dv dx d d Þ vII = = 4×t Þ a IIt = II = 4 cm/s 2 = konst. dt dt dt dt ------------------------------------------------------------------------------------------------------------x = 4 + 2×t2
Za t = 2 s :
vII = 8 cm/s
a1 =
a IIt r2
a IIIn =
vIII r3
Þ
Þ
w1 =
v II r2
Þ
a It = a 1 × r1 = a IIt
vI = w1 × r1 = vIII
v
w k
Brzina točke E: v
v
v
w = -w × sin a × j + w × cos a × k sin a =
10 10 2 + 12 2
cos a =
,
12 10 2 + 12 2
v v v rE = r × i - k × j --------------------------------------------------------------------------v i
v j
v k
r
-k
0
v v v v v v vE = w ´ rE = 0 - w × sin a w × cos a = v x × i + v y × j + v z × k
vE = v x2 + v 2y + v z2
Ubrzanje točke E:
v i v v v v v a E = a ´ rE + w ´ vE = 0 vx 0 a E = a x2 + a y2 + a z2
v v j k v v v - w × sin a w × cos a = a x × i + a y × j + a z × k vy vz
v rE
an
a = at2 + a n2 = 2
Þ
4 = at2 + an2
at = a × r
v2 r ------------------------------------------------------------------------an =