51150059-PERENCANAAN-JEMBATAN-RANGKA-REVISI-ANNISA-ANDI-NUR-BAITI-2SIPIL1PAGI.doc

TUGAS BESAR KONSTRUKSI BAJA PERENCANAAN JEMBATAN RANGKA BAJA ANDI ASWAR, ANNISA HAPSARI, NUR BAITI HASANAH – 2SIPIL 1 PAGI

TUGAS BESAR KONSTRUKSI BAJA PERENCANAAN JEMBATAN RANGKA BAJA

Andi Aswar Annisa Hapsari Nur Baiti Hasanah 2 Sipil 1 Pagi Pengajar : Ibu Anis Rosyidah

POI!"#NI# N"$"RI %A#AR!A


2&1& PERENCANAAN JEMBATAN RANGKA BAJA



SPESIFIKASI JEMBATAN :

b (lebar jembatan)

=7m

a (lebar trotoar)

= 0,5 m

b-2a (lebar jalan)

=6m

h (t (tinggi jem jemb batan)

=3m

λ(panjang segmen) segmen)

=4m

L (pa (panj njan ang g ben benta tang ng)) = 24 m Tebal trotoar

=0,2m


!t! baja

= "# 37

%$= 240 &a

$!

= 370 &a

'

= 200000 &a

"# spal = 22 *+m3 "# "eton =24 *+m3 Tebal aspal =0,05 m Tebal pererasan = 0,2 m



PERENCANAAN DIAFRAGMA

"'"+ T. / "eban pererasan "eban spal o

= 4  0,2  24 = 1,2 +m3 = 4  0,05  22 = 4,4 +m3  3

 = 23,6 +m

7m 

ma = 1    L2

"

! = 1,4  ma

= 1  23,6  4

= 1,4  144,55

= 144,55 +m

= 202,37 +m

 =26 *+




PERHITUNGAN GAYA-GAYA BATANG

o

e 8erajat *eti9atent!an :tr!t!r

sin ;1 = 0,6<

21 = (212)  3

>os ;1 = 0,< ?* @

#!mlah easi T!mp!an = 2

;2

>os ;2 = 0,6<

= 1 enghit!ng easi T!mp!an

A" = 0 a  24  0,5&  24  &1  20  &2  16  &3  12  &4    &5  4 = 0 24  12&  20&  16&  12&  &  4& = 0 B = 3& *+ A = 0 -b  24  0,5&  24  &5  20  &4  16  &3  12  &2    &1  4 = 0 -24b  12&  20&  16&  12&  &  4& = 0 "B = 3& *+



= 53<

sin ;2 = 0,<

3 ( :tr!t!r Tertent! )

o

= 37<

m = 2#  3

21 = 21 o

;1

PERHITUNGAN GAYA-GAYA BATANG (METODE TITIK BUHUL)


BUHUL B

:20sin;1

20

:2>os;1

&2

21 "

CB = 0

CD = 0

"  :20sin;1 - 0,5& = 0

-:21  :20>os;1 = 0

3&  0,5&  :20  0,6 = 0

:21 = - (-4,167  0,)

