

)

Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose. 5 Things NOT ALLOWED in EXAM HALL : Blank Paper, Paper, clipboard, log table, slide rule, calculator, calculator, camera, mobile and any electronic or electrical gadget. If you are carrying any of these then keep them at a place specified by invigilator at your own risk : dks js dkxt  dkxt  fDyi cks MZ  ykWx rkfydk  LykbM  y  dS Ydqy Vj s  dS ejk  ls yQks u  vkS j fdlh Hkh izdkj   mUgs a nhft;sA ds bys bys DVªkWfud midj.kA vki buesa ls fdlh fdlh Hkh oLrq dks ys ys tk tk jgs gS gSa rks vkids vius vius tks tks f[ke ij fujh{kd  kjk fufnZ"V LFkku ij LFkku ij j[kus ds ds fy fy

1. 2. 3.

4. 5.

6.

7. 8. 9.

This This bookle booklett is your your Questi Question on Paper Paper.. DO NOT break NOT break seal of Booklet until the invigilator instructs to do so. Fill your Form Form No. in in the space space provide provided d on the the top top of this page. page. The Answer Answer Sheet Sheet is provided provided to to you you separately separately which is is a (ORS). You have to machine readable Optical Response Sheet (ORS). ORS by darkening bubble, as per mark your answers in the ORS by pen . your answer choice, by using black & blue ball point pen. Total otal Ques Questio tions ns to be be Attemp Attempte ted d 80. 80. Part-I : 20 : 20 Questions & Part-II : 60 : 60 Questions. After breaking breaking the Questi Question on Paper Paper seal, seal, check check the following following : a. Ther There e ar are 25 pages in pages in the booklet containing question no. 1 to 100 under 2 Parts i.e. Part-I & Part-II. b. Part-I Part-I contains contains total total 20 questions questions of IQ (Mental Ability). Ability). c. Part-II Part-II contains contains total total 80 question questionss under 4 sections sections which are-Section (A) : Physics, Section (B): Chemistry, Section (C): Mathematics* & Section (D): Biology*. *Important: You have to attempt ANY ONE SECTION only out of Section(C): Mathematics Mat hematics and Section (D) : Biology. Bi ology. DO NOT attempt both sections. Marking Scheme : Marks. a. If darkene darkened d bubble bubble is is RIGHT RIGHT answer answer : 4 Marks. b. If no bubble bubble is darke darkened ned in any any questio question: n: No Mark. Mark. c. Only for part - II : If : If darkened bubble is WRONG answer: an swer: -1 Mark (Minus One Mark). Mark). Think wisely wisely before before darken darkening ing bubble bubble as there is negati negative ve marking for wrong answer. If you you are found found involve involved d in cheati cheating ng or disturb disturbing ing others others then your ORS will be cancelled. Do not not put any any stain stain on ORS ORS and hand hand it over over back back properly properly to the invigilator.

2. 3.

 gSA bldh eqgj rc rd u rks M+s tc ;g iqfLrdk vkidk iz'u&i tc rd  fujh{kd ds  kjk bldk funZ 'k s u fn;k tk;sA is t ds Åijh Åijh fgLls ij fn;s x;s x;s LFkku LFkku ij viuk QkWeZ uaEcj ua Ecj Hkfj;sA mÙkj i d  a Js.khdj.k  ks X tks fd fd vyx ls fn;s fn;s      i  (ORS) gS tks tk;s axsA vkidks viuk viuk mÙkj ORS mÙkj mÙkj iq fLrdk fLrd k es a ls mfpr mfpr xks ys dks dk xgjk s xgjk djds ns ns uk gSA

4.

dqy 80 iz 'u gy djus gS gSaA

5.

bl iqfLrdk dh eqgj rksM+u ds s ds i'pkr i'pkr dì;k tk¡p ys a fd : a. iqfLrdk es a 25 100 es a 2 Hkkx gSa Hkkx -I -I o gS aA iz'u la  k 1 ls 100 Hkkx -II -II b. Hkkx -I -I esa dqy 20 iz'u IQ ( ekufld  ekufld  ksX;rk ) ds gS gS aA c. Hkkx -II -II ds dq dqy 80 iz'u 4 [k.Mksa es a gSA ftles a  k.M (A) : HkkS frdh ,  (B): jlk;u , [k.M (C): (C): xf.kr (D) : tho [k.M (B): xf.kr * o  k.M (D) t ho foKku * gSA

1.

*

9.

-II : 60 iz'u .

(D) :

lgh mÙkj okys okys cq cqycqy dks s dks dkyk dkyk djus ij ij : 4 dks bZ Hkh cqycqyk dkyk ugha djus ij ij : - II : xyr mÙkj okys cq cqycqys dks dkyk dkyk djus ( ). ij -1 cqycqyk dkyk djus ls igys igys Bhd Bhd izdkj ls tka tkap ys a  xyr mÙkj ij ½.kkRed vad gSA ;fn vki udy vFkok ckrs ckrs a djrs gq  ik;s x;s x;s rks rks ORS dks fujLr fujLr dj fn;k tk;s xkA ORS ij fdlh Hkh izdkj dk nkx   kCck ugha ug ha yxk;s a o lgh rjhds rj hds ls ls fujh{kd dks lks lks s aisA a. b. c.

8.

(C):

o

:

6.

7.

:

-I : 20 iz 'u

Sample question for ASAT : Nurture Course PART - I IQ (MENTAL ABILITY) This section contains 20 multiple choice questions. Each question has four choices (1), (2), (3) and (4) out of which ONLY ONE is correct.

a 20 bl  k.M se 1.

2.

gSA izR;s d iz'u esa pkj fodYi (1), (2), (3) vkS j (4) gS a ftues a ls lgh gSA fn;s x;s iz 'u es a  d la  k Jà[kyk nh x;h gS ftldk  d In the following question, a number series is 1. in xk;c gSA fn;s x;s fodYiks a es a ls lgh fodYi dk pquko given with one term missing. Choose the dhft;sA correct alternative that will continue the same pattern and replace the question mark in the

9, 27, 31, 155, 161, 1127, ?

given series.

(1) 316

9, 27, 31, 155, 161, 1127, ?

(2) 1135

(1) 316

(2) 1135

(3) 1288

(3) 1288

(4) 2254

(4) 2254

A clock is set to show the correct time at 11

2.

a.m. The clock gains 12 minutes in 12 hours.

 h 12 ?kUVks a es a 12 feuV vkxs og lgh le  n'kkZ rh gSA  g kM+

What will be the true time when the clock

 n'kkZ jgh gks tkrh gSA rks NBsa fnu tc  kM+h 1 p.m. dk le

gS rks ml oDr lgh le  D;k gks xk ?

th

indicates 1 p.m. on the 6 day?

3.

,d  kM+h dks bl izdkj fu/kkZfjr fd;k x;k fd 11 a.m. ij

(1) 10 a.m.

(2) 11 a.m.

(1) 10 a.m.

(2) 11 a.m.

(3) 12 noon

(4) None of these

(3) 12 noon

(4) bues a ls

Which day can be the first day and last day of any century? (1) Monday

(2) Tuesday

(3) Friday

(4) Wednesday

3.

dkS ulk fnu fdlh Hkh 'krkCnh o"kZ dk izFke vkS j vfUre fnu gks ldrk gS ? (1) lks eokj (3) 'kq Øokj

diagram, circle represents tall children, the square represents obese children, rectangle

(2) eaxyokj (4) cq/kokj

(Q.4 & Q.5) fuEufyf[kr

Direction (Q.4 & Q.5) The following questions are based on the diagram given below. In the

dks bZ ugha

 ij iz'u fn;s x;s fp

vk/kkfjr gS aaA fp  es a o` Ùk yEcs cPpks a dks n'kkZrk gS oxZ eks Vs cPpksa dks n'kkZ rk gS vk;r deZ B cPpks a dks n'kkZrk gS vkS j f=Hkq t

represents the energetic children and the

cfPp;ks a dks n'kkZrk gSA fn;s x;s fp  dk v  u djs a vkS j

triangle represents girl children. Study the

fuEu iz'uks a ds lgh mÙkj ns aA

diagram and answer the questions that follow. Energetic

Energetic

Girls

Girls 8

8 15 9

11 10

3

Obese 14

12

5 2 1 6 13

9

11

7

4

Tall

15

Tall

10

Obese 14

7

4 3 12

5 2 1 6 13

1/25

Sample question for ASAT : Nurture Course 4.

Which areas represent energetic children who

4.

are not obese ?

5.

dkS ulk  ks  deZB cPpksa dks n'kkZrk gS tks eks Vs ugha gSA

(1) 1, 13 and 15

(2) 13 and 15

(1) 1, 13 rFkk 15

(2) 13 rFkk 15

(3) 1, 11 and 15

(4) 6, 13 and 15

(3) 1, 11 rFkk 15

(4) 6, 13 rFkk 15

Which of the following areas represent obese and

5.

dkS ulk  ks  eks Vs vkS j deZB cPpksa dks n'kkZrk gS tks fd uk rks cfPp;k¡ gS a vkS j uk gh yEcs gS aa ?

energetic children, who are neither girls nor tall ? (1) 2 and 12

(2) 3 and 10

(1) 2 rFkk 12

(2) 3 rFkk 10

(3) 2 and 3

(4) 11 and 12

(3) 2 rFkk 3

(4) 11 rFkk 12

(Q.6

Direction (Q.6 & Q.7): P, Q, R, S, T, V and

vyx&vyx okguks a ls  k=k dj jgs gSA izR;s d okgu I, II

There are at least two passengers in each

vkS j III es a de ls de nks  k=h gS a vkS j mues a ls ds oy  d

vehicle I, II & III and only one of them is a male.

iq:"k  k=h gSA  kf  ksa esa 2 bUthfu;lZ  2 MkWD Vj rFkk v  kid gS aaA

There are two engineers, two doctors and three

3

teachers among them.

(i) R ,d

k=k (ii) Q ,d iq:"k bUthfu;j gS tks fd dsoy W ds lkFk  djrk gS tks fd  d v  kid gS vkS j okgu I es a gSA

(ii) Q, a male engineer, travels with only W, a

(iii) S ,d

teacher in vehicle I.

