F\u00ed s i ca
EDUCACIONAL
\u00d3 p ti
ESPELHOS PLANOS EXERC\u00cdCIOS RESOLVIDOS
01. Construa a imagem do ponto P, conjugada pelo espelho E nos seguintes casos: a)
Resolu\u00e7\u00e3o :
P
P
(E) (E)
b)
P'
Resolu\u00e7\u00e3o :
P
P (E)
(E) P'
c)
Resolu\u00e7\u00e3o :
(E)
P' P
(E) P
d)
P
(E)
Resolu\u00e7\u00e3o :
P
(E) P'
FISCOL1599-R
1
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F\u00cdS ICA
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02. Qual a conclus\u00e3o que podemos extrairResolu\u00e7\u00e3o observando a : resolu\u00e7\u00e3o do exerc\u00edcio d)?
Os espelhos planos conjugam imagens tamb\u00e9m para obje estejam frontais a ele.
03.Usando as leis da reflex\u00e3o, construa oResolu\u00e7\u00e3o: pincel de luz refletido pelo espelho nos seguintes casos: a)
a)
(E)
(E)
b)
b)
(E)
(E)
c)
c)
(E)
(E)
04.Classifique em ponto objeto ou ponto imagem, os v\u00e9rtices Resolu\u00e7\u00e3o: a) ponto objeto real (incidente) ponto imagem virtual (refletido) b) ponto objeto impr\u00f3prio (incidente) ponto imagem impr\u00f3prio (refletido)
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Resolu\u00e7\u00e3o: 05. Construa a imagem do objeto AB conjugada pelo espelho (E) nos seguintes casos:
a)
a)
A
A'
A
B
B
B'
b)
A
(E)
b)
A
B
B
A'
(E)
c)
B'
A A
B (E)
B
B'
d)
B
A
A'
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06. Observe as resoluções dos itens (c) e (d) doResolução: exercício anterior. O que podemos concluir?
Podemos concluir que se o espelho for horizontal, a imagem conjug
07.Construa a imagem do objeto dado, conjugada pelo espelho: Resolução: A
A
A'
C C'
C
B
B'
B
D
D'
D
(E)
Resolução: 08.(UF-GO) Diante de um espelho plano, um homem
Pela teoria
⇒
Alternativa D
⇒
Alternativa C
a) a mão direita escrevendo e as letras revertidas
e) nda 09.(FUVEST) Maria e Joana são gêmeas e têm a mesm a Resolução: Pela teoria
Maria
Joana 5m
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Resolução: 10. (CESGRANRIO)Sentado na cadeira da barbearia, um rapaz B 1
a) 0,5m
0,50m
A 4 4
2
44
0,5 m
3
1
B' 4
2
4 3
0,8 m
1 4444 2 4444 3
(0,5 + 0,8 ) m
0,80m
d = 0,8 + 0,8 + 0,5 = 2,1 m Alternativa E
Resolução: 11.(FEFASP) Um relógio visto através de espelho plano parece indicar 6 horas e 15 minutos. Qual a indicação real? imagem
a) 5h 45min
objeto
d) 12h 45min e) nda
5h45 min
⇒
Alternativa A
Resolução: 12.(FUVEST) Através do espelho (plano) retrovisor, um imagem
SORRIA SORRIA
Alternativa A
Pode-se concluir que a inscrição pintada naquele párachoque é: a) AI R R OS b) AI RROS c) SORRIA d) SO R RI A
objeto AI R R OS
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13. (FATEC) Antônio está de pé, fixo, diante de umResolução: espelho
A distância entre Antônio e sua imagem era 2 x 2,5 m e passou 2 x 1,5 m. Alternativa A
a) A distância de Antônio à sua imagem diminui de 2,0m b) A altura da imagem de Antônio aumenta c) A distância de Antônio à sua imagem diminui de 1,0m d) O ângulo visual da imagem de Antônio diminui e) nda
Resolução: 14.(ITA) Quando um homem se aproxima diretamente de um espelho plano com velocidade 1,2m/s, ele:
A velocidade relativa de aproximação entre o objeto e a imag 2 x 1,2 a) afasta-se de sua imagem com velocidade 1,2m /s m/s = 2,4 m/s.
b) aproxima-se de sua imagem com velocidade Alternativa C 1,2m/s c) aproxima-se de sua imagem com velocidade 2,4m/s d) mantém uma distância constante de sua imagem e) nda Resolução: 15.Dois espelhos planos formam entre si um ângulo de 30°. 360
N =
a) 2
α
360
− 1 = 30
− 1 = 12 − 1 = 11 imagens
Alternativa D
d) 11 e) 15 Resolução: 16.Um observador frontal a um espelho plano vê sua imagem 2 = 1m e A distância do observador ao espelho era passou a ser 3m.