2,5&0,6 = :20

S21 = 3,33P KN

S2! = -,1"#P KN

BUHUL G

1 1

21

CB = 0

CD = 0

S1$ = P KN

:21 = :1 S1% = 3,33P KN

P

BUHUL L


:17>os;1

16

:20>os;1

17

20 1 :17sin;1

:20sin;1

CB = 0

CD = 0

-:1  :17sin;1  :20sin;1 = 0

:20>os;1  :16  2& = 0

-&  0,6:17  2,5& = 0

3,334&  :16  2& = 0

1,5& = 0,6:17

S1" = 1,33P KN

S1# = 2,&P KN

BUHUL F

:17sin;1 15 17


14

:17>os;1 1 &

CB = 0

CD = 0

:15  :17sin;1  & = 0

:1  :17>os;1  :14 = 0

:15 = &  1,5

3,334  2  :14 = 0

S1& = !,&P KN

S1 = 1,33P KN

BUHUL K

12 :13>os;1

16 13

15

:13sin;1 CB = 0

CD = 0

-:15  :13sin;1 = 0

:16  :12  :13>os;1 = 0

0,5& = :13sin;1

1,334  :12  0,666 = 0

S13 = !,%33P KN

S12 = !,""%P KN

BUHUL E

:13sin;1 :sin;1 10 

13


:>os;1

:13>os;1

10

14 &

CB = 0

CD = 0

:11  :sin;1  :13sin;1  & = 0 0

:14  :13>os;  :10  :>os;1 =

0,6:  0,5&  & = 0

1,334&  0,66&  :10  0,666& = 0

: = 0,5&0,6

S1! = 1,33P KN

S$ = !,%33P KN

BUHUL J



12

CB = 0

CD = 0

- :11 = 0

:12 = :

S11 = !

S% = !,""%P KN

11

BUHUL I

4

 10

:sin;1



:>os;1


CB = 0

CD = 0

-:7  :sin;1 = 0

:  :>os;1  :4 = 0

:7 = -0,33  0,6

0,66  0,666&  :4 = 0

S# = -!,&P KN

S = 1,33P KN

BUHUL D ''*

:5sin;1

5

7 6

10

:5>os;1 & CB = 0

CD = 0

:7  :5sin;1  & = 0

:10  :6  :5>os;1 = 0

-0,5&  0,6:5  & = 0

1,334  :6  2 = 0

-1,5& = -0,6:5

S" = -!,"""P KN

S& = 2,&P KN BUHUL C

3

2

6

& CB = 0

CD = 0


:6 = :2

S3 = P KN

S2 = -!,"""P KN

BUHUL H

:1>os;1

4 1

3

:5>os;1

5 :5sin;1

:1sin;1

CB = 0

CD = 0

-:3  :5sin;1  :1sin;1 = 0

:4  :5>os;1  :1>os;1 = 0

-&  1,5  0,6:1 = 0

:4 = (-2,50,)  (-4,1670,)

-2,5& = 0,6:1

:4 = -2  3,334

S1 = -,1"#P KN

S = 1,33P KN

BUHUL A

CB = 0 :1sin;1

  :1sin;1  0,5& = 0

&

1

3&  0,6:1  0,5& = 0 2,5& = -0,6:1

2

:1>os;1

S1 = -,1"#P KN

CD = 0 :2 = -:1>os;1


S2 = 3,33P KN

TABEL HASIL PERHITUNGAN GAYA-GAYA BATANG



N+ B.*'

G/ B.*'

K0.0*'*

1

-4,1617&

Tean

2

3,334&

Tari

3

&

Tari



1,334&

Tari

&

2,5&

Tari

"

-0,666&

Tean


#

-0,5&

Tean

%

0,66&

Tari

$

0,33&

Tari

1!

1,334&

Tari

11

0

"atang *estabilan

12

0,66&

Tari

13

0,33&

Tari

1

1,334&

Tari

1&

-0,5&

Tean

1"

1,334&

Tari

1#

2,5&

Tari

1%

3,334&

Tari

1$

&

Tari

2!

-4,167&

Tean

21

3,334&

Tari

PERHITUNGAN BEBAN-BEBAN YANG BEKERJA

&8L / " mati  9ia$ragma =26  11 " trotoar = 24  02 05  4  13 T+.

&LL/ b pejalan = 5  05  4  2 b laj!r =   7  4  2  05 b gen air = 05  56  4  1  05 .+.

"eban berjalan / b garis(*'L)

=06 n =124 n = 1!33 N

=20 n = 252 n = 56 n =2##" N

= 4  7  14  2  05 =%!2 N


ANALISA GAYA BATANG

TABEL BEBAN MATI DAN HIDUP

Ga!a Batang

No.Batang

Niai

B1

&'.1(2

&1,1))

&'*+.+++-

B2

*.**'

2(

*''.)*))(

B*

1.+++

2-

1+*.*'

B'

1.**'

*+

1*.-)))(

B)

2.)++

('

2)-.*)

B(

&+.(((

&1-)

&(-.-2'''

B

&+.)++

&1*

&)1.(

B-

+.((-

1-)