(iv) nks

(iii) S is a male doctor.

iq :"k MkWD Vj gSA

O;fDr tks fd  d gh is 'ks es a gS a  d gh okgu es a  k=k

(iv) Two persons belonging to the same

ugha djrs gSA

profession do not travel in the same vehicle.

(v) P bUthfu;j

Which of the following is not correct?

ugha gS vkS j okgu II esa  k=k djrk

gSA

(v) P is not an engineer and travels in vehicle II 6.

fuEu es a dkS ulk lR  ugha gS?

(1) T-Male Teacher

(1) T- iq:"k

(2) Q-Male Engineer

(2) Q- iq:"k

v  kid

(3) W-Female Teacher

bUthfu;j kid (3) W- efgyk v 

(4) V-Female Teacher

(4) V- efgyk

How many lady members are there among them? (1) Three (2) Four

2/25

efgyk MkWDVj gS tks fd nks cguks a, P rFkk V ds

lkFk  k=k ugha djrh gSA

with the pair of sisters, P and V

7.

vkS j W rhu

W are travelling in three different vehicles.

(i) R is a lady doctor and she does not travel

6.

Q.7): P, Q, R, S, T, V

7.

v  kid ;kf  ks a ds lewg esa fdruh efgyk lnL  gS a ? (1) rhu (2) pkj

(3) Three or Four

(3) rhu

(4) Data inadequate

(4)

vkS j pkj

vkadM+ as vi;kZIr

Sample question for ASAT : Nurture Course Direction (Q.8 & Q.9) : In a certain code language if ‘pit na sa’ means ‘you are welcome’ ‘na ho pa la’ means ‘They are very good’ ‘ka da la’ means ‘who is good’ ‘od ho pit la’ means ‘they welcome good people’ 8.

Which of the following means ‘people’ in that

8.

code language?

9.

(1) ho

(2) pit

(3) la

(4) od

Which of the following means ‘very’ in that

9.

(2) pit (4) od

fuEu esa ls fdl dk vFk Z dw V Hkk"kk esa ‘ cgq r ’ gS ? (1) na

(1) na

(2) da

(3) pa

(4) data inadequate

A watch, which gains uniformly, is 2 min, slow

10 .

fast at 2 PM on the following Sunday. When was it correct ? (1) 2 : 00 PM on Tuesday (2) 12 Noon on Monday (3) 2 : 00 AM on Tuesday (4) None of these The following question consists of a set of three figures X, Y and Z showing a sequence of folding of a piece of paper. Fig (Z) shows the manner in which the folded paper has been cut. These three figures are followed by four answer figures from which you have to choose a figure which would most closely resemble the

(2) da

vk¡dM+s vi;kZIr ,d  kM+h tks  d lh xfr ls vkxs py jgh gS jfookj nks igj dks 2 min /khes Fkh vkS j vkus okys jfookj dks 2 PM ij 4 min 48 lS d.M vkxs py jgh Fkh rks  g fdl le  ij lgh Fkh ? (1) eaxyokj dks 2 : 00 PM ij (2) lkseokj dks nks igj 12 ij (3) eaxyokj dks 2 : 00 AM ij (4) bues a ls dks bZ ugha fn;s x;s iz'u es a X, Y vkS j Z rhu fp  gS a tks fd  d dkxt  (Z) eks M+s ds VqdM+ksa dks eks M+us dh Ja`[kyk dks n'kkZr s gS aA fp x;s dkxt dks dkVus dk rjhdk n'kkZ rk gSA bu rhu iz'u fp=ksa ds lkFk pkj m¥ Ùkj fp  fn;s x;s gS a ftues a ls vkidks ml lgh fp  dk pquko djuk gS tks fd fp  (Z) okys eqM+s dkxt dks  fn okil QS yk fn;k tk;s ds leku gksA (3) pa

at noon on Sunday, and is 4 min 48 seconds

11 .

Q.9) : ,d  kkl

(1) ho (3) la

code language?

10 .

dwV Hkk"kk es a  fn ‘pit na sa’ vFkkZr~ ‘vkidk Lokxr gS a ’ ‘na ho pa la’ vFkkZr~ ‘ os cgq r vPNs gS a’ ‘ka da la’ vFkkZr~ ‘ dkS u vPNk gS a’ ‘od ho pit la’ vFkkZr~ ‘ os vPNs yks xksa dk Lokxr djrs gS a’ fuEu esa ls fdl dk vFkZ dw V Hkk "kk esa ‘ yk sx ’ gS ? (Q.8

11 .

(4)

unfolded form of fig. (Z).

X

Y

Z

(1)

(2)

(3)

(4)

X

Y

Z

(1)

(2)

(3)

(4) 3/25

Sample question for ASAT : Nurture Course 12 .

In a coded language:

12 .

= 8,

= 10,

= 20,

Then

13 .

=

= 35,

rc

?

=

= 35,

?

(1) 2

(2) 4

(1) 2

(2) 4

(3) 7

(4) 5

(3) 7

(4) 5

Pointing out to a lady, a girl said “She is the

13 .

(1) Sister-in-law (2) Mother (3) Aunt (4) Cousin There are two circular concentric rings, with 26 sectors on each ring marked A to Z. Sectors on outer and inner circles match in a perfect size fit. Whereas the outer ring contains the sectors marked clockwise, the inner ring has sectors marked anticlockwise, such that sectors marked A on both the circles are coinciding at present, B on the outer circle coincides with Z on the inner circle and so on. If the outer circle is rotated clockwise by two sectors from the original position, how many alphabets will coincide on both the circles ? (1) 1 (2) 2 (3) 3 (4) None of these Direction : In the given question a dots are placed in the figure marked as (X), this figure is followed by four alternatives marked as (1), (2), (3) and (4). One out of these four options contains the common region to circle, squares triangle similar to that of marked by dot in figure (X). Select that option.

(1)

14 .

,d efgyk dh vksj b'kkjk djrs gq ;s  d yM+dh dgrh gS fd og es js firk ds bdykS rs iq  dh nknh dh iq  o/kq gSA ml efgyk dk yM+dh ds lkFk D;k fj'rk gS ? (1) uun (2) ekrk (3) pkph (4) HkkbZ  k cgu nks lad Uæh s o` Ùkkdkj xks ys gS a tks fd izR;sd xksys ij 26 txg A ls Z vafdr gSA izR;sd xks ys ds lHkh Hkkx cká vkS j vkUrfjd xks ys ls  d ne lgh lgh vkdkj esa lgh cS Brs gS aA tcfd cká xksy s es a lHkh Hkkx  cka; as ls nka ; as vkS j vkUrfjd xksys es a nka; as ls cka; s bl izdkj va fdr gS a fd xksy aks dk og Hkkx tks A }kjk vafdr gS a orZeku es a  d lkFk iM+sa gS a vkS j B cká xks ys dk vkS j Z vkUrfjd xksy s dk  d lkFk iM+ as gS aA ;fn cká xksys dks viuh okLrfod voLFkk ls  kM+h dh lqbZ dh fn'kk es a nks Hkkx  kqek;k x;k gS a rks nks uksa o`Ùkks a ds fdrus v{kj ,d lkFk iM+ xss a ? (1) 1

(2) 2 (4) bues a ls

dks bZ ugha fn;s x;s iz'u es a fp  (X) fcUnqv aks  kjk vafdr gS blds lkFk pkj oS dfYid fp  (1), (2), (3) vkS j (4) fn;s x;s gS aA fn;s x;s fodYiks a es a ls  d fp  es a o`r oxZ rFkk f=Hkqt dk mHk;fu"B  ks  Bhd mlh izdkj ls iznf'kZr gS tS lk fd fp  (X) esa fcUnqv aks  kjk fpfUgr gSA og fodYi pqfu;s (3) 3

15 .

(X)

(X)

4/25

= 10,

= 20,

only son” How is the lady related to the girl ?

15.

: = 8,

daughter-in-law of the grand mother of my father’s

14 .

,d dwV Hkk"kk esa

(2)

(3)

(4)

(1)

(2)

(3)

(4)


Find the minimum cuts required to divide a

16 .

cube in 125 cubes ? (1) 8

(1) (2) (3) (4)

(2) 10 (3) 12 (4) 15 17 .

,d  ku dks 125 ?kuks a es a ckaVus ds fy;s U;wure fdruh ckj dkVuk iM+ xk s ?

Is country X's GDP higher than country Y's

17 .

 yw vk  ns 'k Y's dh dqy  D;k ns 'k X's dh dq y kjs kjsyw vk 

ls T;knk gS ?

GDP ? (A) GDP's of the countries X and Y have grown

(A) ns'k X rFkk Y dh

dqy  kjsyw vk  fiNys ikap o"kks Z es a Øe'k  5% rFkk 6% ds pØo`f¼ nj ls c  h gS aA

over the past 5 years at compounded annual rate of 5% and 6% respectively.

 ns 'k Y ls T;knk FkhA  kjs yw vk (B) ikap o"kZ igys ns 'k X dh dq y

(B) 5 years ago, GDP of country X was higher than that of country Y.

d (1) ;fn iz'u dk mÙkj nks uks a es a ls 

(1) If the question can be answered by one of

gh dFku  kjk fn;k tkuk

gSA nwljs ls ughaA

the statements alone and not by the other.

(2) ;fn iz 'u dk mÙkj fdlh Hkh  d dFku  kjk fn;k tkuk gSA

(2) If the question can be answered by using

(3) ;fn iz 'u dk mÙkj nks uks a dFkuks a dk iz ;ks x

dj fn;k tk ldrk gks ys fdu fdlh Hkh  d dFku ds  kjk ugha fn;k tk ldrkA

either statement alone (3) If the question can be answered by using both the statements together, but cannot be answered by using either statements alone.

(4) ;fn

(4) If the question cannot be answered even by

iz'u dk mÙkj nksu aks dFkuksa dk iz;ksx djds Hkh ugha

fn;k tk ldrk

using both the statements together. 18 .

8 10 12 15

different letters in the problem below, so that

fn;s x;s iz'u es a izR;s d v{kj dh txg vad (0, 1, 2.....,9) izfrLFkkfir dhft;s rkfd le:ih tks M  lgh gksA rFkk

the corresponding addition is correct and it

ifj.kkeLo:i MONEY dk vf/kdre lEHkkfor eku

results in the maximum possible value of

gksA

Substitute different digits (0, 1, 2.....,9) for

18 .

