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EA102
American Concrete Association (ACI) Absolute Volume Method of Concrete Mix Design
"#$ %$& '()$*+ Mix Component Properties: P roperties: Type: 10 Specific Gravity: 3.155
Cement
Coarse Aggregate
Nominal Max imum Particle Size: 20 mm
SSD Bulk Specific Grav it y: 2.610 2.610 % Absorpt Absor pt ion Capacit y: 3.10% 10% Dr y-Rodded Densit Dens it y: 1.570 Mg/m Mg/m
Fine Aggregate
SSD Bulk Specific Specific Gravi t y: 2.700 % Abso rp tion ti on Capaci Cap acitt y: 1.10% 10% Finene Fine ness ss Modul us: 3.00
Desired Mix Properties: A 200 kg batch on air-entrained concrete with a slump in the 30 to 50 mm range and a water/ cement cemen t ratio rat io of 0.45 45 is required. requ ired.
SOLUTION: 1. Determine densities of all materials to be used: Specific Material Gravity Water 1.0 Cement 3.155 SSD Fine Aggregate 2.700 SSD Coarse Aggregate 2.610 Dry-Rodded Coarse Aggregate
ρ =
G x ρw x ρw =
Density (kg/m3)
x 1000 = x 1000 = x 1000 = x 1000 =
1000 3155 2700 1570
2.
Mass of mixing water in 1 m 3 of mix = 168 kg = 0.168 m
3.
!"#$%& "( )*+ in 1 m 3 of mix is 5.00% of 1 m 3 or ,-,. % / (Table 4c for non-air-entrained, non-air-entrained, Nominal Maximum size = 10mm)
1
2610
3
4. If
w w 0.45, then c c 0.5
The volume of cement
228 kg 456 kg The mass of cement required = 456 kg 0.5 456 kg The volume of cement required = 0.145 m3 3 3155 kg/m
5. Volume of dry-rodded coarse aggregate = 0.47 m3 (Table 3 for Nominal Maximum size = 10 mm and fineness modulus of 2.70)
6. SSD mass of coarse aggregate = 0.47 m3 x 1530 kg/m3 = 719 kg SSD volume of coarse aggregate
719 kg 2660 kg/m 3
= 0.270 m3
7. Sum of known volumes = (0.228 + 0.030 + 0.145 + 0.270) m 3 = 0.673 m3 SSD volume of fine aggregate = 1 – 0.673 m 3 = 0.327 m3 SSD mass of fine aggregate = 0.327 m3 x 2700 kg/m3 = 883 kg 8. Total mass of 1 m3 of mix = (228 + 456 + 719 + 883) kg = 2286 kg/m3 The proportioning factor
2286 kg 30 kg
= 76.2
Each mass for the 1 m 3 of mix is then divided by this factor: Materials Cement Water Coarse Aggregate Fine Aggregate Air Totals