(.+*112

B

+.-**

2*1

-(.+-222

B1+

1.**'

*+

1*.-)))(

B11

+.+++

+

+

B. Ma"

B.Hi#

%$ TUGAS BESAR KONSTRUKSI BAJA PERENCANAAN JEMBATAN RANGKA BAJA ANDI ASWAR, ANNISA HAPSARI, NUR BAITI HASANAH – 2SIPIL 1 PAGI

TABEL GAYA BATANG AKIBAT BEBAN BERJALAN

Ga!a /atang 0n

No.Batang

Niai

B1

&1.*-

&(((.'-

B2

1.111

)**.))+22

B*

1.+++

'-+.2

B'

+.+++

+

B)

2.222

1+(.1++''

B(

1.111

)**.)+22

B

+.)++

2'+.1

B-

2.+++

(+.'

B

+.-**

'++.++((

B1+

1.-

-)*.()(

B11

+.+++

+

B3/an B345aan

TABEL PENTABULASIAN BEBAN MATI, B. HIDUP & B. BERJALAN

N6 BATANG

B. MATI

B. HIDUP

T6TAL

B. BJALAN

TEKAN

TARIK

B1

&1,1))

&'*+.+

&(((.)

B2

2(

*''.)'

)**.))

1,-+*.(+

B*

2-

1+*.*'

'-+.2+

-(1.1'

B'

*+

1*.-(

+.++

)+-.1

B)

('

2)-.*)

1,+(.1+

2,+1.')

B(

&1-)

&(-.-2

)**.)+

&2)*.1

)**.)+

B

&1*

&)1.(

2'+.1+

&1+.'

2'+.1+

B-

1-)

(.+*

(+.'+

1,21'.-

B

2*1

-(.+-

'++.+1

1.**

B1+

*+

1*.-(

-)*.+

1,*(1.-

B11

+

+.++

+.++

+.++

DESIGN BATANG TARIK

&2,2)2.*1


BATANG DIAGONAL (B5)

P$ 7

2,+1.')

8ta4i 7

+.

894at$4

+.)

:! 7

'1+

MPa

:$ 7

))+

MPa

2+

M;

D/a$t 7 P43i;ina4! D3:!>Ag Ag7P$?89! Ag 7

)'2.()'2

;;2

)'.2()'2

@;2

Dari tab! ba"a #i$i!i% $r'! ba"a bb

IW:

*++

>

*++

>

(

Ag 7

11.-

@;2

47

1-

;;

/9 7

*++

;;

7

*++

;;

7

1)

;;

I> 7

2+'++

@;'

t 7

1+

;;

I! 7

()+

@;'

i! 7

.)1

@;

*+ Kat L!% Tari+

S!a4at  P$=8Pn

2,+1.')

8Pn 7

*.-

*+ Kat -ra+tr

S!a4at

P$=8Pn

8Pn7 +.)>:$>A3 An7

Ag & '0$a< $/ang

An 7 A3 7 A3 7 8Pn 7

1+2+

;;2

('-

;;2

An F U *-++ *.-

DESIGN BATANG TEKAN

KN

=

*-+

6K


BATANG DIAG6NAL 0B1 P$ 7

&2,2)2.*1

8t3an 7

+.-)

K7

1

L7

)

E7

2+++++

; M%a

Dari tab! ba"a #i$i!i% $r'! ba"a bb

IW:

*++

>

*++

>

(

Ag 7

11.-

@;2

47

1-

;;

/9 7

*++

;;

7

*++

;;

7

1)

;;

I> 7

2+'++

@;'

t 7

1+

;;

I! 7

()+

@;'

i! 7

.)1

@;

+ +!a/0i/0a/ $/a1$a/0

((.)-(1'

o<

<1'+

+ $/a1$a/0 λ

1)

λ %

1).-11*--*

OK

λ

*+

λ %

'2.+)-22

OK

@3 $at t3an no;ina λ @

+.(++1*)21 t34n!ata $4ang #a4i 1.)

Maa  ω=

1.'(((+''*'

:@4 7

2.))*1()

M%a

ΦPn 7

2-'(*2.1)'

N


S!a4at 

Pu<ΦPn

22)2.*12-'(.*

+

#i0/ a1b/0a/ $a#a a1b/0a/ D

2'+.1+ 2,+1.')