MONEY.

ifj.kkeLo:i 'MONEY' dk eku gksxk (1) 10364 The resulting value of 'MONEY' is

(2) 10563

(1) 10364

(2) 10563

(3) 10978

(3) 10978

(4) None of these

(4)

dks bZ ugha

5/25


Following question has a set of four statements.

19 .

alternative where the third segment in the

rhu Hkkx gS aA og fodYi pqfu;s ftles a fd dFku dk rhljk Hkkx rdZl xr a gks ftles a igys nks uks a Hkkxksa dk iz; x ks fd;k x;k

statement can be logically deduced using both

gks ys fdu dsoy  d Hkkx dk ughaA

Each statement has three segments. Choose the

the preceding two but not just from one of them.

frgkfld jpuk gSA leqæh HkS l a Mk;uklks j (A) Mk;uklksj iwoZ 

(A) Dinosaurs are pre-historic creatures. Water-

ugha gSA leqæh HkS al iwoZ  frgkfld jpuk ugha gSA

buffaloes are not dinosaurs. Water buffaloes

(B) lHkh jktuS frK  kq ys fny okys gS aA dks bZ Hkh  kq ys fnu okyk

are not pre-historic creatures.

exjePN ugha gSA dksbZ Hkh exjePN jktuS frK ugha

(B) All politicians are frank. No frank people are

crocodiles.

No

crocodiles

gSA

are

(C) dksbZ ghjk LQq fVd

politicians.

(D) lHkh

Diamonds are opals. (D) All monkeys like bananas. Some GI Joes

(1) ds oy C

(1) C only

(2) ds oy B

(2) B only

(3) A rFkk D

(3) A and D

(4) B rFkk C

(4) B and C

John. He drove 30 km towards north and then 40 km towards west. He then turned to south and covered 8 km. Further he turned to east and moved 26 km. Finally he turned right and drove 10 km and then turned left to travel 19 km. How far and in which direction is he from the starting point?

6/25

cUnj ds ys ds leku gS aA dqN GI Joes dsy s ds

leku gS aA dqN GI Joes cUnj gS aA

like bananas. Some GI Joes are monkeys.

Mr. Raghav went in his car to meet his friend

ugha gSA dksb Z Hkh nwf/k;k iRFkj LQqfVd

ugha gSA ghjs nwf/k;k iRFkj gS aA

(C) No diamond is quartz. No opal is quartz.

20 .

fuEufyf[kr iz'u pkj dFkuks a dk lewg gSA izR;sd dFku ds

20 .

fe- jk?ko viuh dkj ls vius nks Lr tkWu ls feyus x;sA igys mUgks us a 30 km mÙkj dh vks j fQj 40 km if'pe dh vks j dkj pykbZ rRi'pkr~ dkj nf{k.k fn'kk es a eks M+ h vkS j 8 km pykbZ fQj dkj iwoZ fn'kk es a eks M+h vkS j 26 km pykbZA vUr es a dkj dks nk;ha vks j eks M+k vkS j 10 km ys x ;k vkS j fQj cka;h vkS j eks M+k vks j 19 km ys x;kA vc og viuh izkjfEHkd fLFkfr ls fdruh nw j rFkk fdl fn'kk es a gSA

(1) East of starting point, 5 km

(1) izkjfEHkd

fLFkfr ds iwoZ , 5 km

(2) East of starting point, 13 km

(2) izkjfEHkd

fLFkfr ds iwoZ , 13 km

(3) North-East of starting point, 13 km

(3) izkjfEHkd

fLFkfr ds mÙkj iwoZ , 13 km

(4) North-East of starting point, 5 km

(4) izkjfEHkd

fLFkfr ds mÙkj iwoZ , 5 km

Sample question for ASAT : Nurture Course PART-II SECTION-A : PHYSICS This section contains 20 multiple choice questions. Each question has four choices (1), (2), (3) and (4) out of which ONLY ONE is correct.

a 20 bl  k.M se 21 .

gSA izR;s d iz'u esa pkj fodYi (1), (2), (3) vkS j (4) gS a ftues a ls lgh gSA All the bulbs below are identical. Which bulb(s) 21 . uhps fn[kk;s x;s cYc  d leku gks rks dkS ulk cYc T;knk light(s) most brightly ? jks 'kuh ns xh ? 1

3

4

1

5

22 .

23 .

24 .

(2) 2 only

(3) 3 and 4 (4) 1 and 5 A piece of copper and another of germanium are cooled from room temperature to 80 K. The resistance of (1) Each of them increases (2) Each of them decreases (3) Copper increases and that of germanium decreases (4) Copper decreases and that of germanium increases What is the total resistance, between A and B in the circuit shown in the given figure.

22 .

(2) dsoy 2

(3) 3 and 4

(4) 1 and 5

,d rkez vkS j tes Zfu;e ds VqdM+ksa dks lkekU  rki ls 80 K rd B.Mk fd;k tkrk gS rks izfrjks/k

23 .

(1) nksuksa

dk c  sxk

(2) nksu aks

dk  kVs xk

(3) rkez

dk c  sxk  tes Zfu;e dk  kVsxkA

(4) rkez

dk  kVsxk  tesZfu;e dk c
fn;s x;s fp  es a A vkS j B ds chp dqy izfrjks/k gS (1) 4

W

(2) 5

W

W

(2) 5

W

(3) 2

W

(3) 2

W

(4) 9

W

(4) 9

W

A wire is placed vertically between the poles of a horse-shoe magnet, such that the north pole is to your left and south pole is to your right. It carries a direct current flowing upwards then it will experience a force tending to deflect it

24 .

,d rkj dks  kqM+uky pqEcd ds  kzqo aks ds e  Å/okZ/kj  i ls bl izdkj j[kk x;k gS fd mÙkjh  kzqo vkids cka;h vkS j o nf{k.kh  kzqo nka;h vks j gSA blesa fn"V (DC) /kkjk Åij dh vksj cg jgh gS rks bl ij yxus okys cy ds dkj.k  g fuEu rjg ls fo{ks fir gks xkA (1) vkids cka;h vksj

(2) to your right

(2)

vkids nka;h vks j

(3) away from you

(3)

vkils nwj dh vks j

(4)

vkidh vks j

(4) towards you

5

(1) dsoy 1

(1) 4

(1) to your left

4 2

2

(1) 1 only

3

7/25


The ratio of equivalent resistance across A and B when

25 .

switch is open to that when switch is

fLop pkyq djus rFkk cUn djus ij Øe'k  A rFkk B ds e  rqY  izfrjks/k dk vuqikr gks xkA

closed is

(1)

(3) 26 .

3

(2)

8 7

(4)

8

5

(1)

8 9

(3)

8

A charged particle moves through a region of

26 .

magnetic field pointing in the direction perpendicular to its direction of velocity. Then during its subsequent motion,

8 7

(4)

8

(2) Its momentum and kinetic energy both changes. (3) Its momentum and kinetic energy both remains constant. (4) Its kinetic energy changes but the 27 .

motion such that it covers 100 rounds per min. Then the minimum time after which its average velocity will be zero is (2) 0.6 s

(3) 0.7 s

(4) 0.8 s

F or a bo dy o f 50 k g ma ss , th e ve lo ci t y-t i me graph is shown in figure. Then force acting on

9 8

ifjo£rr gksxk ijUrq xfrt ÅtkZ vifjo£rr

(2) laosx  oa

xfrt ÅtkZ nks uks a ifjo£rr gks xhA

s  oa (3) lao x

xfrt ÅtkZ nks uks a fu;r gks xhA

xfrt ÅtkZ ifjo£rr gks xh ys fdu lao xs fu;r

jgs xkA

momentum remains constant.

(1) 0.5 s

8

,d vkos f'kr d.k  d pqEcdh   ks  ls xq tjrk gS tks fd blds osx dh fn'kk ds yEcor~ fn'kk es a gSA rc bldh xfr ds nkS jku 

(4) bldh

A body starts performing uniform circular

5

jgsxhA

energy remains constant.

28 .

(2)

(1) laosx

(1) Its momentum changes but the kinetic

27 .

3

28 .

,d d.k o`Ùkkdkj iFk es a xfr djuk vkjEHk djrk gS  oa izfr feuV 100 pDdj yxkrk gSA Kkr dhft;s og de ls de le  ftles a vkS lr os x 'kwU  gks xk (1) 0.5 s

(2) 0.6 s

(3) 0.7 s

(4) 0.8 s

,d oLrq  ftldk æO;eku 50 kg gS dk os x  le  xzkQ fn;k x;k gSA oLrq ij yx jgk cy gks xkA

the body is ) s / m 1 ( y t i c0.5 o l e V

) s / m 1 ( y t i c0.5 o l e V

1

8/25

2

1

t(s)

2

t(s)

(1) 25 N

(2) 50 N

(1) 25 N

(2) 50 N

(3) 12.5 N

(4) 100 N

(3) 12.5 N

(4) 100 N


Superconductors are materials that appear to

29 .

exhibit no resistance. Therefore, electrons passing through a superconductor will (1) generate no current (2) generate no heat (3) increase the current’s power (4) decrease the electrons’ charge 30 .

A conductor with rectangular cross-section has

30 .

dimensions (a × 2a × 4a) as shown in figure. Resistance across AB is x, across across

31 .

EF

CD

is y and

is z. Then

(1) x = y = z

(2) x > y > z

(1) x = y = z

(2) x > y > z

(3) y > z > x

(4) x > z > y

(3) y > z > x

(4) x > z > y

Fleming’s right hand rule gives

31 .

