Room 206 JPD Buildin 1!"" #M R$%&o '($nu$) M*nil* +$l$,on$ +$l$,on$ Num.$/ 02 "16 3""! E-M*il m$*/$(i$45200 78*oo9%om
REFRESHER MODULE 1 - SURVEYING PROBLEM 1 A 0.65kg, 50m tape was standardized standardized and supported trougout its wo!e !engt and "ound to #e 0.00$05m !onger at an o#ser%ed temperature o" &1.'() and a pu!! o" 10*+. is tape was used to measure a - grade !ine wi/ was "ound "ound to #e 66$.0$m. 66$.0$m. uring measurement, measurement, te temperature temperature is 15() and te tape is suspended under a pu!! o" $0*+. E2$003Pa, /ross4 se/tiona! area o" tape is &mm $ and te /oe""i/ient o" !inear epansion is 0.0000116m(). 1. )ompute te standard temperature. a. $'.$() #. &0.$-() /. $6.$() d. &$.$-() $. )ompute te tota! /orre/tion per tape !engt. a. 40.$&' #. 70.$&' /. 40.$1' d. 70.$1' &. )ompute te t rue orizonta! distan/e. a. 658.-6m #. 658.$m /. 658.$0m
d. 658.&5m
PROBLEM $ A !ine measures '00m at e!e%ation 800m. e a%erage radius o" te /ur%ature in te area is 6-00km. 1. )ompute te sea !e%e! distan/e. a. 6'.80m #. '.80m /. ''.80m d. 8'.80m $. )ompute te redu/tion "a/tor. a. 0.88''6 #. 0.888'6 /. 0.886'6 d. 0.88'6 PROBLEM & A !ine 1$5 m. !ong was pa/ed #9 a sur%e9or "or "our times wit te "o!!owing data 161,165, 158 and 15'. en anoter !ine was pa/ed "or "i%e times wit te "o!!owing resu!ts, 5$0, 5$5, 5$-, 5$$ and 51'. 1. etermine te pa/e "a/tor. a. 0.56 #. 0.6 /. 0.86 d. 0.'06 $. etermine te num#er num#er o" pa/es "or te new !ine. a. 5$1.' #. 518.' /. 5$&.' d. 5$-.' &. etermine te distan/e o" te new !ine. a. -05.5m #. -0$.5m /. -0.5m d. -0'.5m PROBLEM :rom te measured measured %a!ues %a!ues o" distan/e AB, te "o!!owing "o!!owing data were re/orded. AA ;<A+)E +o. O: MEA<=REME+< 1 1$0.6' 1 $ 1$0.'& 1$0.6 6 1$0.6' 1. :ind te pro#a#!e weigt o" data $. a. #. 6 $. :ind te pro#a#!e error o" te mean. a. 70.0106 #. 70.01$6 &. :ind te standard de%iation. a. 70.0'56 #. 70.0'&6 -. :ind te standard error. a. 70.01' #. 70.016 5. :ind te pro#a#!e distan/e o" AB. a. 1$0.$ #. 1$0.8$
/. '
d. 1
/. 70.01-6
d. 70.0166
/. 70.0'16
d. 70.086
/. 70.01-
d. 70.01&
/. 1$0.5$
d. 1$0.&$
PROBLEM 5 e "o!!owing interior ang!es o" a triang!e tra%erse were measured wit te same pre/ision. A+3LE >AL=E ?E3REE<@ +o. O: MEA<=REME+< A &8 5 B 65 ) 5 & 1. etermine te most most pro#a#!e %a!ue o" ang!e ang!e A. a. &8( 15.&$ #. &8( 18.15 /. &8( $5.5& $. etermine te most most pro#a#!e %a!ue o" ang!e ang!e B. a. 65( 1&.&5 #. 65( 15.&$ /. 65( 18.15 &. etermine te most pro#a#!e %a!ue o" ang!e ). a. 5( 18.15 #. 5( 1&.&5 /. 5( $5.5&
d. &8( 1&.&5 d. 65( $5.5& d. 5( 18.15
PROBLEM 6 :rom te gi%en data o" a di""erent !e%e!ing as sown in t e ta#u!ation <A. 1 $ & 5 6
B.<. 5.' .0& &.-' .$5 10.18 8.$8
:.<.
ELE>. &8$.$5
6.$8 6.$5 .0' 5.5 -.-5 -.8-
1. :ind te di"". in e!e%ation o" station and station 5. a. 10.08m #. '.08m /. 1$.08m $. :ind te eigt eigt o" instrument instrument at station -. a. -00.$6m #. &86.$6m /. &8$.$6m
d. 1-.08m d. &'6.$6m
PROBLEM e ta#!e sows sows te %a!ues o" #a/ksig #a/ksigt, t, "oresig "oresigtt C intermed intermediate iate "oresigt reading taken "rom BM1 to BM$. E!e%ation o" BM1 2 &$'.0m. <A. BM1 1 $ & P1 5 6 P$ ' 8 10 11 BM$
B.<. $.&$
:.<.