Logo, a imagem está a 6 m do observador. Resolução: 17.O motorista de um automóvel que se encontra em 80
Vi = 2 . V c
⇒
Vc =2 = 40 km/h
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Resolução: 19. Dois espelhos planos que formam entre si um ângulo θ 360
N= 360
θ
20 .(FUVEST)A figura F, ao lado,
espelhos
θ
−1 ⇒
=5
b)
c)
θ
−1
360
⇒
θ = 5 = 72º
Resolução:
Pela teoria
a)
4=
360
⇒
Alternativa C
7
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Resolução: 21. (SANTA CASA) A figura que representa corretam ente a
Pela teoria
a) O
d) O
E
E
⇒
Alternativa D
I
I
b) O
E
c) O- I
I
e)
E
22.(UF-PR) Um espelho plano fornece, de um dado Resolução: objeto em Alternativa B
I
a) é real e divergente
O Resolução: 23.(CESGRANRIO) Um periscópio é formado por dois
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Ó PTICA
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Resolução: 24. Na figura abaixo, F e E são dois espelhos planos. A maior
d2 = 82 + 122 d = F
a) 4,0
d =
1,0 cm
208 =
64748
4 cm
P
6
4. 52
∴ ∴ d = 2 52
1,0 cm
e) 2 52
+ 1 44 64
P"
cm
Alternativa D
P
90° P'
E
25.(FUVEST) Tem-se um objeto O defronte a dois espelhos Resolução: a) d2 = 0,82 + 0,62 d2 = 1 d = 1m C
b)
A
O
O
C d 60 cm
A
80 cm C
B
a) Qual a distância entre o objeto e a imagem B? b) Desenhe o esquema com os espelhos, o objeto e as imagens. A 26.(UNIP) Os dois espelhos planos perpendiculares E e F da
B
B
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Resolução: 27. (PUC) ABC representa a seção normal do diedro formado A
A
M
a) 30°
M
T B
α
60º 30 + i
O M'
i
90 + i i 6
0
-i
60
T
x=? O
-i
M'
S
S
C
C
x é o ângulo externo ao triângulo MM'O, logo: x = 2i + 2 (60 − i) = 2i + 120 − 2i ∴ x = 120º Alternativa D Resolução: 28. (FUVEST) Nafigura, estão representados um ponto luminoso
P E
P E
P' 29. (MACK) Diante do espelho plano E, encontram-se o Resolução:
A B
A.
E
C
C D
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11
Resolução: 31. (CESCEM) Um objeto puntual está em frente a um espelho
o l h o objeto 144424443
144424443
20 cm
20 cm
a) 10cm 14444 4 244444
30 cm
∴ d = 30 + 20 = 50 cm
3
⇒
Alternativa E
32. (UFSCAR) Um homem aproxima-se de um espelho plano e Resolução:
a)
b)
d)
e)
c)
O tamanho da imagem é constante, independe da proximi homem em relação ao espelho. Alternativa D
33. (MACK)Umobservador de 1,70m de altura e cujos olhos se Resolução: 0,1 m
olhos
a) A altura mínima do espelho, bem como a altura onde ele
E
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Resolução: 34. (E.E. Juiz de Fora) A 1,5m de distância de um espelho plano
1,4 m
0,5 m
0
1,5 m
1,5 m
0
Por semelhança: 1, 4 h
3, 5
= 1, 5 ⇒ h = 0,6 m
35. Uma esfera é lançada do ponto A de um trilho lisoResolução: com
Comoo trilho é liso e a altura em C é a mesmaaltura que A, a bola ch
com relação à sua imagem: Alternativa A
E
v A
B
C
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13
37. Dois espelhos formam entre si um certo ângulo.Resolução: 360
N=
a) 45°
α
360
15 − 1 (II) − 1 (I) ⇒ N + 4 = α−
Substituindo (I) em (II), temos: 360
α
−1+4=
α−
360
360
α
360
−
α−
15
15 − 1 ⇒
α" = −30º (não convém) Alternativa A
Resolução: 38. (VUNESP) O olho de um observador está na posição Oe três
α
+3=
360
α−
15 − 1
+ 4 = 0 ⇒ 360(α − 15) − 360α + 4α (α − 15) = 0
−5400 + 4α2 − 60α = 0 α2 − 15α − 1350 = 0 α'= 45º
360
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ESPELHOS ESFÉRICOS 01. Complete os desenhos abaixo, desenhando os : Resolução correspondentes raios refletidos pelos espelhos. a)
a)
C
F
V
V
b)
b)
C
F
V
F
V
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Resolução : as 02. Construa as imagens conjugadas pelos espelhos e dê suas características.