(1) The magnitude of induced current (2) The magnitude of the magnetic field (3) The direction of induced current (4)Both magnitude and direction of the induced current 32 .

vfrpkyd os inkFkZ gS tks dksb Z izfrjks/k ugha n'kkZrs gS aA blfy;s vfrpkyd ls xqtjus okys bysDVªkWu  (1) dks bZ  kkjk mRiUu ugha djrsA (2) dksbZ Å"ek mRiUu ugha gks xhA  k;sxAs (3) /kkjk dk lkeF;Z c (4) bysDVªkWu dk vkos 'k  kVk;sxsA ,d pkyd tks fd vk;rkdkj vuqizLFkdkV dk gS ftldh foek;sa (a × 2a × 4a) fp  es a n'kkZ; h x;h gS AB ds e  izfrjks/k x gS, CD ds e  y gS rFkk EF ds e  z gS rks 

A wire PQ carrying a current 'i' is placed

32 .

perpendicular to a long wire XY carrying a current I. The direction of force on PQ will be

¶ysfeax ds nka;s gkFk dk fu;e D;k crkrk gSA kkjk dk ifjek.k (1) izsfjr  (2) pqEcdh 

 ks  dk ifjek.k

(3) izsfjr  kkjk

dh fn'kk

kkjk (4) izsfjr 

dh fn'kk o ifjek.k nksu aks dks

,d rkj PQ ftlesa  kkjk 'i' izokfgr gks jgh gS dks  d yEcs rkj XY ftlesa  kkjk I gS ds yEcor~ fp=kuqlkj j[kk tkrk gSA PQ ij yx jgs cy dh fn'kk gks xhA Y

Y P I

i

P

Q I

l

(1) nka;h

(1) towards right (2) towards left (3) upwards (4) downwards In SONAR, we use (1) ultrasonic waves (2) infrasonic waves (3) radio waves (4) audible sound waves

Q

X

X

33 .

i l

33 .

vksj (2) cka;h vks j (3) Åij dh vks j (4) uhps dh vks j lksukj (SONAR) es a mi;ks x yh tkrh gSA (1) vYVª klks fud rjax a s (2) bUÝklks fud rjaxsa (3) js fM;ks rjax as   ofu rjax as (4) JO 9/25


Which of the following statements is incorrect?

34 .

fuEu es a ls dkS ulk dFku vlR  gks xk ? (1) ;fn oLrq dk os x ifjorZu'khy gS rks bldk Roj.k 'kw  U ugha gksxkA (2) ;fn oLrq dh pky ifjorZu'khy gS rks bldk Roj.k 'kw  U ugha gksxkA (3) ;fn oLrq dk Roj.k gS rks bldh pky ifjo£rr gksxhA (4) ;f n oLrq dk Roj.k gS rks bldk os x if jo£rr gksxkA

35 .

,d xs an ftldk dqN æO;eku gS v0 os x ls  kS frt ry es a xfr  xa dj jgh gSA xs n a fdlh vU s n ls tks fLFkj j[kh gS rFkk æO;eku pkj xquk gS ls Vdjkrh gSA izFke xsan Vdjkus ds i'pkr~ rqjUr fLFkj voLFkk esa vk tkrh gS  rks f}rh  xs an dk os x

(1) If the velocity of a body changes, it must have some acceleration. (2) If the speed of a body changes, it must have some acceleration. (3) If the body has acceleration, its speed must change. (4) If the body has acceleration, its velocity must change. 35 .

A ball having a certain mass is moving with a velocity v0 on a horizontal surface. The ball collides with a stationary ball having four times its mass. The first ball immediately comes to rest after collision then with what velocity will the

crkbZ;sA  k"kZ.k jfgr lrg ekurs gq;s

second ball move? (Assume frictionless surfaces)

36 .

(1) 0.25 v 0

(2) 0.5 v 0

(3) 4 v0

(4) v0

Ananya is travelling to visit her grandmother.

36 .

(1) 0.25 v 0

(2) 0.5 v 0

(3) 4 v0

(4) v 0

vuU;k viuh nknh ls feyus tk jgh gSA izFke  og vkS lr pky

First, she travels at an average speed of 12 km/h

 djrh 12 km/h ls 10 km r

for 10 km. Then she travels at 8.0 km/h for

1.25 ?k.Vs ds fy;s 8.0 km/h ls pyrh

another 1.25 h. Calculate her average speed for the entire trip to her grandma's house.

gSA blds ckn vxys

nkS jku mldh vkS lr pky crkbZ;sA (1) 3.2 km/h

(1) 3.2 km/h (2) 4.4 km/h

(2) 4.4 km/h

(3) 9.6 km/h

(3) 9.6 km/h

(4) 19.2 km/h

(4) 19.2 km/h

Comprehension for (Q.No.37 & Q.No.38) A rotating device is shown in figure, answer the following questions :

( 37

38)

fp  es a  d  kwf.kZr q fDr n'kkZ;h xbZ gS fuEu iz'uks a ds mÙkj nhft,A

C

B

C

B

:-

S S

N

N C 2

C 2 B1

B2

B1

P

10/25

B2 C 1

C 1 +

D

A

D

A

+ – Q

P

– Q

gSA iwjh xfr ds


37 .

The device shown in figure is : (1) A dc motor (2) An ac motor (3) An ac generator (4) A dc generator

38 .

In the given figure the direction of force

38 .

fp  esa n'kkZ;h q fDr gS : (1) dc eksVj (2) ac eksVj  (3) ac tfu (4) dc tfu  fn;s x;s fp  es a Hkqtk AB ij dk;Zjr cy dh fn'kk gS :

acting on arm AB is :

(1) vUnj dh vks j ( dkxt

(1) Inwards (into the paper)

(2) ckgj

dh vksj ( dkxt ds ckgj )

(3) ck;ha

vksj

(2) Outwards (out of paper) (3) Leftwards

ds vUnj )

(4) AB Hkqtk ij dksbZ cy ugha ( 39 40) :-

(4) No force will act on arm AB Comprehension for (Q.No.39 & Q.No.40)

fp  es a rhu vkos 'k n'kkZ, s x;s gSA nks utnhdh vkos 'kksa ds e  nwjh d gSA

There are three charges placed as shown in figure. The distances between two nearby charges are d.

d d Q

39 .

d –Q/2

The force on 2Q will be

Q

39 .

2Q ij

cy gks xk

KQ 2 (1) 2d 2

ck;ha vks j

KQ 2 (2) towards right 2d 2

(2)

KQ 2 2d 2

nk;ha vksj

3KQ 2 (3) 2d 2

3KQ towards right 2d 2

KQ 2 (1) towards left 2d 2

KQ 2 (2) towards right 2d 2 3KQ 2 (3) towards right 2d 2

(4) zero

nk;ha vksj

(4) 'kw  U

(4) zero The force on –Q/2 will be

2Q

2Q

2

40 .

–Q/2

KQ 2 (1) towards left 2d 2

(3)

d

40 .

–Q/2 ij

cy gks xk

KQ 2 (1) 2d 2

ck;ha vks j

KQ 2 (2) 2d 2

nk;ha vksj

(3)

3KQ 2 2d 2

nk;ha vksj

(4) 'kw  U 11/25

Sample question for ASAT : Nurture Course SECTION-B : CHEMISTRY This section contains 20 multiple choice questions. Each question has four choices (1), (2), (3) and (4) out of which ONLY ONE is correct.

bl  k.M se a 20 41 .

gS aA izR;s d iz'u es a pkj fodYi (1), (2), (3) vkS j (4) gS a ftues a ls

A volatile liquid has :

41 .

(1) low boiling point and weaker interparticle forces (2) high boiling point and weaker interparticle forces. (3) high boiling point and stronger interparticle forces (4) low boiling point and stronger interparticle forces. 42 .

Which of these is a solution ?

42 .

(1) 14 Carat Gold (2) Salted water (3) Carbonated water (4) All of these 43 .

When

sodium

bisulphite

reacts

with

43 .

hydrochloric acid, the products formed are : (1) NaCl, H 2O and SO 2 (2) Na 2SO 4 and NaCl (3) NaCl and H 2S (4) No reaction takes place 44 .

44 .

....................................... coloured ppt is

45 .

whose

chemical

formula

is

 NaOH, ls djk;h tc Qs fjd Dyks jkbM dh vfHkfØ;k tyh tkrh gS rc ....................................... jaxhu vo{ks i iz kIr gk sr k gS vkSj ml dk jklk; fud lw  gks xkA

:........................................

........................................

(1) Brown, Fe(OH) 2

(1)

(2) Green, Fe(OH) 2

(2) gjk , Fe(OH) 2

(3) Green, Fe(OH) 3

(3) gjk , Fe(OH) 3

(4) Brown, Fe(OH) 3

(4)

Number of molecules in 500 ml of each H2, O2 and CO 2 at STP are in the order

45 .

Hkwjk , Fe(OH)2

Hkwjk , Fe(OH) 3

STP ij H2, O2 rFkk CO2 izR;s d

mifLFkr v.kqv aks dh la  k 

(1) H2 < O2 < CO2

(1) H2 < O2 < CO 2

(2) H2 > O2 > CO2

(2) H2 > O2 > CO 2

(3) H2 = O2 = CO2

(3) H2 = O2 = CO 2

(4) H2 > O2

12/25

ok"i'khy nz o j[krk gS :  cy (1) de DoFkukad rFkk nqcZ y vUrjd.kh (2) mPp DoFkukad rFkk nqcZy vUrjd.kh  cy  cy (3) mPp DoFkukad rFkk izcy vUrjd.kh  cy (4) fuEu DoFkukad rFkk izcy vUrjd.kh fuEu es a ls dkS ulk foy;u gS ? (1) 14 dS js V lks uk  ikuh (2) yo.kh (3) dkcks Zu Vs s M ikuh (4) lHkh tc lks fM;e ckbZ lYQkbV  gkbMª ksDyksfjd vEy ls vfHkfØ;k djrs gS rks tks inkFkZ curk gS : (1) NaCl, H2O rFkk SO2 (2) Na2SO4 rFkk NaCl (3) NaCl rFkk H2 S (4) No reaction takes place

When ferric chloride reacts with aq. NaOH, a formed,

¹

CO 2

lgh gSA

(4) H2 > O2

¹

CO 2

ds 500 ml fyVj es a


Which among the following statements about

46 .

the reaction given below are CORRECT? MnO2 + 4 HCl

® MnCl2

+ 2H2O + Cl 2

(I) Manganese oxide is oxidised (II) Hydrogen Chloride is reduced (III) Manganese oxide is oxidising agent (IV) Hydrogen Chloride is reducing agent

47 .

(1) I and II

(2) III and IV

(3) II and IV

(4) I, II, III and IV

Which

of

the

following

statements

is

47 .

