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GROUP 1
Andrada, Filmar T. Dulliyao, Van Vesper J. Cauilan, Kaicee Lapuebla, Jeremy C. Necesito, Miko Paul B.
2.5 Eadie (1942) measured the initial reaction rate of hydrolysis of acetylcholme (substrate) by dog serum (source of enzyme) and obtained the following data: Substrate Concentration (mol/L) Initial Reaction Rate (mol/L) 0.0032 0.111 0.0049 0.148 0.0062 0.143 0.0080 0.166 0.0095 0.200 Evaluate the Michaelis-Menten kinetic parameters by employing a) b) c) d)
The Langmuir plot; The Lineweaver-Burk plot; The Eadie-Hofstee plot; and Non-linear regression procedure
Solution: a) Employing the Langmuir plot x (Cs) 0.0032 0.0049 0.0062 0.008 0.0095
y (r) 0.028829 0.033108 0.043357 0.048193 0.0475
Langmuir Plot 0.06
0.04 r /
s
C
r max
1
y = 3.3133x + 0.0191 R² = 0.8837
0.05
0.03 0.02
slope 0.01
K m
y
r max max K m
intercept r max 0.301814 0.005765
0 0
0.002
0.004
0.006
Cs
1
0.008
0.01
b) Lineweaver-Burk Plot x (1/Cs) 312.5 204.0816 161.2903
y (1/r) 9.009009 6.756757 6.993007
10
125 105.2632
6.024096 5
7
Lineweaver-Burk Plot
6
K m
y
3
intercept
2 1
slope r max
r max K m
5 4
1
R² = 0.9146
8
r / 1
r max
y = 0.0172x + 3.6342
9
0 0
0.275164 0.004733
50
100
150
200
250
300
350
1/Cs
c) Eadie-Hofstee Plot x (r/Cs) 34.6875 30.20408 23.06452 20.75 21.05263
2.19 The initial rate of reaction for the enzyme cleavage of deoxyguanosine triphosphate was measured as a function of initial substrate concentration as follows: Substrate Concentration (μmol/L) Initial Reaction Rate (μmol/L) 6.7 0.30 3.5 0.25 1.7 0.16 a) Calculate the Michaelis-Menten constants of the above reaction.
Solution: In finding the Michaelis-Menten constants, we first determine the highest coefficient of R by plotting the three different graphs namely Langmuir, Lineweaver-Burk, and Eadie-Hofstee plot. Cs 6.7 3.5 1.7
Among the above graphs, the Langmuir plot displayed the best fit of our data. Using the Langmuir plot to solve the problem, the equation below shall be used: r max
K m
y
r max K m
1
slope
intercept r max 0.42155 2.631692
The Michaelis-Menten constant (K m) is equal to 2.631692.