;.:.<.
ELE>A;O+ &$'.0
1. $.$ 1.$ 0.8 $.
&.-& $.$ &. 1.6
$.$$
&.06 $.' &.6 $.0 1.1 $.-5
1. :ind te di""eren/e in e!e%ation #etween stations 5 C 8. a. $.6-m #. $.--m /. $.$-m $. :ind te e!e%ation o" P$. a. &$5.&0m #. &$.&0m /. &$8.&0m
d. $.-m d. &$&.&0m
PROBLEM ' ;n a two peg D test test o" a dump9 !e%e!, !e%e!, te "o!!owing "o!!owing o#ser%ations o#ser%ations were taken.
Rod reading on A Rod reading on B
;nstrument at at ) 0.$86 0.810
;nstrument at at 1.56& $.1-0
Point ) is euidistant "rom A and B. is $.5m "rom A and $.5m "rom B. 1. Fat is te di""eren/e in e!e%ation #etween A and BG a. 0.61#. 0.6$/. 0.6&d. 0.6-$. etermine te error in te rod reading reading at B wit te instrument at . a. 0.0&8& #. 0.0&'& /. 0.0&& d. 0.0&6& &. Fat is te /orresponding rod reading on A "or a orizonta! !ine o" sigt wit instrument instrument sti!! at . a. 1.5#. 1.56/. 1.55d. 1.5-PROBLEM 8 )onsidering te e""e/ts o" /ur%ature and re"ra/tion, te di""eren/e in e!e%ation o" points B C ) is "ound out to #e 111.&56m. :rom point A, te ang!e o" e!e%ation o" B is 1' ⁰&0 C tat o" ) is ' ⁰15. A is #etween B C ). 1. ;" ) is $000m "rom A, ow "ar is B "rom )G a. 1.6km #. 1.-km /. 1.$km d. 1.0km $. :ind te e!e%ation e!e%ation o" A i" e!e%ation o" B is -50m. a. -'.8m #. -'.58m /. -'.18m d. -'.&8m
Room 206 JPD Buildin 1!"" #M R$%&o '($nu$) M*nil* +$l$,on$ Num.$/ 02 "16 3""! E-M*il m$*/$(i$45200 78*oo9%om
REFRESHER MODULE 1 - SURVEYING PROBLEM 10 wo i!!s A C ) a%e e!e%ations o" 600m C '00m respe/ti%e!9. ;n #etween A C ), is i!! B wi/ as an e!e%ation o" 05m. B is !o/ated 1$km "rom A C 10km "rom ). etermine te /!earan/e or o#stru/tion o" te !ine o" sigt i" an o#ser%er is H A so tat ) wi!! #e %isi#!e "rom A. Ans. &.85m a. &.85m ?o#stru/tion@ #. &.85m ?/!earan/e@ /. &.5m ?o#stru/tion@ d. &.5m ?/!earan/e@ PROBLEM 11 A "ie!d is in te "orm o" a regu!ar pentagon. e dire/tions o" te #ounding sides were sur%e9ed wit an assumed meridian 5 ⁰ to te rigt o" te true nort C sout meridian. As sur%e9ed, te #earing o" one side AB is + &&⁰$0 F. 1. )ompute te true #earing o" Line ). a. <65⁰$0E #. <66⁰$0E /. <6-⁰$0E d. <6&⁰$0E $. )ompute te true azimut o" Line B). a. $$0⁰-0 #. $$1⁰-0 /. $$$⁰-0 d. $$&⁰-0 PROBLEM 1$ e #earing o" a !ine "rom A to B was measured as <16(&0F. ;t was "ound tat tere was a !o/a! attra/tion at #ot A C B and tere"ore a "orward and a #a/kward #earing were taken #etween A C a point ) at wi/ tere was no !o/a! attra/tion. ;" te #earing o" A) was <&0(10E C tat o" )A was +$'($0F, wat is te /orre/ted #earing o" ABG a. <1'($0F #. <16($0F /. <1($0F d. <18($0F PROBLEM 1& :rom te gi%en /!osed tra%ersed sown. L;+E< BEAR;+3 ;<A+)E< A4B --.& m. <. &5 &0 F B4) 1&.'- m. +. 5 15 F )4 1$.'& m. +. 1 -5 E 4E G 6-.'6 m. E4A G 106.$ 1. :ind te Bearing o" !ine 4E. a. + 66.1(E #. + 6'.1(E /. + 0.1(E d. + $.1(E $. :ind te Bearing o" !ine E4A. a. <5-.$(E #. <5$.$(E /. <50.$(E d. <-'.$(E PROBLEM 1:rom te data #e!ow L;+E AB B) ) E EA
LA;=E 4&6.1& 7-.56 71$.'$ 718.80 46'.-0
1.
EPAR=RE 4$5. 4115.8& 70.&8 761.768.5
/. 6$6.$8m$
d. 65&.6$m $
/. 6$6.$8m$
d. 65&.6$m $