INCORRECT ?

(1) HPO42– , H2PO4– dk –

2–

(1) The conjugate base of H 2 PO 4 is HPO4 . (3) H3PO 3 is a tribasic acid. (4) The concentration of H+ ions in pure water Which of the following has arranged in order

48 .

of increasing oxidation numbers of nitrogen? (1) NH 3 < N2O5
–

(2) NO 2 < NO 3
49 .

(3) H3PO3 ,d

 f kkjdh  vEy gS

(4) 'kq¼

298 K rki

ty esa

ij H+ vk;u dh lkaærk

gSA fuEu es a ls ukbVªkstu ds c  rs gq  vkWDlhdj.k vad dk Øe gksxk ? (1) NH 3 < N2O5
–

(2) NO 2+ < NO 3–
(3) NH 4+ < N2H4 < NH 2OH < N 2 O

(3) NH 4+ < N2 H4 < NH 2OH < N 2O

(4) NO2 < NaN 3 < NH 4+ < N2O

(4) NO 2 < NaN 3 < NH 4+ < N2O

Which among the following statements is

49 .

INCORRECT for magnesium metal?

gSA

flame.

(2) ;g

B.M+s ikuh ds lkFk eS Xuhf'k;e vkWDlkbM dk fuekZ.k rFkk gkbMª tu ks xS l dks fu"dkflr djrk gSA

(2) It reacts with cold water to form magnesium oxide and evolves hydrogen gas.

(3) ;g xeZ ikuh ds lkFk eS Xuhf'k;e gkbMªkWDlkbM dk fuekZ .k

(3) It reacts with hot water to form magnesium

rFkk gkbMª tu ks xS l dks fu"dkflr djrk gSA

hydroxide and evolves hydrogen gas.

(4) ;g

Hkki ds lkFk eS Xuhf'k;e vkWDlkbM dk fuekZ.k rFkk gkbMª kstu xS l dks fu"dkflr djrk gSA

(4) It reacts with steam to form magnesium oxide and evolves hydrogen gas. For a reaction A + 2 B

fuEu esa ls eS Xuhf'k;e  kkrq ds fy;s dkS ulk dFku gS ? (1) ;g vkWDlhtu ds lkFk tykus ij pednkj lQs n ykS nsrk

(1) It burns in oxygen with a dazzling white

50 .

eku 'kwU  gSA

10–7 mol L–1 gksrh

is 10 –7 mol L–1 at 298 K.

+

la;qXeh  kkj gSA

(2) 1 eks yj HCl ds pH dk

(2) The pH of 1 M HCl is 0.

48 .

fuEu esa ls dkS ulk dFku nh x;h vfHkfØ;k dh fy;s gksxk ? MnO2 + 4 HCl ® MnCl2 + 2H2O + Cl 2 (I) eS Xuht vkWDlkbM vkWDlhd`r gks xkA (II) gkbMªkstu Dyks jkbM vipf;r gksxkA (III) eS Xuht vkWDlkbM vkWDlhdkjh vfHkdeZd gSA (IV) gkbMª ks tu Dyks jkbM vipk;d vfHkdeZ d gSA (1) I rFkk II (2) III rFkk IV (3) II rFkk IV (4) I, II, III rFkk IV fuEu es a ls dkS ulk dFku gS ?

® C,

the amount of C

formed by starting the reaction with 5 moles of A and 8 moles of B is

50 .

fuEu vfHkfØ;k A + 2 B ® C es a izkjfEHkd eksyksa dh la  k A dh 5 rFkk B dh 8 yh tkrh gS rks C dh ek=k D;k cus xhA

(1) 5 moles

(2) 8 moles

(1) 5 moles

(2) 8 moles

(3) 16 moles

(4) 4 moles

(3) 16 moles

(4) 4 moles 13/25


Which of the following metals are refined by

51 .

electrolytic refining?

52 .

(i) Au

(ii) Cu

(i) Au

(ii) Cu

(iii) Zn

(iv) K

(iii) Zn

(iv) K

(1) (i) and (ii)

(2) (ii) and (iii)

(1) (i) rFkk (ii)

(2) (ii) rFkk (iii)

(3) (i), (ii), (iii)

(4) (ii), (ii i) and (i v)

(3) (i), (ii), (iii)

(4) (ii), (iii) rFkk (iv)

How many moles of ferric alum (NH 4 )2SO 4·

52 .

Fe2(SO4)3·24H2O can be made from the sample of Fe containing 0.0056 g of it ?

53 .

[Fe dk

(1) 10 –4 mol

(2) 0.5 × 10–4 mol

(1) 10 –4 mol

(2) 0.5 × 10–4 mol

(3) 0.33 × 10 –4 mol

(4) 2 × 10–4 mol

(3) 0.33 × 10 –4 mol

(4) 2 × 10–4 mol

How many moles of O2 will be liberated by one

53 .

fuEu vfHkfØ;k es a  d eks y CrO5 ysus ij O2 ds fdrus eks y eqDr gks xsaA CrO5 + H2 SO4 ¾® Cr2(SO 4)3 + H2O + O2

(1) 4.5

(2) 2.5

(1) 4.5

(2) 2.5

(3) 1.25

(4) None of these

(3) 1.25

(4) bues a ls

If your teeth start decaying, the dentist may

54 .

the following is not used as the dental filling?

(1) lks uk

(2) Sorel's cement

(2) lks js y

(3) Zinc oxychloride

(3) ftad

Bleaching powder has several uses, some of which are mentioned here. Pick the false one?

55 .

fojatd pw.kZ  Cyhfpaax ikmMj  ds dbZ mi;ks x gS ftuesa ls dqN uhps fn;s x;s gS xyr dks pqfu;s ? (1) 'kdZjk

(2) For bleaching paper pulp

(2) is ij

(4) For making chloroform

lhes UV

vkWDlhDyksjkbM (4) ftad

(1) For decolourising sugar

(3) For sterilizing water

dksb Z ugha

vxj vkids nk¡rks dk fx juk  k  k  gksuk 'kq  gks x;k gS vkS j nUr fpfdRld us vkidks nUr HkjkbZ dk lq>ko fn;k gS rks fuEu es a ls dkS ulk nUr HkjkbZ ds fy  mi;ksx es a ugha ys xs a ?

(1) Gold

(4) Zinc

14/25

ijek.kq æO;eku = 56 u]

CrO5 + H2SO4 ¾® Cr2 (SO 4)3 + H2O + O2

advise you to have your teeth filled. Which of

55 .

(vk;ju  ds 0.0056 g ds  d uew us ls fdrus eks y Qsfjd  ye (NH4)2SO4 · Fe 2(SO4)3·24H2O ds cuk ldrs gSA Fe

[Atomic mass of Fe = 56 u]

mole of CrO5 in the following reaction?

54 .

bues a ls dkS ulk  kkrq ,s a oS |q rvi?kVuh ifj"dj.k ls ifj"d`r dh tkrh gS ?

dk fojatdhdj.k

iYi dk fojatu (3) ikuh ds jks xk.kquk'ku ds fy;s (4) Dyks jks QkeZ cukus ds fy;s


5.85 g of NaCl was treated with concentrated

56 .

x;k vkS j fu"dkflr xS l dks flYoj ukbVª s V ds foy;u ls xq tkjk x;kA izkIr lQs n vo{ks i dks Nkuk tkrk gS lq[kk;k tkrk gS rFkk Hkkj djrs gS aA  fn vfHkfØ;k lEiw.kZ gks rh gS rks vo{ksi dk fdrus xzke izkIr gksxkA

H2SO 4 and the gas evolved was passed into a solution of silver nitrate. The white precipitate obtained was filtered, dried and weighed. Assuming complete reaction, how many grams of precipitate was obtained ?

[Ag dk

[Atomic mass of Ag = 108 u, Na = 23 u &

Cl = 35.5 u]

Cl = 35.5 u] (1) 10.8g

(2) 14.35g

(3) 35.5g

(4) 3.65g

by dissolving 3.65 gram HCl in distilled water. (1) 0.01 M (2) 0.02 M (3) 0.2 M 58 .

57 . 58 .

solution will be :(1) zero (3) 5 × 10

(2) 5 × 10 –14

–12

M

(3) 35.5g

(4) 3.65g 58)

(4) can not be calculated

Which of the following concepts was not considered in Rutherford’s atomic model ? (1) the electrical neutrality of atom (2) the quantization of energy (3) electrons revolve around nucleus at very high speeds (4) existence of nuclear forces of attraction on the electrons

59 .

60 .

(4) 0.1 M

bl foy;u es a gkbMªksDlkbM vk;u dh eks yjrk D;k gks xh :-

( 59

motion in solar system. Therefore, Rutherford’s model of atom is also called planetary model. When alpha particles are sent through a thin metal foil only one out of ten thousand of them is reversed. This observation led to the conclusion that (1) An extremely small positively charged particles are concentrated at the centre of the atom (2) more number of electrons are revolving around the nucleus of the atom (3) unit positive charge is only present in an atom (4) a massive sphere with more negative charge and unit positive charge is present at the centre of the atom

:-

ty es a foys  djds HCl gkbMªksDyksjhd vEy dk 500 mL foy;u cuk;k x;kA foy;u es a Dyks jkbM vk;u dh eks yjrk D;k gS ?

(3) 5 × 10

Rutherford’s atomic model resembles the planetary

60 .

(2) 14.35g

–12

(1) 'kq  U

Comprehension for (Q.No.59 & Q.No.60)

59 .

(1) 10.8g

(1) 0.01 M (2) 0.02 M (3) 0.2 M

(4) 0.1 M

The molarity of the hydroxide ions in this

u, N a = 2 3 u &

3.65 gram HCl dks 'kq¼

500 mL solution of hydrochloric acid is made What is the molarity of chloride ions in the solution?

ijek.kq æO;eku = 1 08

( 57


57 .