a)
A
a) imagem:
A
•
real B
B
b)
C
F
C
B' F
V
A'
V
b) imagem:
A
15
•
A
real
B C
B' = BC
V
F
F
A'
03. Complete os desenhos abaixo segundo as propriedades dos espelhos esféricos: a)
b)
c)
V
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04. Construa as imagens conjugadas pelos espelhos e dê as suas características. a)
A
b)
CB F
V
A B C F
c) V
C
d)
A
A
F B V
B
V
C
F
Resolução:
a)
b) A B'
C B
A F
V
e.p. C
B
F
V
e.p.
A'
natureza: real tamanho: maior que o objeto orientação: invertida
Neste caso a imagem será imprópria (o pincel que sai espelho é cilíndrico).
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17
Resolução : 06. Um objeto luminoso encontra-se a 10cm de um espelho côncavo de raio de curvatura igual a 40cm. Determine:
a) a abscissa da imagem b) as características da imagem
a) objeto luminoso = objeto real ⇒ p = +10cm f
R
=2 ⇒
f
20cm
=+
1 = 1 −1 1 1 1 1= 1 + 1 ⇒ = + f p p' 20 10 p'⇒ p' 20 10 1 = 1− 2⇒ 1 = −1 = 20cm p' 20 p' 20 b) p' < 0 ⇒ imagem virtual | p' | > p ⇒ imagem > objeto.
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Resolução: 08. Um objeto luminoso é colocado a 30cm de um espelho
a) O raio de curvatura é o dobro da distância focal. − −30 cm Logo, f =
a) a abscissa do foco b) a posição da imagem c) a aumento linear transversal
1
1
1
b) −30 = 30 + p p
c ) A =−
15
= 30 = 0,5
: 09. Um objeto real está situado a 60cm do vértice deResolução um espelho côncavo de foco 40cm e sobre o eixo principal. Determine: 1
p' =− − 15 cm
⇒
1
1
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19
Resolução 12. (MACK) Osesquemas abaixo representam a reflexão de:um
O raio luminoso que incide passando pelo centro de curvatu sobre si mesmo.
a)
d) V
b)
F
Alternativa E
V
C
e)
F
C
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20
FÍS ICA
Ó PTICA EDUCACIONAL
Resolução: 15. (PUC) Espelhos convexos são freqüentemente utilizados
I → correta II → errada, pois é virtual I. A área refletida para o olho, por um espelho III circular → correta IV → errada, pois a relação entre p' e f é linear. convexo, é maior que a refletida por um espelho
plano de igual diâmetro na mesmaposição. A II. A imagem é formada atrás do espelho, sendo,Alternativa portanto, real. III. A imagem é menor que o objeto e não é invertida. IV. A distância entre a imagem e o espelho é limitada, a) somente I e III
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Ó PTICA
FÍS ICA
EDUCACIONAL
18. (MACK) Um objeto real é colocado diante de umResolução espelho: 1
1
=
1
+ 2p ⇒
a) o objeto se encontra entre o foco principal e o centro de ∴ 2p = 3f ⇒ curvatura b) o objeto se encontra entre o vértice e o foco principal c) o objeto se encontra no foco principal d) a imagem se encontra entre o foco principalAlternativa e o centro A de curvatura e) a imagem se encontra entre o vértice e o foco principal 19. (UFU-MG) Em um experiência de Óptica, um estudante
p =
+
2p
3f 2
1
=
1
3
⇒
2p
=
21
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22
FÍS ICA
Ó PTICA EDUCACIONAL
22. (FATEC) No espelho convexo da figura, podemResolução os afirm:ar que há correspondência entre objeto e imagem:
Observando a figura, vemos que os pares de objeto e imagem s
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Ó PTICA
FÍS ICA
EDUCACIONAL
Resolução : 25. (FCC) Umespelho esférico fornece umaimagem real de um
− p' A = −3 = ⇒
p' = 3p
23
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24
FÍS ICA
Ó PTICA EDUCACIONAL