53350 pa9a batang 5

1,*(1.-


&! =

2,+1.')

n

9$ 7 -2) MPa

8 l!bang = 21

D/a$t 7

2+

;;

A/a$t 7

*1'

;;2

5; /a$t 7

1(

/$a /a$t

t%at 7

2+

;;

7

1)

;;

7

*++

;;

Φ 94at$4 7

833 7

+.) +.

An 7

1+'+

;;2

A3 7

(((

;;2

+ !!% ΦPn =

P$ =

''2+(2+

n

''2+(2+

n

222)

n

222)

n

8 Pn 2+1,').++

6K

+ -ra+tr ΦPn =

P$ =

8 Pn 2+1,').++

6K

++ata/ bat + +at 0r

# 7

*1+-.(

n



2,+1.')

n

)+'

n



2,+1.')

n

41 7 +.) + +at t1$ R# 2

*+ b!+ %ar

<17

'+

;;

<7

*+

;;

<27

(+

;;

Agt7

1-++

;;2

Ant7

11+

;;2

Ag<7

1*2++

;;2


An<7

-+

;;2

:$ Ant7

()2)+

n

+.(9$Ant7

)1)+

n

*-1-.)-)

n

8Pn 7

a1b/0a/ A

2,2)2.*1

1,-+*.(+

%a#a /atang 1 P$ 7

22)2.*1

+ +at $!at + !!%

8Pn 7 P$  8Pn

''2+.(2

n

22.2)

n

6K

+ -ra+tr

8Pn 7 P$  8Pn

5; /a$t

6K

1(

Ba$t

+ +at bat + +at 0r

# 7

*1+-.(

n


41 7 +.)

@3 $at t$;%$ R# 7

)+'

n

@3 /o@ <3a4 <17

'+

;;

<7

*+

;;

<27

(+

;;

Agt7

1-++

;;2

Ant7

11+

;;2

Ag<7

1*2++

;;2

An<7

-+

;;2

:$ Ant7

()2)+

n

+.(9$Ant7

)1)+

n

*-1-.)--

n

8Pn 7

Sa1b/0a/ H

)+-.1 22)2.*1 -(1.1'

$a#a bata/0 3

P$ 7

22)2.*1

+ +at $!at + !!%

8Pn 7

''2+.(2

n

2+1.')


P$  8Pn

+ -ra+tr

8Pn 7 P$  8Pn

5; /a$t

22.2)

n

6K

Ba$t

34

+ +at bat + +at 0r

# 7

*1+-.(

n

)+'

n

41 7 +.)

+ +at t1$

R#7

+ b!+ %ar

<17

'+

;;

<7

*+

;;

<27

(+

;;

Agt7

1-++

;;2

Ant7

11+

;;2

Ag<7

1*2++

;;2

An<7

-+

;;2

:$ Ant7

()2)+

n

+.(9$Ant7

)1)+

n

*-1-.)-)

n

8Pn 7


FFK 3t34angan  Saat #ig$naan 5$;a /a$t ' /$a /a$t, ;aa #i#a%at a
KESIMPULAN

Da4i %343n@anaan 53;/atan 4anga !ang t3a #i/$at, #a%at #i
b (lebar jembatan)

=7m

a (lebar trotoar)

= 0,5 m

b-2a (lebar jalan)

=6m

h (tinggi jembatan)

=3 m

λ(panjang segmen)

=4m

L (panjang bentang) = 24 m Tebal trotoar

=0,2m

!t! baja

= "# 37

%$= 240 &a

$!

= 370 &a

'

= 200000 &a

"# spal = 22 *+m3 "# "eton =24 *+m3 Tebal aspal =0,05 m Tebal pererasan = 0,2 m


T34n!ata 53;/atan 4anga ;a;%$ ;3naan /3/an&/3/an !ang n3345a. J$ga %a#a

51150059-PERENCANAAN-JEMBATAN-RANGKA-REVISI-ANNISA-ANDI-NUR-BAITI-2SIPIL1PAGI.doc

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