NaCl ds 5.85 g dks lkaæ H2SO4 ds lkFk mipkfjr fd;k

(2) 5 × 10 –14

60)

M

(4) can not be calculated :-

jnjQksM Z dk ijek.kq izfrj{kk lw;Z ra  es a x`g ds  kw .kZ u ds leku gSA blfy  jnjQksMZ ijek.kq izfr:i dks x` g izfr:i Hkh dgrs gSA iryh  kkrq iékh es a ls tc a d.kksa dks izdhf.kZr fd;k rc 10,000 es a ls  d a- d.k mlh fn'kk es a ykS V tkrk gS bl ?kVuk ls fu'd"kZ fudyrk gS  (1) ijek.kq ds dsUnz es a vfrlw{e  kukosf'kr d.k mifLFkr gks rs gSA (2) ijek.kq ds ukfHkd ds pkjks vksj bysDVªkWu  kwf.kZr djrs gSA dy bdkbZ  kukos'k gks rk gSA (3) ijek.kq es a ds oy   Dr vf/kd (4) ijek.kq ds ds Unz esa xksykdkj nzO;eku q ½.kkRed vkos 'k rFkk bdkbZ  kukos'k mifLFkr gks rk gS jnjQks MZ es a ijek.kq ekWMy  izfr:i  es a fuEu es a ls dkS ulh vfHk/kkj.kk ugha yh x;h Fkh ? (1) ijek.kq dh fo|qr mnklhurk (2) ÅtkZ dk DokaVhdj.k (3) ukfHkd ds pkjks vks j bysDVªkWu mPp osx ls xfr djrs gS aA (4) bys DVª uks kW a ij ukfHkdh  vkd"kZ .k cy dk vfLrRo gks rk gSA 15/25

Sample question for ASAT : Nurture Course Attempt any one of the section C or D Section C or D section SECTION-C : MATHEMATICS This section contains 20 multiple choice questions. Each question has four choices (1), (2), (3) and (4) out of which ONLY ONE is correct.

a 20 bl  k.M se 61 .

a, b, c are three

gSA izR;s d iz'u es a pkj fodYi (1), (2), (3) vkS j (4) gS a ftues a ls lgh gS real numbers such that 61 . a, b, c rh u okLrfod la  k,s a bl iz d kj gS fd

a + b + c = 7, a 3

3

2

+ b

2

2

a + b + c = 7, a2 + b2 + c2 = 35 vkS j a3 + b3 + c3 = 151

+ c = 35 and

3

gSA

a + b + c = 151. Find the value of abc.

62 .

abc dk

eku Kkr dhft,A

(1) 12

(2) 14

(1) 12

(2) 14

(3) –15

(4) –13

(3) –15

(4) –13

In the given figure, O is the centre and AB is

62 .

O;kl gSA AC rFkk BD dks c  kus ij  g E ij feyrs gSA ;fn ÐCOD = 50°, rc ÐCED =________?

a diameter of the circle. AC and BD when produced, meet at E. If

ÐCED

Ð COD

uhps  d fp  fn;k x;k gS ftlesa O dsUnz rFkk AB o`r dk

= 50°, then

=________? A C

A

E C

50°

O

E

D

50°

O D

B

B

63 .

(1) 100°

(2) 65°

(3) 130°

(4) None of these

If A + B = 225°, then the value of (1 + tan A)

63 .

(1 + tan B) is

64 .

(2) 65°

(3) 130°

(4) bues a ls

;fn A + B = 225°, rc (1 + dk eku gks xk\

(2) 3

(1) 1

(2) 3

(3) 2

(4) 4

(3) 2

(4) 4

Value of (a – c) [(a – b)2 + (b – c)2 – (a – b)

64 .

dksb Z ugha

tan A) (1 + tan B)

(1) 1

(b – c)] + (c – a)3 is equal to

16/25

(1) 100°

(a – c) [(a – b)2 + (b – c) 2 – (a – b) (b–c)] + (c–a)3

dk eku cjkcj gksxk 

(1) 3(a – b) (b – c) (c –a)

(1) 3(a – b) (b – c) (c –a)

(2) (a – b) (b – c) (c – a)

(2) (a – b) (b – c) (c – a)

(3) (a – b) 3 (b – c)3 (c – a)3

(3) (a – b)3 (b – c)3 (c – a)3

(4) None of these

(4) bues a ls

dksb Z ugha


The value of m if 2x m + x3 – 3x2 – 26 leaves

65 .

x – 2. (2) 7

(1) 0

(2) 7

(3) 10

(4) All of these

(3) 10

(4) mijks Dr

If 20 men take 30 days to complete a job, in

66 .

job ? (1) 23

(2) 24

(3) 25

(4) 26

The remainder when x 1999 is divided by

67 .

x2 – 1 is

68 .

(2) 24

(3) 25

(4) 26

;fn x1999 dks x2 – 1 }kjk foHkkftr fd;k tkrk gS rks 'ks "kQy gS(1) – x

(2) 3x

(3) x

(4) None of these

(3) x

(4) bues a ls

q

=

-

1

and

5 then the value of cos

(3) If

q lies q

5

-1

68 .

is

-

5

(1)

6

(3)

(4) Both (1) and (2)

6

a = b+ c and

c are three

a, b and

(1)

a is dissimilar to

(2)

b and

(3) Only

b and

c are similar to b is similar to

;fn tan q cos

(2)

6

in the II quadrant,

69 .

surds, then

c a

The leading coefficient of a polynomial P(x) of degree 3 is 2006. Suppose that P(1) = 5, P(2) = 7 and P(3) = 9, then find P(x).

70 .

=

-

1 5

dks bZ ugha

vkS j q f}rh  prqF kk±'k es a gS rc

q dk eku Kkr dhft,A 5

(2)

6

-1

-

5 6

(4) (1) o (2) nksuksaA

6

;fn a = b+ c , rc

a, b

o

c

rhu dj.kh gS

(1)

a

dk eku b o c ds leku ugha gSA

(2)

b

o c dk eku a ds leku gSA

(3) ds oy

a

(4) None of these 70 .

(1) 23

(2) 3x

If tan

lHkh

;fn 20 O;fDr feydj fdlh dk;Z dks 30 fnu esa iw.kZ djrs gS rks 25 O;fDr blh dk;Z dks iwjk djus es a fdrus fnu ys xs a ?

(1) – x

(1)

69 .

+ x3 – 3x 2 – 26

(1) 0

how many days can 25 men complete the

67 .

eku Kkr dhft   fn 2x m

dk s x – 2 }k jk foHkk ftr djus ij 'ks "kQy 22 6 vkrk gks 

a remainder of 226 when it is divided by

66 .

m dk

dk eku gh a ds leku gSA (4) bues a ls dks bZ ugha fdlh rhu  kkr ds cgqin ds vf/kdre  kkr dk xq. kkad 2006 gS ekuk P(1) = 5, P(2) = 7 rFkk P(3) = 9 rks P(x) dk eku gks xkA b

(1) 2006 (x–1) (x–2) (x– 3) + 2x + 3

(1) 2006 (x–1) (x–2) (x– 3) + 2x + 3

(2) 2006 (x–1) (x–2) (x– 3) + 2x + 1

(2) 2006 (x–1) (x–2) (x– 3) + 2x + 1

(3) 2006 (x–1) (x–2) (x– 3) + 2x – 1

(3) 2006 (x–1) (x–2) (x– 3) + 2x – 1

(4) 2006 (x–2) (x–3) (x– 1) –( 2x – 3)

(4) 2006 (x–2) (x–3) (x– 1) –( 2x – 3) 17/25


If the difference between the roots of the equa-

71 .

rc p dk eku gks xk -

tion x2 + px + 8 = 0 is 2, then p =

72 .

(1) ±2

(2) ±4

(1) ±2

(2) ±4

(3) ±6

(4) ±8

(3) ±6

(4) ±8

Let

a and b be

the roots of the equation

¹ 0, then the roots equation (x–a)(x– b ) + c = 0 a re (x–a)(x–b) = c, c

73 .

(1) a, c

(2) b, c

(3) a, b

(4) a+c, b+c

72 .

of the

p is a prime number and (p 2 + 3) is also a prime

73 .

number. The number of numbers that p can

(1) a, c

(2) b, c

(3) a, b

(4) a+c, b+c

;fn p rFkk (p2 + 3) vHkkT  la  k,¡ gks rks p ds laHko ekuks a dh la  k gks ldrh gS (2) 2

(1) 3

(2) 2

(3) 1

(4) can't say

(4) dg

ugha ldrs ;fn f(x) = cos2x + sec2 x, rc bldk eku lnS o gksxk (3) 1

If f(x) = cos 2x + sec2 x, its value always is

74 .

(1) f(x) < 1

(1) f(x) < 1

(2) f(x) = 1

(2) f(x) = 1

(3) 2 > f(x) > 1

(3) 2 > f(x) > 1

(4) f(x) 75 .

;fn a o b lehdj.k (x–a)(x–b) = c, c ¹ 0 ds ewy gS rks lehdj.k (x–a)(x–b) + c = 0 ds ewy gks xs -

(1) 3

assume is

74 .

;fn lehdj.k x2 + px + 8 = 0 ds ew yks a dk vUrj 2 gS

³

2

(4) f(x)

In the given figure, P and Q are the mid-points of AC and AB. Also PG = GR and HQ = HR. What is the ratio of area of

DABC

DPQR to

area of

75 .

³

2

fn  x  fp  esa AC rFkk AB ds e  fcUnq Øe'k  P rFkk Q gS rFkk PG = GR ,oa HQ = HR gSA f=Hkq t PQR rFkk f=Hkqt ABC ds  kS =Qyksa dk vuqikr gS ?

? C C G

R

G

R P

P

H H A

A

(1)

(3)

18/25

1 2 3 5

Q

Q

B

B

(2)

2 3

(4) None of these

(1)

(3)

1 2 3 5

(2)

2 3

(4) bues a ls

dksb Z ugha


In the adjoining figure O is the centre of the

76 .

circle with radius r. AB, CD and EF are the diameters of the circle.

ÐOAF = ÐOCB = 60º.

fn  x  fp  esa o`Ùk dk ds Unz O rFkk f=T;k r gSA AB, CD rFkk EF o`Ùk ds O;kl gS  oa ÐOAF = ÐOCB = 60º gS rks Nk;kafdr Hkkx dk  ks =Qy Kkr dhft  ?

What is the area of the shaded region ? D

D

A A

60º

B

O

60º

F

æ 3 3ö (1) 2 çç p - 2 ÷÷ è ø (3) 3

60º

B

O

60º

F

C

C

r2

æ 3 3ö (2) 2 çç p - 4 ÷÷ è ø

r2

r2

E

E

r2

(1) 2

æ 3 3ö çç p ÷÷ 2 è ø

æ 3 3ö (2) 2 çç p - 4 ÷÷ è ø r2

æ 2 3ö (3) 3 çç p - 3 ÷÷ è ø r2

æ 2 3ö çç p ÷ 3 ÷ø è

(4) data insufficient

(


77

(4) vkadM+ as 78

)

fn;s x;s fp  esa  Hkqtk BC dk e  fcUnq D gS rFkk ;fn BC = a, AC = b, AB=c, ED= x, AD = p rFkk AE = h gSA

In the given figure, D is the midpoint of side BC and If BC = a, AC = b, AB=c, ED= x, AD = p and AE = h.

A

A

b

b c

h

77 .

If b - p - ax = 2

2

(1) 2 78 .

2

(1) p

a 2

D

77 .

(3) 8

(4) 16

a2 is equal to 4

2

p2 (3) 2

(2) 2p

78 .

(4) None of these

80 .

Value of a is :

79 .

(1) 1

(2) –1

(3) ± 1

(4) None of these

For the above quadratic equation :

a2 k

2

D

2

a2 4

C

(3) 8

(4) 16

dk eku gS 2

(1) p

(2) 2p

p2 (3) 2

(4) buesa

79

80

ls dks bZ ugha

)

ekuk  d f  kkr lehdj.k x2 + 3ax + 2a2 = 0 gS  fn lehdj.k ds ewy a rFkk b gS rFkk a2 + b2 = 5 fn;k x;k gSA a dk eku gS : (1) 1 (3) ± 1

80 .

a 2

gks rks k dk eku gS -

(2) 4

c + ax –

(

Let us consider a quadratic equation 2 2 x + 3ax + 2a = 0. If the equation has roots a, b and it is given that a2 + b2 = 5

x

;fn b - p - ax = 2

2

2

p

E

(1) 2


79 .

h

B

C

a2 then k is k

(2) 4

c + ax –

c

p x

E

B

vi;kZIr

(2) –1 (4) buesa

ls dks bZ ugha

fn;s x;s lehdj.k ds fy  :

(1) D > 0

(2) D < 0

(1) D > 0

(2) D < 0

(3) D = 0

(4) None of these

(3) D = 0

(4) buesa

ls dks bZ ugha 19/25

Sample question for ASAT : Nurture Course SECTION-D : BIOLOGY This section contains 20 multiple choice questions. Each question has four choices (1), (2), (3) and (4) out of which ONLY ONE is correct.

a 20 bl  k.M se 81 .

gSA izR;s d iz'u esa pkj fodYi (1), (2), (3) vkS j (4) gS a ftues a ls

Among mammals, which one plays a

81 .

significant role in the digestion of milk proteins? (1) Pepsin (2) Rennin (3) Trypsin (4) Amylase 82 .

Match Column - I with Column - II and select the correct option. (A) Plantae

1. Archaebacteria

(B) Fungi

2. Euglenoids

(C) Protista

3. Phycomycetes

(D) Monera

4. Bryophyta

82 .

Lru/kkfj;ks es a nq X/k iz ksVhu ds ikpu es a dkS ulk egRoiw.kZ Hkwfedk fuHkkrk gS ? (1) isfIlu (2) jsuhu (3) fVªfIlu (4) ,ekbyst LrEHk -I dks LrEHk -II ls feyku dhft,A vkS j lgh mÙkj dk p;u djs aA (A) ikni 1. vkdhZc DVhfj;k S (B) dod 2. ;wXyhuksbM~l (C) iz fVLVk 3. Qkbdks ekblhVht ks (D) eks us jk 4. czk;ksQkbVk (1) A - 4, B - 3, C - 2, D - 1

(1) A - 4, B - 3, C - 2, D - 1 (2) A - 1, B - 2, C - 3, D - 4

(2) A - 1, B - 2, C - 3, D - 4 (3) A - 3, B - 4, C - 2, D - 1 (4) A - 4, B - 2, C - 3, D - 1

(3) A - 3, B - 4, C - 2, D - 1 (4) A - 4, B - 2, C - 3, D - 1 83 .

The term ‘water-pollution’ can be defined in several ways. Which of the following statements does not give the correct definition ? (1) The addition of undesirable substances in water bodies. (2) The removal of desirable substances from water bodies. (3) A change in pressure of the water bodies. (4) A change in temperature of the water bodies.

83 .

84 .

Identify the missing labels in the diagram

84 .

below.

ty&iznw"k.k dks fofHkék rjhds ls ifjHkkf"kr dj ldrs gSA fuEu es a ls dkS ulk dFku ty iznw"k.k dks lgh ifjHkkf"kr ugha djrk ? (1) vuqi;qDr inkFkks  dk ty lewg esa feykuk (2) ty lewg ls okafNr inkFkks  dks gVkuk (3) ty lewg ds nkc es a ifjorZu gksukA (4) ty lewg ds rkieku es a ifjorZu gks ukA uhps fn  x  fp  es a  kkyh txg ij lgh mÙkj dks igpkfu,\ 1

1 C ell divisions

Cell divisions Diploid cells (2n) Reproductive cells develop

4

Male gamete Female gamete (sperm) (egg) Cell divisions

2

Cell divisions

3 Natur e ga metoph yte 20/25

lgh gSA

C ell divisions

C ell divisions Diploid cells (2n) Reproductive cells develop

4

Male gamete Female gamete (sperm) (egg) Cell divisions

2

Cell divisions

3 Natur e ga metop hyte

Sample question for ASAT : Nurture Course (1) 1-v/kZlw=h

(1) 1-meiosis forms spores; 2-zygote forms; 3-diploid; 4-sporophyte (2) 1-sporophyte; 2-meiosis forms spores; 3-haploid; 4-zygote forms (3) 1-sporophyte; 2-meiosis forms spores; 3-diploid; 4-zygote forms (4) 1-zygote forms; 2-sporophyte; 3-diploid; 4-meiosis forms spores 85 .

The diagram below shows part of the carbon

85 .

foHkktu ls chtk.kq ; 2- ;qX eut cuuk ; 3- f}xqf.kr ; 4- fctk.kqn~fHkn (2) 1- fotk.kq n~ fHkn ; 2- v/kZ l w = h foHkktu ls chtk.kq ; 3-vxqf.kr ; 4- ;qXeut cuuk (3) 1- fctk.kq n~ fHkn~ ; 2- v/kZ l w = h foHkktu ls chtk.kq ; 3- f}xqf.kr ; 4- ;qXeut cuuk (4) 1- ;qXeut cuuk ; 2- fc tk.kq n~ fHkn ; 3- f} xqf .kr ; 4-v/kZlw=h foHkktu ls chtk.kq cuukA uhps fn;k x;k fp  dkcZu pØ dks iznf'kZr djrk gS :-

cycle. Atmospheric CO 2

Atmospheric CO 2

Organic compounds

Organic compounds

Carbon compounds in soil

Carbon compounds in soil

Fossil fuels Fossil fuels

If many trees are removed from a forest by logging, what is the most immediate effect on the carbon cycle in that forest? (1) Increased rates of decomposition (2) Decreased use of atmospheric CO 2 (3) Decreased combustion of fossil fuels (4) Increased production of organic compounds 86 .

The diagram below shows the locations of the pituitary gland and the kidneys in the human

86 .

;fn dVkbZ djus ls tax y ds cgqr ls o`{kksa dks gVk fn;k tkrk gS rks ml taxy es a dkcZu pØ ij gks us okyk rqjUr izHkko D;k gks xk ?  tkukA (1) vi?kVu dh nj c  CO2 dk mi;ksx de gks tk,xkA (2) okrkoj.kh  b  ku dk ngu de gks tk,xkA (3) thok'eh  tk,xkA (4) dkcZfud inkFkks  dk mRiknu c uhps fn  ekuo 'kjhj ds fp  es a ih;w"k xzfUFk  oa o`Dd dh fLFkfr dks n'kkZ;k x;k gSA

body. Pituitary gland

Kidney

Pituitary gland

Kidney

21/25

Sample question for ASAT : Nurture Course ih;w"k xzfUFk ls  d inkFkZ L=kfor gks rk gS tks jDr izokg ls gksrk gqv k o`Dd dh y  dks f'kdk dks vf/kd ikuhvo'kks f"kr djus ds fy  lw puk ns rk gSA L=kfor inkFkZ fuEu es a ls mnkgj.k gS fdldk --------- ?

The pituitary gland can release a substance into the bloodstream that signals target cells in the kidneys to reabsorb more water. The released substance is an example of (1) An enzyme

(2) A hormone

(3) A neurotransmitter (4) A vitamin 87 .

88 .

During which stage of the cell cycle does the cell duplicate its DNA?

(1) M stage

(2) G 1 stage

(3) S stage

(4) G 2 stage

Predict what will happen as an impulse travels

87 .

(1) ,d  Utkbe

(2) ,d

gkWeksZu

(3) ,d

(4) ,d

foVkehu

U;wj Vª ks kWlehVj

dks f'kdk pØ dh fdl voLFkk es a dksf'kdk vius DNA dk izfrÏrhdj.k djrh gS ?

(2) G1 voLFkk voLFkk (3) S voLFkk (4) G2 voLFkk uhps fn  x  fp  es a lks fp  D;k gks xk tc  d vkos x  DlkWu (1) M

88 .

ls gks rk gqvk xqtjsxk ?

along the axon in the diagram below. Resting potential

Inside cell

Outside cell

Resting potential

Inside cell

[Na ] [K ]

Outside cell

[Na ] [K ]

[Na ] [K ]

[Na ] [K ]

(1) More potassium will move into the cell.

vf/kd ikS Vs f'k;e dksf'kdk ds vUnj tk,xkA  e dksf'kdk ds vUnj tk,xkA (2) vf/kd lksfM (1)

(2) More sodium will move into the cell. (3) Both sodium and potassium will move out

oa (3) lksfM;e 

ikS Vs f'k;e dksf'kdk ds ckgj tk,xkA (4) lksfM;e dksf'kdk ds ckgj tk,xkA

of the cell. (4) Sodium will move out of the cell. 89 .

What is produced by the structure labelled A in the illustration?

89 .

lajpuk A dks fp  es a n'kkZ ;k x;k gSA bl la jpuk ls D;k mRiék gks rk gS ? A

A

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(1) Rhizoids

(2) Thallose leaves

(1) ewykxz

(3) Spores

(4) Rhizomes

(3) chtk.kq

FkS yl iÙkh (4) izdUn (2)


Which process is taking place in this diagram?

90 .

fn  x  fp  es a dkS ulh izf Ø;k gks jgh gS ?

Ribs Diaphragm

Ribs Diaphragm

(2) Exhalation; the diaphragm is relaxing. (3) Inhalation; the chest cavity is reduced. (4) Exhalation; the rib cage is expanding. 91 .

Two arteries and two veins are labelled in the

91 .

diagram.Which two are veins?

92 .

vUr  'olu ; Mk;ÝkWe ladqfpr gks jgk gSA (2) fu  'olu ; Mk;ÝkWe f'kfFky gks jgk gSA (3) vUr  'olu ; o{kh  xqgk dk de gksuk (4) fu  'olu ; ilyh fiatjk QS yuk  fp  es a nks  fn  x keuh;k¡ o nks f'kjk,s a n'kkZ;h xbZ gSA dkS ulh nks f'kjk,sa gS ? (1)

(1) Inhalation; the diaphragm is contracting.

(1) A and B

(2) B and C

(1) A ,oa B

(2) B ,oa C

(3) B and D

(4) C and D

(3) B ,oa D

(4) C ,oa D

Which reaction takes place in the stroma (2) of

92 .

fuEu es a ls dkS ulh fØ;k gfjr yod ds LVª ek ks esa gks rh gS ?

the chloroplast?

(1) Glycolysis

(1) XykbQksykbfll

(2) Light-dependent reaction

(2) izdk'k

(3) Light-independent reaction (4) Krebs cycle 93.

Arteries (1) Carry blood away from heart ,are thick walled and contain valve (2) Carry blood away from heart ,are thick walled and Lack valve (3) Carry blood towards heart ,are thin walled and contain valve (4) Carry blood towards heart ,are thin walled and lack valve 94 . Which of the following bacterial component is made up of DNA? (1) Ribosome (2) Plasmid (3) Lysosomes (4) Protein

93.

vk/kkfjr vfHkfØ;k (3) izdk'k&lora  vfHkfØ;k (4) Øs c pØ /keuh;ka  ls nwj eks Vh fHkfÙk o okYo okyh (1) jDr dks ân (2) jDr

dks ân  ls nwj eks Vh fHkfÙk o fcuk okYo okyh

(3) jDr

dks ân  dh rjQ  iryh fHkfÙk o okYo okyh

 dh (4) jDr dks ân 94 .

rjQ  iryh fHkfÙk o fcuk okYo okyh

fuEu esa ls dkSu lk thok.kqo h   kVd DNA dk cuk gks rk gS ? (1) jkbcksl e (2) IyktfeM ks ks (3) ykblks lks e (4) iz Vhu 23/25

Sample question for ASAT : Nurture Course (

Comprehension for (Q.No.95 to Q.No.97) the earth is used up by the plants in the process

 djrs igq ¡p rh gS ftldk mi;ks x ikS/ks izdk'k la'ys "k.k ds fy

energy of food. There is a continuous transfer

gS a vkS j Hkks tu ds fy  jklk;fud ÅtkZ ds  i es a la xzfgr djrs

of energy from one trophic level of organisms

gSA Hkks tu  kk  Jà[kyk es a bl ÅtkZ dk  d iks"k.k Lrj ls

to the next in a food chain (producer to

nwl jh iks "k.k Lrj rd LFkk ukUrj.k gk sr k gS

herbivore to carnivore and so on). At each trophic level, some of the energy is utilized by

( mRiknd ® 'kkdkgkjh ® ekalkgkjh  oa

the organisms for their metabolic activities like lost at each energy transfer in various tropic

fØ;k  tS ls 'olu o o` fð es a dke es a ys rs gSA ÅtkZ dk Lrj

levels. The amount of energy available gradually decreases. Only 10% of the energy

lrr~ de gksrk tkrk gSA tS ls&tS ls s vkxs ds iks"k.k Lrj dks

entering a particular trophic level of organisms

LFkkukUrfjr gksrh gSA dsoy ÅtkZ dk 10% Hkkx vkxs ds

is available for transfer to the next higher

iks "k.k Lrj rd igq¡p ikrh gS ÅtkZ dk izokg  d fn'kk es a gksrk gS D;ks afd Å"ek ds  i es a âkflr ÅtkZ  kk  Jà[kyk es a ikni }kjk izdk'k la'ys "k.k es a mi;ks x ugha dh tk ldrh gS

trophic level. The flow of energy is in single direction because the energy lost as heat from the living organisms of a food chain cannot be reused by plants in photosynthesis. T1

T2

T3

T4

T1

T5

1000 cal.

100 cal.

10 cal.

1cal.

1000 cal.

0.1 cal.

In the above food chain total amount of solar

T2

T3

T4

T5

?kkal ® dhV ® es a d ® lkai ® phy

Grass ®Insects®Frogs®Snakes ®Eagle

95 .

energy perceived on earth converted to food by producers is-

100 cal.

10 cal.

1cal.

(2) 10%

(1) 1%

(2) 10%

(3) 99%

(4) 90%

(3) 99%

(4) 90%

Total amount of energy available at Herbivore

96 .

'kkdkgkjh Lrj ij mifLFkr ÅtkZ dk dqy Hkkx tks vkxs ds iks"k.k Lrj ds fy  mifLFkr gS :

(1) 100 cal.

(2) 1000 cal.

(1) 100 cal.

(2) 1000 cal.

(3) 10 cal.

(4) 90 cal.

(3) 10 cal.

(4) 90 cal.

In the above food chain primary consumer and secondary carnivore is(respectively)-

97 .

0.1 cal.

mijksDr  kk  Jà[kyk es a lw;Z ÅtkZ dh fdruk % Hkkx i`Foh ij vk ikrh gS tks mRikndks  kjk  kk  inkFkZ es a cnyh tkrh gS -

(1) 1%

level for next trophic level is:

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Øe'k  ) iz R;sd

iks "k.k Lrj ij ml ÅtkZ dk dqN Hkkx  izk.kh  kjk mikip;h

respiration and growth. A part of the energy is

97 .

)

chemical

of photosynthesis and stored as

96 .

97

lw;Z izdk'k ÅtkZ dh dqy ÅtkZ dk 1% i`Foh lrg rd

About 1% of the total sun's energy reaching

95 .

95

 Ja [kyk  eka lkgkjh mijks Dr  kk ` es a iz kFkfed miHkks Drk vkS j f}rh Øe'k  gS -

(1) Insect and frog

(1) dhV

vkS j es  d

(2) Frog and Snake

(2) es  d

vkS j lkai

(3) Insect and Snake

(3) dhV

(4) None of the above

(4) mijks Dr

vkS j lkai es a ls dks bZ ugha

Sample question for ASAT : Nurture Course Comprehension for (Q.No.98 to Q.No.100) The eukaryotes include all the protists, plants, animals and fungi. In eukaryotic cells there is an extensive compartmentalization of cytoplasm through the presence of membrane bound organelles. Eukaryotic cells possess an organised nucleus with a nuclear envelope. In addition, eukaryotic cells have a variety of complex locomotory and cytoskeletal structures. Their genetic material is organised into chromosomes. All eukaryotic cells are not identical. Plant and animal cells are different as the former possess cell walls, plastids and a large central vacuole which are absent in animal cells. On the other hand, animal cells have centrioles which are absent in plant cells. 98 . Membrane bound cell organelles are found in(1) Bacteria (2) fungi (3) Blue green algae (4) Virus 99 . Presence of plastids are characterstic feature of(1) Plants (2) animals (3) Fungi (4) Bacteria 100. Nucleus is peripheral in plant cell due to presence of(1) Central large vacuole (2) Mitochondria (3) Plasma membrane (4) Ribosome

(

98 .

99 .

100.

98

100

)

;wd fjvks S V~ l es a lHkh iz ks fVLV  ikni  tUrq rFkk dod lfEefyr gSA  wd fjvks S fVd dks f'kdkvksa es a f>Yyh vkLrkfjr dksf'kdka xksa dh mifLFkfr ls dks f'kdk æO  dk foLr`r foHkktu gksrk gSA ;wd fj;ks S fVd dks f'kdkvks a es a ds Uædh  vkoj.k ds lkFk  d la xfBr ds Uæd gksrk gSA blds vykok  wd fj;ks S fVd dks f'kdkvks es a tfVy pkyd rFkk dks f'kdk fiatj lajpukvks a dh fofHkUu fdLesa gks rh gS aA vkuqokaf'kd inkFkZ xq.klq=ksa es a O;ofLFkr gks rk gSA lHkh  wd fj;ks S fVd dksf'kdk,¡ leku ugha gSA ikni rFkk tUrq dks f'kdk,¡ fHkUu gS a D;ks a fd ikniks a es a dks f'kdk fHkfÙk  yod rFkk  d cM+h dsUædh  fjfDrdk mifLFkr gks rh gS tks fd tUrq dks f'kdkvksa es a s vuqifLFkr gks rs gSA tcfd tUrq dks f'kdk esa rkjdds Uæ gks rk gS tks ikni dks f'kdkvks a es a vuqifLFkr gksrk gSA f>Yyh vkLrkfjr dksf'kdkax feyrs gS a(1) thok.kq (2) dod (3) uhy&gfjr 'kS oky (4) fo"kk.kq yodks a dk ik;k tkuk fdldk vfHkyk{kf.kd xq.k gS(1) ikni (2) tUrq (3) dod (4) thok.kq ikni dksf'kdk es a dsUæd fdldh mifLFkfr ds dkj.k ifjèkh  gks rk gS (1) cM+h ds Uædh  fjfDrdk (2) lw=df.kdk (3) IykTek f>Yyh (4) jkbcksl e ks

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Allen Asat 2015 Paper

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